/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q94P An object is placed against the ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 34: Q94P (page 1042)

An object is placed against the center of a spherical mirror and then moved 70 cm from it along the central axis as the image distance i is measured. Figure 34-48 gives i versus object distance p out to ps=40cm. What is the image distance when the object is 70 cm from the mirror?

Short Answer

Expert verified

The image distance is inew=-21cm.

Step by step solution

01

Step 1: Given data

  • Object distance,pgiven=70cm .
  • Horizontal Scale, ps=40cm.
02

Determining the concept

The focal length of the lens is constant for every situation. Using this concept, find the focal length from the graph. Using the value in the equation and the given object distance, find the new image distance.

Formulae are as follows:

1f=1p+1i

Here, p is the pole, f is the focal length, and i is the image distance.

03

Determining the image distance

From the graph, take one point Q having co-ordinate Q15,-10.

So,

1p+1i=1f

115+1-10=1f=1pgiven+1inew

Rearrange for the inew;

1inew=-10+15-10脳15-170=-5150-170

Solve for inew;

1inew=-1002100=-21cm

Therefore, the image distance isinew=-21cm .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If the angular magnification of an astronomical telescope is 36 and the diameter of the objective is 75 mm, what is the minimum diameter of the eyepiece required to collect all the light entering the objective from a distant point source on the telescope axis?

Prove that if a plane mirror is rotated through an angle a, the reflected beam is rotated through an angle 2伪. Show that this result is reasonable for 伪=45鈭�.

Figure 34-33 shows an overhead view of a corridor with a plane mirror Mmounted at one end. A burglar Bsneaks along the corridor directly toward the center of the mirror. Ifd=3m, how far from the mirror will she from the mirror when the security guardScan first see her in the mirror?

In Fig. 34-26, stick figure O stands in front of a thin, symmetric lens that is mounted within the boxed region; the central axis through the lens is shown. The four stick figuresI1andI4suggest general locations and orientations for the images that might be produced by the lens. (The figures are only sketched in; neither their height nor their distance from the lens is drawn to scale.) (a) Which of the stick figures could not possibly represent images? Of the possible images, (b) which would be due to a converging lens, (c) which would be due to a diverging lens, (d) which would be virtual, and (e) which would involve negative magnification?

Figure 34-40 gives the lateral magnification of an object versus the object distancefrom a lens asthe object is moved along the central axis of the lens through a range of values for p out to ps=20.0cm. What is the magnification of the objectwhen the object is 35cmfrom the lens?
See all solutions

Recommended explanations on Physics Textbooks

Linear Momentum

Read Explanation

Nuclear Physics

Read Explanation

Classical Mechanics

Read Explanation

Solid State Physics

Read Explanation

Geometrical and Physical Optics

Read Explanation

Translational Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.