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Antarctica is roughly semicircular, with a radius of \(2000 \mathrm{~km}\) (Fig. \(1-5)\). The average thickness of its ice cover is \(3000 \mathrm{~m}\). How many cubic centimeters of ice does Antarctica contain? (Ignore the curvature of Earth.)

Short Answer

Expert verified
Antarctica contains approximately \(1.884 \times 10^{21} \text{ cubic centimeters of ice.}\)

Step by step solution

01

Calculating the Area of the Semicircle

First, we need to calculate the area of Antarctica, which is roughly semicircular. The formula for the area of a circle is \(A = \pi r^2\). Since Antarctica is semicircular, we use half of this formula: \(A = \frac{1}{2} \pi r^2\). Given the radius \(r = 2000 \text{ km} = 2,000,000 \text{ m}\), we calculate the area in square meters.
02

Volume of Ice in Cubic Meters

To find the volume of the ice, we multiply the area of the semicircle by the average thickness of the ice. With the area from Step 1 and the thickness of 3000 m, the volume in cubic meters is given by \(V = A \times 3000\).
03

Conversion from Cubic Meters to Cubic Centimeters

We need to convert the volume from cubic meters to cubic centimeters. Since \(1 \text{ m}^3 = 10^6 \text{ cm}^3\), we multiply the volume in cubic meters by \(10^6\) to get the volume in cubic centimeters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Semicircular area
When dealing with geometric shapes like a semicircle, it's important to understand how to calculate their areas. A semicircle is half of a full circle, and its area can be determined by halving the formula for the area of a full circle. The formula to calculate the area of a circle is given by:\[A = \pi r^2\]
To find the area of a semicircle, we simply take half of the circle's area:\[A = \frac{1}{2} \pi r^2\]We need to pay special attention to the units of measurement for the radius, ensuring they are consistent throughout the calculation. For the problem at hand, the radius is provided as 2000 kilometers, which needs to be converted into meters (1 kilometer = 1000 meters), resulting in a radius of 2,000,000 meters for our area calculation.
It's crucial to remember that the radius has a huge impact on the size of the area; doubling the radius increases the area by four times because the radius is squared in the formula.
Ice thickness
The concept of ice thickness plays a vital role in determining how much ice is present over a given area. Thickness is essentially the vertical measurement from the base of the glacier or ice sheet to its surface. It gives the third dimension necessary to calculate volume once the area is known.
In this exercise, the average ice thickness is 3000 meters. This means that, on average, the glacier extends 3000 meters vertically at any given point. This measurement is crucial as it directly influences the volume calculation of the ice in Antarctica.
  • The thicker the ice, the more volume it occupies for the same area.
  • This vertical dimension turns the two-dimensional area into a three-dimensional space, allowing for volume calculations.
  • Understanding ice thickness helps in assessing the total mass and corresponding water volume if the ice were to melt.
Unit conversion
Unit conversion is the process of changing the measurements from one unit to another to maintain consistency and understanding. In scientific calculations like these, unit conversions are virtually unavoidable. Here, we need to manage conversions between kilometers, meters, and subsequently cubic meters to cubic centimeters.
For this problem:
  • The radius was initially given in kilometers and converted to meters to align with the standard unit of thickness in meters. With 1 kilometer equal to 1000 meters, 2000 kilometers converts to 2,000,000 meters.
  • After calculating the volume in cubic meters, we needed to convert it into cubic centimeters since it’s easier to work with smaller units for further calculations. One cubic meter equals 1,000,000 cubic centimeters (\(1 \text{ m}^3 = 10^6 \text{ cm}^3\)).
This precise conversion ensures our final volume of ice is expressed in a standard, understandable unit, ensuring accuracy and applicability in various contexts.
Mathematical operations
Mathematical operations involve procedures like addition, subtraction, multiplication, and division to solve problems. In this particular exercise on volume calculation, operations are integral to progress through each step systematically.
We begin by multiplying to calculate the semicircular area using:\[A = \frac{1}{2} \pi r^2\]Given that the area is solved, the next operation involves multiplying this area by the average thickness of the ice to determine the volume. This process, called multiplication, extends the two-dimensional area into three-dimensional space through thickness:\[V = A \times 3000\]
Lastly, conversion requires scaling operations, multiplying the cubic meter volume by \(10^6\) to convert it to cubic centimeters:\[V_{\text{cm}^3} = V_{\text{m}^3} \times 10^6\]
Understanding these operations' rules and application is essential to solve such exercises accurately and obtain meaningful results.

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Most popular questions from this chapter

In the United States, a doll house has the scale of \(1: 12\) of a real house (that is, each length of the doll house is \(\frac{1}{12}\) that of the real house) and a miniature house (a doll house to fit within a doll house) has the scale of \(1: 144\) of a real house. Suppose a real house (Fig. 1-7) has a front length of \(20 \mathrm{~m}\), a depth of \(12 \mathrm{~m}\), a height of \(6.0 \mathrm{~m}\), and a standard sloped roof (vertical triangular faces on the ends) of height \(3.0 \mathrm{~m}\). In cubic meters, what are the volumes of the corresponding (a) doll house and (b) miniature house?

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