91影视

The given data can be listed below,

• The distance between flowers is,$D=60\text{cm}$
• The wavelength of the light from flower is,$位=500\text{nm}$
• The diameter of the pupil is, $d=5.5\text{mm}$

The capacity to recognise two closely spaced points as distinct is referred to as resolution power. Resolution is the capacity to recognise detail.

The angle of diffraction is given by,

$$\begin{gathered} \sin 胃=\frac{1.22位}{d} \\ 胃={\sin }^{-1}\left(\frac{1.22位}{d}\right) \end{gathered}$$ 鈥�(颈)

The distance between eye and length of the resolution is given by,

$$\begin{gathered} L胃=D \\ 胃=\frac{D}{L} \end{gathered}$$ 鈥�(颈颈)

Compare equation (i) and (ii) the distance of the flowers from the observation point is given by,

$$\begin{gathered} \frac{D}{L}=\frac{1.22位}{d} \\ L=\frac{Dd}{1.22位} \end{gathered}$$

Here,$位$ is the wavelength of the light, dis the diameter of the pupil, D is the smallest resolution distance.

Substitute all the values in the above,

$$\begin{gathered} L=\frac{\left(0.60\text{m}\right)\left(5,5脳{10}^{-3}\right)}{1.22\left(550脳{10}^{-9}\text{m}\right)} \\ =4918\text{m} \end{gathered}$$

Thus, the distance of flowers from the observation point is 4918 m.