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Four bricks of length L, identical and uniform, are stacked on top of oneanother (Fig. 12-71) in such a way that part of each extends beyond the one beneath. Find, in terms of L, the maximum values of (a) a1 , (b) a2, (c) a3 , (d)a4 , and (e) h, such that the stack is in equilibrium, on the verge of falling.

Short Answer

Expert verified

Maximum values of

(a) a1=L2(b) a2=L4(c) a3=L6(d) a4=L8(e) h=25L24

Step by step solution

01

Understanding the given information

The length of the bricks is L.

02

Concept and formula used in the given question

For the given equilibrium,you can find the distance of bricks in terms of L. The formulas used are given below.

Ï„=0Netforce=0

03

(a) Calculation for the a1

You know the condition of equilibrium in which the moment of force, and torque is zero.

The Center of mass of the top brick cannot be extended further to the rightL/2; otherwise, it will fall. So maximum value ofa1is

a1=L2

04

(b) Calculation for the a2

N2=2mg

Moment of force

∑τ=0−a2(N2)+L2(mg)=0a2=L4

05

(c) Calculation for the  a3

N3=3mg

Moment of force

∑τ=0−a3(N3)+L2(mg)=0a3=L6

06

(d) Calculation for the  a4

N4=4mg

Moment of force

∑τ=0−a4(N4)+L2(mg)=0a4=L8

07

(e) Calculation for the  h

h=a1+a2+a3+a4=L2+L4+L6+L8=25L24

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