/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 A pulley wheel that is \(8.0 \ma... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A pulley wheel that is \(8.0 \mathrm{~cm}\) in diameter has a \(5.6\) -m-long cord wrapped around its periphery. Starting from rest, the wheel is given a constant angular acceleration of \(1.5 \mathrm{rad} / \mathrm{s}^{2}\). (a) Through what angle must the wheel turn for the cord to unwind completely? (b) How long will this take?

Short Answer

Expert verified
a) The wheel turns through 140 radians. b) It takes approximately 13.66 seconds.

Step by step solution

01

Understanding the problem

The problem describes a pulley wheel with a cord wrapped around it, and requires finding the angle through which the wheel turns to fully unwind the cord, and the time taken with a given angular acceleration.
02

Find the circumference of the wheel

The diameter of the wheel is given as 8.0 cm, so the radius is 4.0 cm. To find the circumference, use the formula for circumference of a circle: \( C = 2\pi r \). Thus, \( C = 2\pi \cdot 4.0 \) cm, which simplifies to \( C = 8\pi \) cm.
03

Convert circumference to meters

Convert the circumference from centimeters to meters for consistency with the length of the cord. So, \( C = 8\pi \approx 25.13 \) cm. Converted to meters, \( C \approx 0.2513 \) meters.
04

Determine total rotations needed

The cord length is 5.6 meters. To unwind the cord completely, divide the total length of the cord by the wheel's circumference in meters: \( \frac{5.6}{0.2513} \approx 22.27 \) full rotations.
05

Calculate the angle of rotation

Since each full rotation is \(2\pi\) radians, multiply the number of rotations by \(2\pi\) to find the angle: \( \theta = 22.27 \cdot 2\pi \approx 140 \) radians.
06

Use angular kinematics to find time

The initial angular velocity \(\omega_0\) is 0 because the wheel starts from rest. Using the angular kinematic equation \( \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \), where \( \theta = 140 \) radians and \( \alpha = 1.5 \) rad/s², solve for \(t\): \( 140 = 0 \cdot t + \frac{1}{2} \cdot 1.5 \cdot t^2 \). Simplifying gives \( t^2 = \frac{280}{1.5} \approx 186.67 \), and \( t \approx \sqrt{186.67} \approx 13.66 \) seconds.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pulley Wheel
Pulley wheels are essential devices found in many mechanical systems. They are circular objects that rotate around a central axis and are often used to change the direction of a force or to transfer motion. In this problem, we are dealing with a pulley wheel that has a cord wrapped around its edge. This setup can efficiently translate rotational motion into linear motion as the pulley rotates and the cord unwinds.

The diameter of our pulley wheel is crucial because it helps determine how far the wheel will turn when the cord is unwound. A larger diameter means a longer circumference, and therefore, fewer rotations are needed to release the same length of cord compared to a smaller wheel. Remember that the circumference of a circle is determined by the formula:
  • Circumference (C) = 2Ï€ × radius (r)
This calculation is fundamental in finding out how many times the wheel must rotate to unwind the entire length of the cord.
Angular Acceleration
Angular acceleration is a measure of how quickly an object's rotational speed changes. It is similar to linear acceleration, but instead of describing how fast an object speeds up or slows down in a straight line, angular acceleration describes these changes in circular motion.

In our problem, the wheel starts from rest, meaning its initial angular velocity is zero. The angular acceleration given is constant at 1.5 rad/s², indicating a steady increase in rotational speed. To calculate how long it takes for the wheel to unwind the cord completely, we use the angular kinematics equation:
  • θ = ω₀t + ½αt²
Here, θ represents the angle through which the wheel turns, ω₀ is the initial angular velocity, α is the angular acceleration, and t is the time. Understanding angular acceleration is key to predicting how dynamic systems like our pulley wheel behave over time.
Rotational Motion
Rotational motion refers to the motion of an object around a central point. It is a crucial part of understanding how different mechanical systems operate, especially those involving wheels or axles, like our pulley wheel. Rotational motion is described using physical concepts such as angular velocity, angular displacement, and angular acceleration.

