/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q107P A 6100 kg rocket is set for ver... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A 6100 kgrocket is set for vertical firing from the ground. If the exhaust speed is 1200 m/s, how much gas must be ejected each second if the thrust (a) is to equal the magnitude of the gravitational force on the rocket and (b) is to give the rocket an initial upward acceleration of 21m/s2?

Short Answer

Expert verified

a) Therate of consumptionis 50 kg/s

b) The rate of consumption with the additional effect due to gravity is1.6×102kg/s

Step by step solution

01

Listing the given quantities

The value ofexhaust speed is 1200 m/s

Mass of the rocket is 6100 kg

Initial upward acceleration of21m/s2

02

Understanding the concept of launching the rocket

To successfully launched a rocket from the ground, fuel is consumed at a rate that results in a thrust big enough to overcome the gravitational force

Formula:

The thrust is given by T =Rvrel

Where, R is the rate of the fuel consumption

is the speed of the exhaust gas relative to the rocket

03

 Calculation of the rate of consumption

(a)

T=RvrelR=TVrel=MgVrel=(6100kg)(9.8m/s2)1200m/s=49.8kg/s≈50kg/s

The rate of consumption is 50 kg/s

04

Calculation of the rate of consumption with the additional effect due to gravity

(b)

(Rvrel-Mg=Ma)R=M(g+a)Vrel=(6100kg)(9.8m/s2+21m/s2)1200m/s=56.6kg/s≈1.6×102kg/s

The rate of consumption with the additional effect due to gravity is1.6×102kg/s

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider a rocket that is in deep space and at rest relative to an inertial reference frame. The rocket’s engine is to be fired for a certain interval. What must be the rocket’s mass ratio (ratio of initial to final mass) over that interval if the rocket’s original speed relative to the inertial frame is to be equal to (a) the exhaust speed (speed of the exhaust products relative to the rocket) and (b)2.0times the exhaust speed?

A uniform soda can of mass0.140kgis12.0cmtall and filled with0.354kgof soda (Figure 9-41). Then small holes are drilled in the top and bottom (with negligible loss of metal) to drain the soda. (a) What is the height hof the com of the can and contents initially and (b) After the can loses all the soda? (c) What happens to has the soda drains out? (d) If xis the height of the remaining soda at any given instant, find x when the com reaches its lowest point.

An electron undergoes a one-dimensional elastic collision with an initially stationary hydrogen atom. What percentage of the electron’s initial kinetic energy is transferred to kinetic energy of the hydrogen atom? (The mass of the hydrogen atom is 1840 times the mass of the electron)

A collision occurs between a 2.00 kgparticle travelling with velocity v1=(-4.00ms)iÁåœ+(-5.00ms)jÁåœand a 4.00 kgparticle travelling with velocity v2=(6.00ms)iÁåœ+(-2.00ms)jÁåœ. The collision connects the two particles. What then is their velocity in (a) unit-vector notation and as a (b) Magnitude and (c) Angle?

Suppose a gangster sprays Superman’s chest with3 gbullets at the rate of 100 bullets/min, and the speed of each bullet is 500 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman’s chest?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.