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Aslit 1.00mmwide is illuminated by light of wavelength 589nm. We see a diffraction pattern on a screen 3.00maway. What is the distance between the first two diffraction minima on the same side of the central diffraction maximum?

Short Answer

Expert verified

The distance between first two diffraction minima is1.77mm.

Step by step solution

01

Identification of given data

The wavelength of the light wave is =589nm

The distance of screen from slit is D=3m.

The width of slit is d=1mm.

The order of first minima is m1=1.

The order of second minima is m2=2.

02

Concept used

The distance between two successive diffraction minima is called the fringe width. It varies with the wavelength, slit width and distance of screen from slit.

03

Determination of distance between first two diffraction minima

The distance between first two diffraction minima is given as:

w=m2-m1Dd

Substitute all the values in equation.

w=2-1589nm10-9m1nm3m1mm10-3m1mm=1.7710-3m=1.7710-3m1mm10-3m=1.77mm

Therefore, the distance between first two diffraction minima is 1.77mm.

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Most popular questions from this chapter

If we make d=a in Fig. 36-50, the two slits coalesce into a single slit of width 2a. Show that Eq. 36-19 reduces to give the diffraction pattern for such a slit.

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