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Fluid enters a tube with a flow rate of \(0.015 \mathrm{~kg} / \mathrm{s}\) and an inlet temperature of \(20^{\circ} \mathrm{C}\). The tube, which has a length of \(6 \mathrm{~m}\) and diameter of \(15 \mathrm{~mm}\), has a surface temperature of \(30^{\circ} \mathrm{C}\). (a) Determine the heat transfer rate to the fluid if it is water. (b) Determine the heat transfer rate for the nanofluid of Example 2.2.

Short Answer

Expert verified
The heat transfer rates for the fluid are found by calculating the Reynolds number, Prandtl number, Nusselt number, and heat transfer coefficient using appropriate correlations. For water, the heat transfer rate, Q, is calculated using the provided temperatures and dimensions. For the nanofluid, the same steps are followed using the properties of the nanofluid given in Example 2.2. After completing these calculations, the heat transfer rate will be higher for the nanofluid due to its improved thermal conductivity.

Step by step solution

01

Calculate the Reynolds number

First, we need to find the Reynolds number (Re) for the given flow rate. The Reynolds number is defined as: \[ Re = \frac{\rho V d}{\mu} \] where 蟻 = density of the fluid, V = flow velocity, d = diameter of the tube, and 渭 = dynamic viscosity of the fluid. Given the flow rate (Q = 0.015 kg/s) and diameter (d = 15 mm), we can find flow velocity (V) by using the formula: \[ V = \frac{4Q}{\pi d^2} \] For water, we can find density and dynamic viscosity at 20掳C from standard tables. Here, we have 蟻 = 998 kg/m鲁 and 渭 = 1.002 x 10鈦宦 kg/(m.s). Now, we can calculate the Reynolds number for water.
02

Calculate the Prandtl number

Next, we need to find the Prandtl number (Pr), which is the ratio of momentum diffusivity to thermal diffusivity. Prandtl number can be calculated using the formula: \[ Pr = \frac{\mu C_p}{k} \] where C_p = specific heat capacity of the fluid, and k = thermal conductivity of the fluid. For water, we can find the specific heat capacity and thermal conductivity at 20掳C from standard tables. Here, we have C_p = 4182 J/(kg.K) and k = 0.6 W/(m.K). Now, we can calculate the Prandtl number for water.
03

Calculate the Nusselt number

For calculating the Nusselt number (Nu), we need to use appropriate correlations depending on the flow type and geometry. For a circular tube, constant surface temperature, and fully developed flow (Re > 2100), we can use the Dittus-Boelter equation: \[ Nu = 0.023 Re^{0.8} Pr^{0.4} \] Now, we can calculate the Nusselt number for water using the Reynolds and Prandtl numbers obtained earlier.
04

Calculate the heat transfer coefficient

Once we have the Nusselt number, we can find the heat transfer coefficient (h) by using the formula: \[ h = \frac{k Nu}{d} \] Now, we can calculate the heat transfer coefficient for water.
05

Calculate the heat transfer rate

Finally, we can find the heat transfer rate (Q) for the water using the following formula: \[ Q = h A \Delta T \] where A = surface area of the tube, and 螖T = temperature difference between the surface and the inlet. Given the surface temperature (T_s = 30掳C) and inlet temperature (T_in = 20掳C), we can find 螖T. A can be calculated as A = 蟺dL, where L is the tube length. Now, we can calculate the heat transfer rate for water.
06

