91Ó°ÊÓ

1. Density of blood,$p=1.06×{10}^{3}kg/m^3$
2. Heart pressure,$p=250torr$

Use the formula for gauge pressure, which depends on density, height, and acceleration due to gravity. Gauge pressure is that, which is exerted by a fluid at any point of time at equilibrium due to the force applied by gravity.

Formula:

Pressure applied on a fluid surface,$p=pgh$

Net pressure applied on a body, $∆p=p_2-p_1$

From equation (ii), the pressure at brain can be given as:

$$\begin{gathered} p_{brain}=p_{heart}-pgh \\ =250-1.06×{10}^3×9.8×2×\frac{1torr}{133.33Pa}(âˆ\mu 1torr=133.33Pa) \\ =94.2torr \end{gathered}$$

The pressure at brain is 94.2 torr.

From equation (ii), the pressure at brain can be given as:

$$\begin{gathered} P_{feet}=P_{heart}+pgh(âˆ\mu \mathrm{here}\mathrm{pressure}\mathrm{is}\mathrm{total}\mathrm{pressure}) \\ =250+1.06×{10}^3×9.8×2×\frac{1torr}{133.33Pa}(âˆ\mu 1torr=133.33Pa) \\ =405.8torr \end{gathered}$$

The pressure at feet is 405.8 torr.

From equation (ii), the net pressure between brain and feet can be given as:

$$\begin{gathered} ∆p=p_{brain}-p_{feet} \\ =405.8-94.2 \\ =311.6torr \end{gathered}$$

Hence, the increased value of pressure is 311.6 torr.