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A point on the rim of a \(0.75-\mathrm{m}\) -diameter grinding wheel changes speed at a constant rate from \(12 \mathrm{~m} / \mathrm{s}\) to \(25 \mathrm{~m} / \mathrm{s}\) in \(6.2 \mathrm{~s}\). What is the average angular acceleration of the wheel?

Short Answer

Expert verified
The average angular acceleration is approximately \(5.59\, \text{rad/s}^2\).

Step by step solution

01

Understanding the Problem

We need to find the average angular acceleration of a grinding wheel. We're given the initial and final linear speeds of a point on its rim and the duration of the change in speed. The wheel's diameter is also provided. We'll start by finding the change in angular speed and then use it to find angular acceleration.
02

Find the Radius of the Wheel

The diameter of the wheel is given as \(0.75\, \text{m}\). The radius \(r\) is half of the diameter, which is \(r = \frac{0.75}{2} = 0.375\, \text{m}\).
03

Convert Linear Speeds to Angular Speeds

The linear speed \(v\) is related to angular speed \(\omega\) by the formula \(v = r\omega\). We first calculate the initial angular speed \(\omega_i\) and final angular speed \(\omega_f\). The initial speed is \(12\, \text{m/s}\), so \(\omega_i = \frac{12}{0.375}\, \text{rad/s}\). The final speed is \(25\, \text{m/s}\), so \(\omega_f = \frac{25}{0.375}\, \text{rad/s}\).
04

Calculate Initial and Final Angular Speeds

Calculate \(\omega_i\) as:\[ \omega_i = \frac{12}{0.375} = 32\, \text{rad/s} \]Calculate \(\omega_f\) as:\[ \omega_f = \frac{25}{0.375} = 66.67\, \text{rad/s} \]
05

Find the Change in Angular Speed

The change in angular speed \(\Delta \omega\) is given by \(\Delta \omega = \omega_f - \omega_i\). Thus:\[ \Delta \omega = 66.67 - 32 = 34.67\, \text{rad/s} \]
06

Calculate the Time Interval

The time over which the change in speed occurs is given as \(6.2\, \text{s}\).
07

Calculate the Average Angular Acceleration

Angular acceleration \(\alpha\) is the change in angular speed per unit time, given by \(\alpha = \frac{\Delta \omega}{\Delta t}\). Substitute the known values:\[ \alpha = \frac{34.67}{6.2} \approx 5.59\, \text{rad/s}^2 \]
08

Conclusion

The average angular acceleration of the wheel is approximately \(5.59\, \text{rad/s}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Speed to Angular Speed Conversion
When dealing with circular motion, it is essential to understand how to convert linear speed into angular speed. Linear speed is the speed along a straight path, whereas angular speed is the rate at which an object moves along a circular path. The relationship between linear speed and angular speed is given by the formula:
  • \( v = r\omega \)
Here, \( v \) represents linear speed, \( r \) is the radius of the circular path, and \( \omega \) denotes angular speed.

Given the linear speed and the radius, you can easily find the angular speed by rearranging the formula to:
  • \( \omega = \frac{v}{r} \)
This conversion is pivotal in problems involving circular motion, such as analyzing the dynamics of a grinding wheel. By understanding this relation, you can seamlessly transition between linear and angular quantities, which simplifies broader calculations such as determining angular acceleration.
Angular Speed Calculation
To calculate angular speed, we must first determine the radius of the circular path. The grinding wheel in our problem has a diameter of \( 0.75 \, \text{m} \), so its radius is:
  • \( r = \frac{0.75}{2} = 0.375 \, \text{m} \)
Using the radius and the given linear speeds, we can find the initial and final angular speeds. For the initial linear speed of \( 12\, \text{m/s} \), the initial angular speed \( \omega_i \) is computed as follows:
  • \( \omega_i = \frac{12}{0.375} = 32 \, \text{rad/s} \)
Similarly, the final angular speed \( \omega_f \) for the linear speed of \( 25\, \text{m/s} \) is:
  • \( \omega_f = \frac{25}{0.375} = 66.67 \, \text{rad/s} \)
This step transitions the analysis from linear to angular measurements, critical for subsequent calculations like finding angular acceleration.
Grinding Wheel Dynamics
Understanding the dynamics of a grinding wheel involves analyzing how its angular speed changes over time. The angular acceleration, \( \alpha \), is a key component here. It describes the rate of change of angular speed and is calculated by dividing the change in angular speed by the time interval over which the change occurs:
  • \( \alpha = \frac{\Delta \omega}{\Delta t} \)
In our example, the change in angular speed \( \Delta \omega \) is:
  • \( \Delta \omega = \omega_f - \omega_i = 66.67 - 32 = 34.67 \, \text{rad/s} \)
Given the time duration \( \Delta t \) of \( 6.2 \, \text{s} \), the average angular acceleration is computed as:
  • \( \alpha = \frac{34.67}{6.2} \approx 5.59 \, \text{rad/s}^2 \)
The average angular acceleration provides insight into how the rotational speed of the wheel is increasing and is a vital metric for understanding the wheel's response to different forces and torques.

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