/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q1Q Figure 34-25 shows a fish and a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Figure 34-25 shows a fish and a fish stalker in water. (a) Does the stalker see the fish in the general region of point a or point b? (b) Does the fish see the (wild) eyes of the stalker in the general region of point c or point d?

Short Answer

Expert verified

(a) The stalker spots the fish in or near point a.

(b) Around point c, the fish can roughly make out the stalker's eyes.

Step by step solution

01

The given data

Fig. 34-25 showing a fish and a fish stalker in water is given.

02

Understanding the concept of refraction

For a material with a higher refractive index, the light bends towards the normal line; while for a material with a low refractive index, it speeds up and bends away from the normal line. Analyzing the given figure and using the concept of refraction we can find the region in which the stalker sees the fish and the fish sees the eyes of the stalker.

03

(a) Calculation of the view through the eyes of a stalker

The ray diagram:

Light refracts away from the normal when it moves from a rarer to a denser medium, and towards the normal when it moves from a rarer to a denser media.

The ray of light is travelling from water to air, or from the denser medium to the rarer medium, according to the ray diagram above. As a result, the light should refract differently than usual. Therefore,

This is only conceivable in region a, as shown in the image.

Therefore, the stalker spots the fish in or near point a.

04

(b) Calculation of the view through the eyes of a fish

The ray diagram:

The beam of light is moving from air to water, or from the rarer medium to the denser medium, according to the ray diagram above. In order to return to normal, the light should do so. Thus,

This is only conceivable in region c, as shown in the image.

Therefore, the around point c, the fish can roughly make out the stalker's eyes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

17 through 29 22 23, 29 More mirrors. Object O stands on the central axis of a spherical or plane mirror. For this situation, each problem in Table 34-4 refers to (a) the type of mirror, (b) the focal distancef, (c) the radius of curvaturer, (d) the object distancep, (e) the image distancei, and (f) the lateral magnification localid="1663002056640" m. (All distances are in centimeters.) It also refers to whether (g) the image is real (R)or virtual (V), (h) inverted (I)or noninverted (NI)from O, and (i) on the same side of the mirror as the object O or on the opposite side. Fill in the missing information. Where only a sign is missing, answer with the sign.

Two thin lenses of focal lengths f1andf2 are in contact and share the same central axis. Show that, in image formation, they are equivalent to a single thin lens for which the focal length is f=f1f2(f1+f2).

Figure 34-33 shows an overhead view of a corridor with a plane mirror Mmounted at one end. A burglar Bsneaks along the corridor directly toward the center of the mirror. Ifd=3m, how far from the mirror will she from the mirror when the security guardScan first see her in the mirror?

An object is placed against the center of a spherical mirror and then moved 70 cm from it along the central axis as the image distance i is measured. Figure 34-48 gives i versus object distance p out to ps=40cm. What is the image distance when the object is 70 cm from the mirror?

The formula 1p+1i=1f is called the Gaussian form of the thin-lens formula. Another form of this formula, the Newtonian form, is obtained by considering the distance xfrom the object to the first focal point and the distancex' from the second focal point to the image. Show thatxx'=f2 is the Newtonian form of the thin-lens formula

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.