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In Fig. 33-77, an albatross glides at aconstant 15m/shorizontallyabove level ground, moving in a vertical plane that contains the Sun. It glides toward a wallof heighth=2.0m, which it will just barely clear. At that time of day, the angle of the Sun relative to the groundis=30.At what speed does the shadow of the albatross move (a) across the level ground and then (b) up the wall? Suppose that later a hawk happens to glide along the same path, alsoat15m/s.You see that when its shadow reaches the wall, the speed of the shadow noticeably increases. (c) Is the Sun now higher or lower in the sky than when the albatross flew by earlier? (d) If the speed of the hawk鈥檚 shadow on the wallis45m/s,what is the angle u of the Sun just then?

Short Answer

Expert verified

a) The speed at which the shadow of the albatross moves across the level ground is15m/s.

b) The speed at which the shadow of the albatross moves up the wall is8.7m/s .

c) The sun is higher in the sky when the hawk glides by.

d) The angle of the Sun if the speed of the hawk鈥檚 shadow on the wall is 45 m/s is=72

Step by step solution

01

Listing the given quantities

Speed of albatross is15m/s

h=2.0m

=30

Speed of hawk is15m/s

Speed of hawk鈥檚 shadow on the wall is45m/s

02

Understanding the concepts of velocity

As the sun is far away, we consider that the rays coming from the sun are parallel, i.e., the angle between the sunray and the bird鈥檚 position is the same everywhere.

Formula:

迟补苍鈥=y/x

v=dxdt

03

(a) Calculations of the speed at which the shadow of the albatross moves across the level ground

The rays coming from the sun are parallel. So, the angle formed by the sunrays with the bird at one position is the same as the one formed with the bird at another position.

Therefore, the shadow of the bird moves on the ground with the same speed as that of the bird.

Thus, the shadow of the albatross moves across the level ground with speed15m/s

04

(b) Calculations of the speed at which the shadow of the albatross moves up the wall 

Now the bird is in the positionx>0from the wall. So, its shadow on the wall is at a distance0yhfrom the top of the wall.

From the figure,

迟补苍鈥=yxy=xtan

Thus,

dydt=dxdt迟补苍鈥(1)dydt=(15)迟补苍鈥30=(15)0.577=-8.7m/s

This means that the distanceyi.e., the positive number downward from the top of the wall is shrinking at the rate of 8.7 m/s.

Thus, the speed at which the shadow of the albatross moves up the wall is.8.7m/s

05

(c) Explain the reasoning

迟补苍鈥is directly proportional to the value of the in the range.0<<90

From equation (1), it is clear that the value of dydtis maximum when迟补苍鈥 is maximum. Thus, the larger value of|dydt| implies a larger value of.

Thus, we can conclude that the sun is higher in the sky when the hawk glides by.

06

(d) Calculations of the speed of hawk’s shadow on the wall

dydt=45m/s

From equation (1), we have

dydt=dxdt迟补苍鈥45=dxdt迟补苍鈥

The speed of hawk is dxdt=15m/s

Therefore,

45=15tantan=4515=(71.56)(72)

The angleof the Sun if the speed of the hawk鈥檚 shadow on the wall is 45 m/s is=72

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