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Chapter 27: Q24P (page 796)

Question: In Figure,R1=R2=4.00惟andR3=2.50惟 . Find the equivalent resistance between points D and E.

(Hint: Imagine that a battery is connected across those points.)

Short Answer

Expert verified

Answer:

The equivalent resistance is Req=4.50惟.

Step by step solution

01

Given data:

The resistance R1=R2=4.00惟

The resistance R3=2.50惟

02

Understanding the concept:

Use the concept of the equivalent resistance of the series and the parallel circuit. Using these equations, we can find the equivalent resistance of the given circuit.

For series:

Req=R1+R2

For parallel:

1Req=1R1+1R2

03

Calculate the equivalent resistance between points D and E.  

The resistor R1 and R2 are parallel to each other, so you can find equivalent resistance for that, you get

1R=1R1+1R2=14惟+14惟=24惟-1=12惟-1R=2惟

Now, this equivalent resistance is in series with R3, so you can write,

Req=R+R3=2.00惟+2.50惟=4.50惟

Hence, the equivalent resistance is 4.50惟.

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Most popular questions from this chapter

In Fig. 27-82, an ideal battery of emf 蔚=12.0Vis connected to a network of resistancesR1=12.0惟, R2=12.0惟,R3=4.0惟,R4=3.00惟andR5=5.00惟. What is the potential difference across resistance 5?

A copper wire of radius a=0.250mmhas an aluminium jacket of outer radiusb=0.380mm. There is a currenti=2.00Ain the composite wire. Using Table 26-1, calculate the current in (a) the copper and (b) the aluminium. (c) If a potential differenceV=12.0Vbetween the ends maintains the current, what is the length of the composite wire?

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