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A diffraction grating has 200 lines/mm. Light consisting of a continuous range of wavelengths between 550 nm and 700 nm s incident perpendicularly on the grating.

(a) What is the lowest order that is overlapped by another order?

(b) What is the highest order for which the complete spectrum is present?

Short Answer

Expert verified

(a) The lowest order that is overlapped by another order is the 4th order.

(b) The highest order for which the complete spectrum is present from a grating having 200 lines/mmwith incident wavelength ranging between 550 nm and 700 nmis the 7th order.

Step by step solution

01

Given data

Number of lines per mm of the grating = 200

Lower limit of wavelength in the incident spectrum = 550 nm

Upper limit of wavelength in the incident spectrum = 700 nm

02

Definition and concept of diffraction from a grating

An optical element with a periodic structure that divides light into a number of beams that move in diverse directions is known as a diffraction grating.

The angular distance θ of the mthorder diffraction pattern produced from a grating having line separation d is

role="math" localid="1663073298458" dsinθ=mλ …(¾±)

Here, λ is the wavelength of the incident light.

03

(a) Determining the lowest order that is overlapped by another order

For overlap of order the mth order produced from the 700nm wave should match with the m+1th order produced from the 550 nm wave.

Thus from equation (i),

m×700nm=m+1×550nmm700-550=550m=550150=3.67

Thus the lowest order where overlap can occur is the 4th order

04

(b) Determining the maximum order with complete spectrum

The line separation of the grating is

d=1200mm=0.005mm=5000nm

Maximum order can be obtained from the 700 nm wave. Maximum value of sinθ is 1. Thus, from equation (i),

5000nm=mmax×700nmmmax=5000700=7.14

Thus, the maximum order for which the full spectrum can be obtained is the 7th order.

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