91影视

Newton鈥檚 second law states that the net force on the body is equal to the product of mass of the body and the acceleration with which body is moving.

Apply Newton鈥檚 second law to find force on each bolt, when the plane is at rest and when it is in motion.

Formulae:

1. W=mg
2. F=ma

Here,W is weight of the object,m I s mass of the object,g is gravitational acceleration,F is force anda is acceleration of the object.

Apply Newton鈥檚 second law, net force on plane is,

$F_{net}=3F-mg$

Here 3F is the force on three bolts.

For rest, $F_{net}=0$

$$\begin{gathered} 0=3F-1400\mathrm{kg}脳9.8\mathrm{m}/{\mathrm{s}}^2 \\ F=\frac{1400\mathrm{kg}脳9.8\mathrm{m}/{\mathrm{s}}^2}{3} \\ =4.6脳{10}^3\mathrm{N} \end{gathered}$$

Therefore, the force on each bolt is $4.6脳{10}^3\mathrm{N}$.

When the plane is in the motion, it will have some acceleration. Using the equation of motion, we can write,

$$\begin{gathered} ma=3F-mg \\ F=\frac{m\left(a+g\right)}{3} \\ =\frac{1400\mathrm{kg}\left(2.6/{\mathrm{s}}^2+9.8\mathrm{m}/{\mathrm{s}}^2\right)}{3} \\ =5.8脳{10}^3\mathrm{N} \end{gathered}$$

Therefore, the force on each bolt is $5.8脳{10}^3\mathrm{N}$.