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Someone with a near point Pn of 25 cm views a thimble through a simple magnifying lens of the focal length 10 cm by placing the lens near his eye. What is the angular magnification of the thimble if it is positioned so that its image appears at (a) Pn and (b) infinity?

Short Answer

Expert verified
  1. The angular magnification of the image that appears at Pn is 3.5.
  2. The angular magnification of the image that appears at infinity is 2.5.

Step by step solution

01

Step 1: Given data

f=10cmPn=25cm

02

Determining the concept

According to the given condition, the image appears at Pn;fromthat, find the object distance and, using the formula of the angular magnification, calculate the magnification when the image appears atPn. Similarly, calculate the magnification when the image appears at ∞.

The formulas are as follows:

1f=(1p+1i)m=θ'θ

Where p is the pole, f is the focal length, and i is the image distance.

03

Determining the angular magnification of the image that appears at Pn.

(a)

Without the magnifier, we can write the angle from figure 34-19,

θ=h/Pn

Where h is the original height of the object.

With magnifier,

i=-i=-Pn

So, now, according to the formula,

1f=1P+1i1P=1f+1PnP=fPnf+Pn

So, now the angular magnification is,

mθ=θ'θmθ=h/Ph/Pnmθ=PnP

By substituting the value,

mθ=Pnf+PnfPnmθ=f+Pnfmθ=1+Pnfmθ=1+2510

mθ=3.5

Therefore, the angular magnification of the image that appears at Pn is 3.5.

04

 Determining the angular magnification of the image that appears at infinity.

(b)

Now, consider the image appears at infinity so that,

i=-i=∞1f=1P+1i1P=1fP=f

So, the magnification is,

mθ=h/Ph/Pnmθ=PnPmθ=Pnfmθ=2510

mθ=2.5

Therefore, the angular magnification of the image that appears at infinity is 2.5.

Using the corresponding formula, find the angular magnification of the image by a simple magnifying lens for different object distances.

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