/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Earth is approximately a sphere ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Earth is approximately a sphere of radius \(6.37 \times 10^{6} \mathrm{~m}\). What are (a) its circumference in kilometers, (b) its surface area in square kilometers, and (c) its volume in cubic kilometers?

Short Answer

Expert verified
Circumference: \( 4.00 \times 10^{4} \mathrm{~km} \), Surface Area: \( 5.10 \times 10^{8} \mathrm{~km^2} \), Volume: \( 1.08 \times 10^{12} \mathrm{~km^3} \).

Step by step solution

01

Formula for Circumference

The circumference of a sphere is given by the formula \( C = 2\pi r \). Here, \( r = 6.37 \times 10^{6} \mathrm{~m} \) is the radius of the Earth.
02

Calculate Circumference

Substitute the radius into the formula: \( C = 2 \times \pi \times 6.37 \times 10^{6} \mathrm{~m} \). When calculated, this yields approximately \( 4.00 \times 10^{4} \mathrm{~km} \) as the circumference of the Earth.
03

Formula for Surface Area

The surface area of a sphere is given by the formula \( A = 4\pi r^2 \). Again, \( r = 6.37 \times 10^{6} \mathrm{~m} \).
04

Calculate Surface Area

Substitute the radius into the formula: \( A = 4 \times \pi \times (6.37 \times 10^{6} \mathrm{~m})^2 \). This results in approximately \( 5.10 \times 10^{8} \mathrm{~km^2} \).
05

Formula for Volume

The volume of a sphere is determined by the formula \( V = \frac{4}{3}\pi r^3 \). Here we again use \( r = 6.37 \times 10^{6} \mathrm{~m} \).
06

Calculate Volume

Substitute the radius into the formula: \( V = \frac{4}{3} \times \pi \times (6.37 \times 10^{6} \mathrm{~m})^3 \). This results in approximately \( 1.08 \times 10^{12} \mathrm{~km^3} \) for the Earth's volume.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circumference Calculation
Understanding how to calculate the circumference of Earth is crucial when studying its geometry. The circumference represents the distance around the widest part of the sphere. For any sphere, it can be calculated using the formula \( C = 2\pi r \). Here, \( r \) symbolizes the radius of the sphere.

When dealing with the Earth, we're given that its radius is \(6.37 \times 10^{6} \mathrm{~m}\). To find the circumference, we plug this value into our formula, giving us \( C = 2 \times \pi \times 6.37 \times 10^{6} \mathrm{~m} \). By performing the calculation step-by-step, you multiply the components together:
  • First, multiply 2 by \(\pi\), which is approximately 3.14159.
  • Next, multiply the result by the Earth's radius in meters.
This simplifies to give a circumference of around \( 4.00 \times 10^{4} \mathrm{~km} \), after converting the result from meters to kilometers. This means if you were to travel around the widest point of Earth without deviating, you would travel approximately 40,000 kilometers.
Surface Area of a Sphere
The surface area of a sphere is important in understanding the total area that makes up its outer layer. For the Earth, this is equivalent to the entire surface that includes land, water, and ice. The formula for surface area is \( A = 4\pi r^2 \). Here, \( r \) is again the radius.

To calculate the Earth's surface area, use the given radius of \(6.37 \times 10^{6} \mathrm{~m}\):
  • Square the radius to get \( (6.37 \times 10^{6} \mathrm{~m})^2 \).
  • Multiply the squared radius by 4 and then by \(\pi\).
This results in a surface area of approximately \( 5.10 \times 10^{8} \mathrm{~km^2} \) once converted into square kilometers. Therefore, the Earth's surface area is roughly 510 million square kilometers, encompassing all continents and oceans.
Volume of a Sphere
The volume of a sphere gives us an idea of how much space it occupies. For Earth, this volume includes the entire mass of its inner layers. To find the volume, use the formula \( V = \frac{4}{3}\pi r^3 \). The radius \( r \) remains as \(6.37 \times 10^{6} \mathrm{~m}\) for Earth.

Here's how you calculate its volume:
  • Cube the radius to get \( (6.37 \times 10^{6} \mathrm{~m})^3 \).
  • Multiply the result by \(\pi\).
  • Finally, multiply by \(\frac{4}{3} \).
The result is the Earth's volume, approximately \( 1.08 \times 10^{12} \mathrm{~km^3} \) when converted into cubic kilometers. This immense volume underscores the vastness of Earth's internal mass.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A cord is a volume of cut wood equal to a stack \(8 \mathrm{ft}\) long, \(4 \mathrm{ft}\) wide, and \(4 \mathrm{ft}\) high. How many cords are in \(1.0 \mathrm{~m}^{3}\) ?

Time standards are now based on atomic clocks. A promising second standard is based on pulsars, which are rotating neutron stars (highly compact stars consisting only of neutrons). Some rotate at a rate that is highly stable, sending out a radio beacon that sweeps briefly across Earth once with each rotation, like a lighthouse beacon. Pulsar PSR \(1937+21\) is an example; it rotates once every \(1.55780644887275 \pm 3 \mathrm{~ms}\), where the trailing \(\pm 3\) indicates the uncertainty in the last decimal place (it does not mean \(\pm 3 \mathrm{~ms}\) ). (a) How many rotations does PSR \(1937+21\) make in \(7.00\) days? (b) How much time does the pulsar take to rotate exactly one million times and (c) what is the associated uncertainty?

In purchasing food for a political rally, you erroneously order shucked medium-size Pacific oysters (which come 8 to 12 per U.S. pint) instead of shucked medium-size Atlantic oysters (which come 26 to 38 per U.S. pint). The filled oyster container shipped to you has the interior measure of \(1.0 \mathrm{~m} \times 12 \mathrm{~cm} \times 20 \mathrm{~cm}\), and a U.S. pint is equivalent to \(0.4732\) liter. By how many oysters is the order short of your anticipated count?

For about 10 years after the French Revolution, the French government attempted to base measures of time on multiples of ten: One week consisted of 10 days, one day consisted of 10 hours, one hour consisted of 100 minutes, and one minute consisted of 100 seconds. What are the ratios of (a) the French decimal week to the standard week and (b) the French decimal second to the standard second?

Antarctica is roughly semicircular, with a radius of \(2000 \mathrm{~km}\) (Fig. \(1-5)\). The average thickness of its ice cover is \(3000 \mathrm{~m}\). How many cubic centimeters of ice does Antarctica contain? (Ignore the curvature of Earth.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.