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A ice block floating in a river is pushed through a displacement d→=(15m)i^-(12m)j^along a straight embankment by rushing water, which exerts a force data-custom-editor="chemistry" F→=(210N)i^-(150N)j^ on the block. How much work does the force do on the block during the displacement?

Short Answer

Expert verified

The work done on the block during the displacement is 5.0×103J.

Step by step solution

01

Given data

  1. Displacement, d→=15mi^-12mj^.
  2. Force, F→=210Ni^-150Nj^.
02

Understanding the concept

Using the formula ofthework done due to force over a distance, we can find the work done on the block during the displacement.

Formula:

W=F→.d→

03

Calculate the work done by the force on the block during the displacement

Work done can be calculated as,

W=F→.d→

Substitute the values in the above expression, and we get,

W=210Ni^-150Nj^.15mi^-12mj^W=3150+1800N.mW=4950N.mW=5.0×103J

Therefore, the work done on the block during the displacement is 5.0×103J.

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Most popular questions from this chapter

(a) at a certain instant, a particle-like object is acted on by a force F→=(4.0 N)i^-(2.0 N)j^+(9.0 N)k^ while the object’s velocity is v→=-(2.0 m/s)i^+(4.0 m/s)k^. What is the instantaneous rate at which the force does work on the object?

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