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An x-ray beam of a certain wavelength is incident on an NaCl crystal, at 30.0°to a certain family of reflecting planes of spacing39.8pm.. If the reflection from those planes is of the first order, what is the wavelength of the x rays?

Short Answer

Expert verified

The wavelength of the x rays will be λA=39.8 pm.

Step by step solution

01

Introduction of diffraction

Diffraction is a phenomena in which the interference or the bending of waves occurs around the corners of the opening or obstacle through or on which it strikes.

The diffraction formula is following,

²Ôλ=2»å²õ¾±²Ôθλ=wavelengthd=spacingθ=bragg anglen=order of diffraction

02

Step 2: Identification of the given data

The reflecting planes of spacing is,d=39.8 pm .

The x-ray incident is, θ=30.0°.

03

The wavelength of the X rays

The wavelength of the x ray will be following with the help of given data and formula,

λ=2dsinθ

Substitute all the value in the above equation.

λA=239.8 pmsin30°λA=39.8 pm

Hence the wavelength of the x rays will be λA=39.8 pm.

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