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Air at \(200 \mathrm{kPa}\) enters a 2 -m-long, thin-walled tube of \(25-\mathrm{mm}\) diameter at \(150^{\circ} \mathrm{C}\) and \(6 \mathrm{~m} / \mathrm{s}\). Steam at 20 bars condenses on the outer surface. (a) Determine the outlet temperature and pressure drop of the air, as well as the rate of heat transfer to the air. (b) Calculate the parameters of part (a) if the pressure of the air is doubled.

Short Answer

Expert verified
In summary, we can use the conservation of mass, energy, and momentum principles along with heat transfer relations to determine the outlet temperature and pressure drop of the air, as well as the rate of heat transfer to the air for the given conditions. Firstly, calculate the mass flow rate of air using the ideal gas law. Next, apply the energy balance equation and the Darcy-Weisbach equation to determine the outlet temperature and pressure drop, respectively. Then, use the overall heat transfer coefficient to find the rate of heat transfer. Lastly, repeat these steps with double the initial air pressure to find the new values for the outlet temperature, pressure drop, and heat transfer rate.

Step by step solution

01

(Step 1: Analyze the given data)

First, let's write down the given data: Initial pressure of air, \(P_1 = 200 \, kPa\) Diameter of the tube, \(D = 25 \, mm\) Length of the tube, \(L = 2 \,m\) Initial temperature of air, \(T_1 = 150^\circ C\) Initial velocity of air, \(v_1 = 6 \,m/s\) Pressure of steam, \(P_{steam} = 20 \,bars\)
02

(Step 2: Calculate mass flow rate of air)

Using the ideal gas law, we can calculate the mass flow rate of air, \( \dot{m} \), using: \[ \dot{m} = \frac{P_1 A_1 v_1}{RT_1} \] Where \(P_1\) is the initial pressure, \(A_1\) is the cross-sectional area of the tube, \(v_1\) is the initial velocity, \(R\) is the specific gas constant for air, and \(T_1\) is the initial temperature. Calculate the cross-sectional area using the diameter of the tube: \[A_1 = \frac{\pi D^2}{4}\] Now, we can find the mass flow rate of air.
03

(Step 3: Determine the outlet temperature and pressure drop)

We can determine the outlet temperature by applying the energy balance equation: \[\dot{Q} = \dot{m}c_p (T_2 - T_1)\] Where \(\dot{Q}\) is the rate of heat transfer, \(c_p\) is the specific heat at constant pressure, and \(T_2\) represents the outlet temperature. To find the pressure drop, we will use the Darcy-Weisbach equation: \[\Delta P = f \frac{L}{D} \frac{\rho v^2}{2}\] Where \(\Delta P\) is the pressure drop, \(f\) is the friction factor, \(L\) is the length of the tube, \(D\) is the diameter of the tube, \(\rho\) is the density of air, and \(v\) is the average air velocity. The friction factor, \(f\), can be found from a correlation such as the Colebrook-White equation relating \(f\), the Reynolds number, and the relative roughness.
04

(Step 4: Calculate the rate of heat transfer)

To find the rate of heat transfer, we can use the overall heat transfer coefficient, \(U\), and an appropriate correlation such as the Nusselt number, \(Nu\): \[Nu = \frac{hD}{k}\] Where \(Nu\) is the Nusselt number, \(h\) is the heat transfer coefficient, \(D\) is the diameter of the tube, and \(k\) is the thermal conductivity of air. The Nusselt number can be found using an appropriate correlation for internal flow. Now, the overall heat transfer can be calculated as: \[\dot{Q} = U A (T_{steam} - T_{air})\] Where \(U\) is the overall heat transfer coefficient, \(A\) is the surface area of the tube, \(T_{steam}\) is the temperature of the steam, and \(T_{air}\) is the average temperature of the air.
05

(Step 5: Solve for the case when the air pressure is doubled)

