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Chapter 34: Q10Q (page 1037)

In Fig. 34-26, stick figure O stands in front of a thin, symmetric lens that is mounted within the boxed region; the central axis through the lens is shown. The four stick figuresI1andI4suggest general locations and orientations for the images that might be produced by the lens. (The figures are only sketched in; neither their height nor their distance from the lens is drawn to scale.) (a) Which of the stick figures could not possibly represent images? Of the possible images, (b) which would be due to a converging lens, (c) which would be due to a diverging lens, (d) which would be virtual, and (e) which would involve negative magnification?

Short Answer

Expert verified

(a) The sick figures that could not possibly represent images areI2andI3.

(b) The sick figures that represent a converging lens areI1andI4.

(c) The sick figure that represents a diverging lens isI1.

(d) The sick figure that represents a virtual magnification isI1.

(e)The sick figure that represents a negative magnification is I4.

Step by step solution

01

Definition of a converging lens and diverging lens

The lens that allows the rays of light to focus on one point is termed a converging lens and the lens that allows the rays of light from one point to scatter at different points is termed a diverging lens.

02

(a) Determination of the sick figures that could not possibly represent images

The lens forms an image on the left of the lens as upright and on the right of the lens as inverted.

Thus, the sick figures that could not possibly represent images are I2andI3.

03

(b) Determination of the sick figures that represent a converging lens

The converging lens forms an image on the left of the lens as upright and on the right of the lens as inverted.

Thus, the sick figures that represent a converging lens are I1andI4.

04

(c) Determination of the sick figures that represent a diverging lens

The image due to a diverging lens is always virtual and is located between the object and the lens.

Thus, the sick figure that represents a diverging lens is I1.

05

(d) Determination of the sick figure that represents a virtual magnification

From the figure, it can be observed that I1is a virtual image due to the lens.

Thus, the sick figure that represents a virtual magnification is I1.

06

(e) Determination of the sick figure that represents a negative magnification

It is known that when the image is inverted, there would be a negative magnification.

Thus, the sick figure that represents a negative magnification is I4.

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Most popular questions from this chapter

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