/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 Trucks can be run on energy stor... [FREE SOLUTION] | 91Ó°ÊÓ

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Trucks can be run on energy stored in a rotating flywheel, with an electric motor getting the flywheel up to its top speed of \(200 \pi \mathrm{rad} / \mathrm{s}\). Suppose that one such flywheel is a solid, uniform cylinder with a mass of \(500 \mathrm{~kg}\) and a radius of \(1.0 \mathrm{~m}\). (a) What is the kinetic energy of the flywheel after charging? (b) If the truck uses an average power of \(8.0 \mathrm{~kW}\), for how many minutes can it operate between chargings?

Short Answer

Expert verified
The flywheel has 49,350 J of energy; the truck operates for about 0.103 minutes per charge.

Step by step solution

01

Calculate Moment of Inertia

The moment of inertia (I) for a solid cylinder rotating about its axis is given by the formula:\[ I = \frac{1}{2} m r^2 \]where \( m = 500 \text{ kg} \) is the mass and \( r = 1.0 \text{ m} \) is the radius. Substituting the given values:\[ I = \frac{1}{2} \times 500 \times (1.0)^2 = 250 \text{ kg m}^2 \]
02

Calculate Kinetic Energy

The kinetic energy (KE) stored in a rotating flywheel is calculated using the formula:\[ KE = \frac{1}{2} I \omega^2 \]where \( \omega = 200 \pi \text{ rad/s} \). Substituting the values:\[ KE = \frac{1}{2} \times 250 \times (200\pi)^2 \]First, calculate \((200\pi)^2 = 40000\pi^2\):\[ KE = 125 \times 40000\pi^2 = 5000\pi^2 \]\Using \( \pi \approx 3.1416 \), compute the \( KE \):\[ KE \approx 5000 \times (3.1416)^2 \approx 5000 \times 9.87 \approx 49350 \text{ J} \]
03

Determine Operating Time of the Truck

The truck consumes power at a rate of \( 8.0 \text{ kW} \) which is \( 8000 \text{ W} \).The total time \( t \) the truck can operate can be calculated by dividing the total kinetic energy by the power consumption:\[ t = \frac{KE}{P} = \frac{49350}{8000} \text{ seconds} \]Compute the time:\[ t \approx 6.17 \text{ seconds} \]Convert seconds to minutes:\[ t \approx \frac{6.17}{60} \approx 0.1028 \text{ minutes} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
The moment of inertia is a physical property of a rotating object that determines how much torque is needed to rotate the object about an axis. For a solid cylinder, like our flywheel, it can be thought of as the rotational equivalent of mass in linear motion. To calculate the moment of inertia for a solid cylinder, use the formula:\[ I = \frac{1}{2} mr^2 \]In this equation, \(m\) represents the mass of the cylinder and \(r\) is its radius. In our example, the mass is 500 kg, and the radius is 1 m. Plug these values into the formula, giving us:\[ I = \frac{1}{2} \times 500 \times (1.0)^2 = 250 \text{ kg m}^2 \]This tells us it takes 250 kg m² of rotational inertia to start or stop the flywheel’s spin. Understanding moment of inertia is crucial for designing systems that involve rotational motion.
Kinetic Energy
Kinetic energy, in the context of a rotating object, measures the energy an object possesses due to its rotation. For rotational motion, the formula is given by:\[ KE = \frac{1}{2} I \omega^2 \]where \(I\) is the moment of inertia and \(\omega\) is the angular velocity. Our flywheel reaches an angular velocity of \(200 \pi \text{ rad/s}\). Using the moment of inertia calculated previously (250 kg m²), we find the kinetic energy:Calculate \((200 \pi)^2 = 40000 \pi^2\):\[ KE = 125 \times 40000 \pi^2 \]Substituting \(\pi \approx 3.1416\):\[ KE \approx 5000 \times (3.1416)^2 \approx 5000 \times 9.87 \approx 49350 \, \text{J} \]This calculated kinetic energy of 49350 Joules is the energy stored in the flywheel after it reaches its maximum speed. This energy will later be utilized by the truck for power consumption.
Power Consumption
Power consumption refers to the rate at which energy is used up. In our scenario, the truck uses power at a rate of 8.0 kW, or 8000 W. To determine how long the truck can operate on the stored energy, divide the total kinetic energy by the power consumption:\[ t = \frac{KE}{P} = \frac{49350}{8000} \, \text{seconds} \]Perform the calculation:\[ t \approx 6.17 \, \text{seconds} \]Convert this operation time from seconds to minutes:\[ t \approx \frac{6.17}{60} \approx 0.1028 \, \text{minutes} \]This means the truck can run for just over 6 seconds on the stored energy. Understanding this helps in designing the system to ensure the energy demands match the application needs.
Solid Cylinder
A solid cylinder is a three-dimensional object with two parallel circular bases connected by a curved surface. In physics, they often serve as models for rotating systems due to their uniform mass distribution. When considering rotational motion, the properties like mass, radius, and axis of rotation are crucial in determining a cylinder's moment of inertia.
  • Mass: For the flywheel, this is given as 500 kg.
  • Radius: Also provided as 1 m.
  • Axis of Rotation: In this problem, the axis passes through the center of the base, making calculations simpler with the standard formulas.
Understanding solid cylinders from this perspective is vital not only for calculating properties like moment of inertia but also for optimizing energy storage and minimizing energy loss in rotating systems.

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Most popular questions from this chapter

A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is rotating at \(10 \mathrm{rev} / \mathrm{s} ; 60\) revolutions later, its angular speed is 15 rev/s. Calculate (a) the angular acceleration, (b) the time required to complete the 60 revolutions, (c) the time required to reach the \(10 \mathrm{rev} / \mathrm{s}\) angular speed, and (d) the number of revolutions from rest until the time the disk reaches the 10 rev/s angular speed.

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