In the second part of the problem, we are asked to calculate the same parameters as before, except the pressure of the air is now doubled. To achieve this, we can follow the same steps as above, but now use an initial pressure of \(P_{1,new} = 2P_1 = 400 \, kPa\). Calculate the new mass flow rate, outlet temperature, pressure drop, and heat transfer rate using the same equations and methods as before. These steps will provide the answers for outlet temperature, pressure drop, and the rate of heat transfer for both cases: the initial pressure and when doubled.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass Flow Rate
The mass flow rate is a key concept in fluid dynamics and thermodynamics, essential for calculating the movement of mass through a pipe or a conduit over time. It is commonly denoted as \( \.{m} \). In our context of air flowing through a tube, the mass flow rate is indicative of how much air mass passes through a cross-sectional area of the tube per unit time.

To calculate the mass flow rate, the following formula derived from the ideal gas law can be applied:
\[ \.{m} = \frac{P_1 A_1 v_1}{RT_1} \] where \( P_1 \) is the pressure of the air, \( A_1 \) is the cross-sectional area of the tube, \( v_1 \) is the velocity of the air, \( R \) is the specific gas constant for air, and \( T_1 \) is the temperature of the air.

The area \( A_1 \) can be calculated using the diameter \( D \) of the tube:
\[ A_1 = \frac{\pi D^2}{4} \] Understanding mass flow rate allows us to determine other important aspects of flow such as velocity profiles, pressure drops, and heat transfer rates which are crucial for designing and optimizing HVAC systems, engines, and various industrial processes.
Outlet Temperature Calculation
The outlet temperature is the temperature of the fluid, in this case, air, as it exits the tube. This is an important parameter in the analysis of heat transfer applications as it ultimately influences the thermal performance of the system.

To calculate the outlet temperature \( T_2 \) of air, we use the energy balance equation, assuming steady-state conditions:
\[ \.{Q} = \.{m}c_p (T_2 - T_1) \] Rearranging the equation to solve for the outlet temperature yields:
\[ T_2 = T_1 + \frac{\dot{Q}}{\dot{m}c_p} \] Here, \( c_p \) is the specific heat of air at constant pressure, and \( \.{Q} \) is the rate of heat transfer to the air. This is a critical calculation in a wide range of engineering applications, including assessing performance in heat exchangers, radiators, and energy systems.
Pressure Drop
Pressure drop across a tube flow is a vital parameter for engineers as it affects system efficiency and pump selection. It is the difference in pressure from one end of a tube to the other, usually caused by frictional forces between the fluid and the tube walls and within the fluid itself.

The Darcy-Weisbach equation provides a formula to estimate this pressure drop:
\[ \Delta P = f \frac{L}{D} \frac{\rho v^2}{2} \] where \( \Delta P \) represents the pressure drop, \( f \) is the friction factor that accounts for the resistance due to friction, \( \rho \) is the density of air, \( L \) and \( D \) are the length and diameter of the tube respectively, and \( v \) is the fluid velocity. A higher pressure drop signifies more energy required to pump the air through the system, which is a critical element to consider for optimization and energy conservation in fluid transport systems.
Darcy-Weisbach Equation
The Darcy-Weisbach equation is a foundational principle in fluid mechanics used to calculate the pressure loss due to friction along a given length of pipe with steady incompressible flow. The equation is expressed as follows:
\[ \Delta P = f \frac{L}{D} \frac{\rho v^2}{2} \]
In this equation, the friction factor \( f \) depends on the characteristics of the fluid and the pipe's surface. It can be determined using empirical correlations such as the Colebrook-White equation, which relates \( f \) to the Reynolds number and the relative roughness of the pipe. The Reynolds number helps to predict whether the flow is laminar or turbulent, which directly affects the calculated friction factor. Understanding how to apply the Darcy-Weisbach equation is essential for engineers not only to predict pressure losses but also to design systems with the appropriate pump and pipe dimensions to ensure efficient operation.
Nusselt Number Correlation
The Nusselt number is a dimensionless value that describes the convective heat transfer occurring within a fluid. It relates the convective to the conductive heat transfer across a boundary layer. Larger Nusselt numbers indicate more effective convection, which is a key insight for optimizing heat exchange systems.

