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Models of torpedoes are sometimes tested in a horizontal pipe of flowing water, much as a wind tunnel is used to test model airplanes. Consider a circular pipe of internal diameter 25.0cmand a torpedo model aligned along the long axis of the pipe. The model has a 5.00cmdiameter and is to be tested with water flowing past it at 2.50m/s.

(a) With what speed must the water flow in the part of the pipe that is unconstricted by the model?

(b) What will the pressure difference be between the constricted and unconstricted parts of the pipe?

Short Answer

Expert verified


Hence, the pressure difference between the constricted and unconstricted parts of the pipe is

Step by step solution

01

Given data

  1. The internal diameter of the pipe,.

  2. The diameter of the torpedoes model,.

  3. The speed of the water at a constricted section of pipe,.

  4. The pipe is horizontal.

02

Determining the concept

Determine the speed of the water at the unconstricted section of the pipe using the equation of continuity. Then, using Bernoulli鈥檚 equation, find the pressure difference between the constricted and unconstricted parts of the pipe. According to Bernoulli鈥檚 equation, as the speed of a moving fluid increases, the pressure within the fluid decreases.

Formulae are as follows:

Where,pis pressure,vis velocity,his height,gis an acceleration due to gravity,his height,Ais the area, andis density.

03

(a) Determining the speed of the water at the unconstricted section of the pipe


The effective diameter of the constricted section of the pipe is,

The water flowing through the pipe obeys the equation of continuity.

Hence,

Hence, the speed of the water at the unconstricted section of the pipe is

04

 (b) Determining the pressure difference between the constricted and unconstricted parts of the pipe

The water flow obeys Bernoulli鈥檚 principle.

So,

Given that the pipe is horizontal, i.e.,hc=hu, and蟻= density of water = 1000 kg/m3,

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