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Question: An electric generator contains a coil of 100 turnsof wire, each forming a rectangular loop 50.0cm to 30.0cm. The coil is placed entirely in a uniform magnetic field with magnitude B = 3.50 Tand withB鈬赌initially perpendicular to the coil鈥檚 plane. What is the maximum value of the emf produced when the coil is spun at 1000 rev/min about an axis perpendicular toB鈬赌?

Short Answer

Expert verified

The maximum value of emf is,=5.5kV.

Step by step solution

01

Step 1: Given

  1. Turns of wire N = 100
  2. Rectangular loop dimension 50.0 cm by 30.0 cm
  3. Magnetic field B = 3.50 T
  4. Coil rotation 1000 rev/min
02

Determining the concept

From Faraday鈥檚 law, evaluate the induced emf from the number of turns and the change in the magnetic field lines that pass through the loop. Find the magnetic field lines with the given magnetic field and the area of the rectangular loop.

Faraday's law of electromagnetic inductionstates, Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced in it.

Formulae are as follows:

=B.dA=-Nddt

Where, is magnetic flux, B is magnetic field, A is area, 饾渶 is emf, Nis number of turns.

03

Determining the maximum value of emf

The coil rotation is,

1000rev/min=1000rev1min1min60s2rad1rev=104.7rad/sec=104.7rad/sec

The magnetic field lines with the given magnetic field and the area of the rectangular loop is given as,

=B.dA=BdAcos

But=trad

=BdAcost=BdAcost

By differentiating the magnetic field lines with respect to time,

ddt=ddtBAcostddt=-BAcost

From Faraday鈥檚 law, induced emf,

=-Nddt=-N-BAsint=NBAsin=100104.73.50.50.3sint

The induced emf will be maximum, when sint=1.

=100104.7rad/s3.5T0.5m0.3m1=5.4961035.5kV

Hence, the maximum value of emf is, =5.5kV.

Therefore, the induced emf in an electric generator can be determined using Faraday鈥檚 law when a coil of wire is wounded with the given number of turns.

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