It is defined as:
\[ Nu = \frac{hD}{k} \]
Here, \( h \) is the convective heat transfer coefficient of the fluid, \( D \) is the characteristic length (diameter for pipe flow), and \( k \) is the thermal conductivity. Correlations to estimate the Nusselt number, such as the Dittus-Boelter equation for turbulent flow or the Sieder-Tate correlation for viscous fluids, consider factors including the Reynolds number and the Prandtl number. The proper use of the Nusselt number can significantly impact the accurate calculation of the heat transfer rates in heat exchangers and other thermal systems.
Overall Heat Transfer Coefficient
The overall heat transfer coefficient, denoted by \( U \), is a measure that accounts for the combined resistance to heat transfer in series, including conductive and convective barriers. It's a critical concept when analyzing complex systems like a tube with an external steam condensation process.

To estimate the rate of heat transfer \( \.{Q} \) in our given problem, we use the equation:
\[ \.{Q} = U A (T_{steam} - T_{air}) \] where \( A \) is the heat transfer surface area, and \( T_{steam} \) and \( T_{air} \) are the temperatures of the steam and the average air temperature, respectively. The overall heat transfer coefficient is influenced by the materials involved, the fluid velocities, and the type of heat exchange process. Accurately calculating \( U \) is essential for sizing heat exchangers and energy systems, ensuring economical and efficient thermal design solutions.

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Most popular questions from this chapter

Heated air required for a food-drying process is generated by passing ambient air at \(20^{\circ} \mathrm{C}\) through long, circular tubes \((D=50 \mathrm{~mm}, L=5 \mathrm{~m})\) housed in a steam condenser. Saturated steam at atmospheric pressure condenses on the outer surface of the tubes, maintaining a uniform surface temperature of \(100^{\circ} \mathrm{C}\). (a) If an airflow rate of \(0.01 \mathrm{~kg} / \mathrm{s}\) is maintained in each tube, determine the air outlet temperature \(T_{m, o}\) and the total heat rate \(q\) for the tube. (b) The air outlet temperature may be controlled by adjusting the tube mass flow rate. Compute and plot \(T_{m \rho}\) as a function of \(\dot{m}\) for \(0.005 \leq \dot{m} \leq\) \(0.050 \mathrm{~kg} / \mathrm{s}\). If a particular drying process requires approximately \(1 \mathrm{~kg} / \mathrm{s}\) of air at \(75^{\circ} \mathrm{C}\), what design and operating conditions should be prescribed for the air heater, subject to the constraint that the tube diameter and length be fixed at \(50 \mathrm{~mm}\) and \(5 \mathrm{~m}\), respectively?