In our pulley scenario, we're interested in determining the angular displacement, or the angle (θ) through which the wheel turns. Each full rotation of the wheel is equal to 2π radians, a complete circle.
  • 1 full rotation = 2Ï€ radians
  • To find out how many rotations are needed to unwind the cord, we divide the total length of the cord by the wheel’s circumference calculated earlier.
Calculating these rotations and converting them into radians give us the angle required for the wheel to complete its job. Understanding rotational motion helps predict the movement and time taken by the wheel to unwind fully.
Physics Problem Solving
Solving physics problems involves breaking down complex systems into manageable parts. This approach helps in understanding not only what calculations need to be performed but also why they are essential.

To solve the problem of the unwinding cord, we followed a structured process:
  • First, defining the problem, which involves identifying the knowns and unknowns.
  • Next, applying relevant formulas—like those for circumference and angular kinematics—to connect these knowns to find the unknowns.
  • Finally, double-checking units, ensuring consistency helps minimize errors, especially when converting between different units of measure, like centimeters to meters.
Following these steps ensures a logical progression in solving rotational dynamics problems like the pulley system, enhancing comprehension and precision.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Trucks can be run on energy stored in a rotating flywheel, with an electric motor getting the flywheel up to its top speed of \(200 \pi \mathrm{rad} / \mathrm{s}\). Suppose that one such flywheel is a solid, uniform cylinder with a mass of \(500 \mathrm{~kg}\) and a radius of \(1.0 \mathrm{~m}\). (a) What is the kinetic energy of the flywheel after charging? (b) If the truck uses an average power of \(8.0 \mathrm{~kW}\), for how many minutes can it operate between chargings?

A disk, with a radius of \(0.25 \mathrm{~m}\), is to be rotated like a merrygo- round through 800 rad, starting from rest, gaining angular speed at the constant rate \(\alpha_{1}\) through the first \(400 \mathrm{rad}\) and then losing angular speed at the constant rate \(-\alpha_{1}\) until it is again at rest. The magnitude of the centripetal acceleration of any portion of the disk is not to exceed \(400 \mathrm{~m} / \mathrm{s}^{2} .\) (a) What is the least time required for the rotation? (b) What is the corresponding value of \(\alpha_{1}\) ?

A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is rotating at \(10 \mathrm{rev} / \mathrm{s} ; 60\) revolutions later, its angular speed is 15 rev/s. Calculate (a) the angular acceleration, (b) the time required to complete the 60 revolutions, (c) the time required to reach the \(10 \mathrm{rev} / \mathrm{s}\) angular speed, and (d) the number of revolutions from rest until the time the disk reaches the 10 rev/s angular speed.

The angular position of a point on the rim of a rotating wheel is given by \(\theta=4.0 t-3.0 t^{2}+t^{3}\), where \(\theta\) is in radians and \(t\) is in seconds. What are the angular velocities at (a) \(t=2.0 \mathrm{~s}\) and \((\mathrm{b}) t=4.0 \mathrm{~s} ?\) (c) What is the average angular acceleration for the time interval that begins at \(t=2.0 \mathrm{~s}\) and ends at \(t=4.0 \mathrm{~s}\) ? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval?

Two uniform solid spheres have the same mass of \(1.65 \mathrm{~kg}\), but one has a radius of \(0.226 \mathrm{~m}\) and the other has a radius of \(0.854 \mathrm{~m}\). Each can rotate about an axis through its center. (a) What is the magnitude \(\tau\) of the torque required to bring the smaller sphere from rest to an angular speed of \(317 \mathrm{rad} / \mathrm{s}\) in \(15.5 \mathrm{~s}\) ? (b) What is the magnitude \(F\) of the force that must be applied tangentially at the sphere's equator to give that torque? What are the corresponding values of (c) \(\tau\) and (d) \(F\) for the larger sphere?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.