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Two coils are at fixed locations. When coil 1 has no current and the current in coil 2 increases at the rate 15.0 A/s, the emf in coil 1 is 25.0 mV. (a) What is their mutual inductance? (b) When coil 2 has no current and coil 1 has a current of 3.60A, what is the flux linkage in coil 2?

Short Answer

Expert verified

a)M=1.67×10-3H

b)ϕ21=6.0×10-3Wb

Step by step solution

01

Given

Rate of change of current,

di2dt=15.0A/sε1=25.0mV=25.0×10-3VI1=3.6A

02

Understanding the concept

We have the formula for the mutual inductance induced in the coil, we also have enough information given, so we can calculate the mutual inductance. We also have enough information along with the formula for flux linkage, so we can find the required answer.

Formula:

Ï•=MIN

M=εdi/dt

03

(a) Calculate the mutual inductance

We have,

M=εdidt

So, mutual inductance in coil 1 will become,

M=εdidtM=25.0×10-315M=1.67+10-3H

04

(b) Calculate the flux linkage in coil 2 when coil 2 has no current and coil 1 has a current of 3.60 A

We have,

Ï•=MIN

Here, N=1

ϕ21=MI1Nϕ21=1.67×10-3×3.61ϕ21=6.0×10-3Wb

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