The problem of heat losses from a fluid moving through a buried pipeline has received considerable attention. Practical applications include the trans- Alaska pipeline, as well as power plant steam and water distribution lines. Consider a steel pipe of diameter \(D\) that is used to transport oil flowing at a rate \(\dot{m}_{o}\) through a cold region. The pipe is covered with a layer of insulation of thickness \(t\) and thermal conductivity \(k_{i}\) and is buried in soil to a depth \(z\) (distance from the soil surface to the pipe centerline). Each section of pipe is of length \(L\) and extends between pumping stations in which the oil is heated to ensure low viscosity and hence low pump power requirements. The temperature of the oil entering the pipe from a pumping station and the temperature of the ground above the pipe are designated as \(T_{m, i}\) and \(T_{s}\), respectively, and are known. Consider conditions for which the oil (o) properties may be approximated as \(\rho_{o}=900 \mathrm{~kg} / \mathrm{m}^{3}, c_{p, o}=2000\) \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K}, \quad \nu_{o}=8.5 \times 10^{-4} \mathrm{~m}^{2} / \mathrm{s}, \quad k_{o}=0.140 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(P r_{o}=10^{4}\); the oil flow rate is \(\dot{m}_{o}=500 \mathrm{~kg} / \mathrm{s}\); and the pipe diameter is \(1.2 \mathrm{~m}\). (a) Expressing your results in terms of \(D, L, z, t, \dot{m}_{o}\), \(T_{m, i}\) and \(T_{s}\), as well as the appropriate oil \((o)\), insulation ( \(i\) ), and soil \((s)\) properties, obtain all the expressions needed to estimate the temperature \(T_{m \rho o}\) of the oil leaving the pipe. (b) If \(T_{s}=-40^{\circ} \mathrm{C}, T_{m, i}=120^{\circ} \mathrm{C}, t=0.15 \mathrm{~m}, k_{i}=0.05\) \(\mathrm{W} / \mathrm{m} \cdot \mathrm{K}, k_{s}=0.5 \mathrm{~W} / \mathrm{m}+\mathrm{K}, z=3 \mathrm{~m}\), and \(L=100 \mathrm{~km}\), what is the value of \(T_{m \rho}\) ? What is the total rate of heat transfer \(q\) from a section of the pipeline? (c) The operations manager wants to know the tradeoff between the burial depth of the pipe and insulation thickness on the heat loss from the pipe. Develop a graphical representation of this design information.

Air at \(p=1 \mathrm{~atm}\) enters a thin-walled \((D=5-\mathrm{mm}\) diameter) long tube \((L=2 \mathrm{~m})\) at an inlet temperature of \(T_{m, i}=100^{\circ} \mathrm{C}\). A constant heat flux is applied to the air from the tube surface. The air mass flow rate is \(\dot{m}=135 \times 10^{-6} \mathrm{~kg} / \mathrm{s}\). (a) If the tube surface temperature at the exit is \(T_{s, o}=160^{\circ} \mathrm{C}\), determine the heat rate entering the tube. Evaluate properties at \(T=400 \mathrm{~K}\). (b) If the tube length of part (a) were reduced to \(L=0.2 \mathrm{~m}\), how would flow conditions at the tube exit be affected? Would the value of the heat transfer coefficient at the tube exit be greater than, equal to, or smaller than the heat transfer coefficient for part (a)? (c) If the flow rate of part (a) were increased by a factor of 10 , would there be a difference in flow conditions at the tube exit? Would the value of the heat transfer coefficient at the tube exit be greater than, equal to, or smaller than the heat transfer coefficient for part (a)?

Fluid enters a tube with a flow rate of \(0.015 \mathrm{~kg} / \mathrm{s}\) and an inlet temperature of \(20^{\circ} \mathrm{C}\). The tube, which has a length of \(6 \mathrm{~m}\) and diameter of \(15 \mathrm{~mm}\), has a surface temperature of \(30^{\circ} \mathrm{C}\). (a) Determine the heat transfer rate to the fluid if it is water. (b) Determine the heat transfer rate for the nanofluid of Example 2.2.

Dry air at \(35^{\circ} \mathrm{C}\) and a velocity of \(10 \mathrm{~m} / \mathrm{s}\) flows over a thin-walled tube of \(20-\mathrm{mm}\) diameter and \(200-\mathrm{mm}\) length, having a fibrous coating that is water-saturated. To maintain an approximately uniform surface temperature of \(27^{\circ} \mathrm{C}\), water at a prescribed flow rate and temperature passes through the tube. (a) Considering the heat and mass transfer processes on the external surface of the tube, determine the heat rate from the tube. (b) For a flow rate of \(0.025 \mathrm{~kg} / \mathrm{s}\), determine the inlet temperature, \(T_{\mathrm{mm},}\), at which water must be supplied to the tube.

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