91Ó°ÊÓ

1. Mass of module,$M\mathrm{is}500.0\mathrm{kg}$.
2. Mass of shuttle craft,$m\mathrm{is}500.0\mathrm{kg}$.
3. Speed of module and shuttle,$V_i\mathrm{is}1000\frac{\mathrm{m}}{\mathrm{s}}$.
4. Speed of module relative to shuttle, $V_R\mathrm{is}100.0\frac{\mathrm{m}}{\mathrm{s}}$.

Consider by conservation of momentum and kinetic energy find the velocity of the shuttle. From the kinetic energies of the module and shuttle and find the fraction. The formula used are stated below.

$$\begin{gathered} m_1{v}_{i1}+m_2{v}_{i2}=m_1{v}_{f1}+m_2{v}_{f2} \\ K.E=\frac{1}{2}m{v}^2 \end{gathered}$$

Determine the speed of the shuttle:

$m{v}_{i1}+m{v}_{i2}=m_1{v}_{f1}+m_2{v}_{f2}$

Initially, both the module and the shuttle had the same speed solve as:

$$\begin{gathered} m{v}_{i1}+m{v}_{i1}=m\left(V_{shuttle}-100.0\right)+m{v}_{shuttle} \\ \left(500.0+400.0\right)\left(1000\right)=500.0\left(V_{shuttle}-100.0\right)+\left(400.0\right)V_{shuttle} \\ 900000=900.0v_{shuttle}-50000 \\ 900.0v_{shuttle}=950000 \end{gathered}$$

Solve further as:

$$\begin{gathered} V_{shuttle}=\frac{950000}{900.0} \\ {V}_{shuttle}=1055.6\frac{\mathrm{m}}{\mathrm{s}} \end{gathered}$$

New speed for shuttle,

$$\begin{gathered} V_{new}=V_{shuttle}-100.0 \\ =1055.6-100 \\ =955.6\frac{\mathrm{m}}{\mathrm{s}} \end{gathered}$$

Finally, the module and shuttle have different speeds.

Now the change in kinetic energy of the module and shuttle is determined as:

$$\begin{gathered} K.E_f-K.E_i=\left[\frac{1}{2}\left(500.0\right){\left(955.6\right)}^2+\frac{1}{2}\left(400\right){\left(1055.6\right)}^2\right]-\frac{1}{2}\left(900\right){\left(1000\right)}^2 \\ K.E_f-K.E_i=1151112 \end{gathered}$$

So, the fraction is,

$$\begin{gathered} \frac{\left(K.E_f-K.E_i\right)}{K.E_i}=\frac{1151112}{4.5×{10}^8} \\ =2.5×{10}^{-3} \end{gathered}$$