Repeat the steps for the nanofluid

Follow the same steps (1 to 5) for the nanofluid of Example 2.2. You will need to find the properties (density, dynamic viscosity, specific heat capacity, and thermal conductivity) of the nanofluid at 20掳C to complete the calculations. After completing these steps, you will have determined the heat transfer rate for both water and the nanofluid. Note that the heat transfer rate will be higher for the nanofluid, as its higher thermal conductivity improves energy transfer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds Number
The Reynolds Number is a crucial concept in fluid dynamics that helps us determine the flow regime of a fluid. It is defined as the ratio of inertial forces to viscous forces within a fluid flow. In simpler terms, it indicates how likely the fluid flow is to be turbulent versus laminar.
Laminar flow is smooth and orderly, while turbulent flow is chaotic and mixed. The formula for Reynolds Number is given by:
  • Re = \( \frac{\rho V d}{\mu} \)
Where:
  • \(\rho\) is the density of the fluid
  • \(V\) is the flow velocity
  • \(d\) is the diameter of the tube
  • \(\mu\) is the dynamic viscosity of the fluid
Reynolds Number helps determine whether heat transfer calculations should use turbulent or laminar flow equations, influencing methods like the Dittus-Boelter equation.
Prandtl Number
The Prandtl Number is key in understanding the relationship between two types of diffusivities in a fluid: momentum and thermal. It is defined as the ratio of momentum diffusivity (kinematic viscosity) to thermal diffusivity.
It tells us how quickly momentum is diffused throughout a fluid relative to that fluid's thermal energy.
The formula for Prandtl Number is given by:
  • Pr = \( \frac{\mu C_p}{k} \)
Where:
  • \(\mu\) is the dynamic viscosity
  • \(C_p\) is the specific heat capacity
  • \(k\) is the thermal conductivity
This number plays a significant role in calculating the Nusselt Number, which in turn affects how we compute the heat transfer coefficient. Each fluid has a unique Prandtl number at a given temperature, impacting heat transfer characteristics.
Nusselt Number
The Nusselt Number is a pivotal concept when analyzing convective heat transfer. It represents the ratio of convective to conductive heat transfer across a fluid boundary. Essentially, it measures the enhancement of heat transfer through a fluid layer as opposed to pure conduction.
For flow inside tubes, this number is particularly important, as it can be calculated using various correlations based on the flow regime and geometry of the system.
A common equation for calculating the Nusselt Number in turbulent flow is given by the Dittus-Boelter equation:
  • Nu = \( 0.023 Re^{0.8} Pr^{0.4} \)
This formula correlates the Reynolds and Prandtl numbers to estimate the Nusselt Number, which thereafter allows for calculating the heat transfer coefficient.
Heat Transfer Coefficient
The Heat Transfer Coefficient is a critical parameter in determining the rate of heat transfer between a fluid and a surface. It quantifies the convective heat transfer occurring over a given surface and is greatly influenced by the flow conditions determined by the Reynolds, Prandtl, and Nusselt numbers.
The formula to find the Heat Transfer Coefficient is:
  • h = \( \frac{k Nu}{d} \)
Where:
  • \(k\) is the thermal conductivity of the fluid
  • \(Nu\) is the Nusselt number
  • \(d\) is the diameter of the tube
This coefficient is vital for calculating the actual heat transfer rate, which tells us the efficiency of heat exchange between the fluid and the tube based on the surface temperature.
Nanofluid
Nanofluids are an innovative class of fluids engineered by adding nanoparticles to traditional fluids to enhance their thermal properties. These particles can be metals, oxides, or other conductive materials, significantly increasing the thermal conductivity even in small percentages.
The use of nanofluids in heat transfer applications offers improved energy transfer rates over traditional fluids like water.
When using nanofluids in calculations, their altered physical properties, like density, viscosity, specific heat, and thermal conductivity, must be considered.
This often leads to higher heat transfer coefficients, as nanofluids are specially designed to elevate energy transfer efficiency, making them ideal for enhancing the performance of cooling systems, automotive heat exchangers, and in medical applications. Such advancements promise reduced energy consumption and heightened thermal regulation.

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Most popular questions from this chapter

Consider pressurized liquid water flowing at \(\dot{m}=0.1 \mathrm{~kg} / \mathrm{s}\) in a circular tube of diameter \(D=0.1 \mathrm{~m}\) and length \(L=6 \mathrm{~m}\). (a) If the water enters at \(T_{m, i}=500 \mathrm{~K}\) and the surface temperature of the tube is \(T_{s}=510 \mathrm{~K}\), determine the water outlet temperature \(T_{\text {m,o. }}\). (b) If the water enters at \(T_{m, i}=300 \mathrm{~K}\) and the surface temperature of the tube is \(T_{s}=310 \mathrm{~K}\), determine the water outlet temperature \(T_{\text {m, } \sigma}\). (c) If the water enters at \(T_{m, i}=300 \mathrm{~K}\) and the surface temperature of the tube is \(T_{s}=647 \mathrm{~K}\), discuss whether the flow is laminar or turbulent.

Consider a cylindrical nuclear fuel rod of length \(L\) and diameter \(D\) that is encased in a concentric tube. Pressurized water flows through the annular region between the rod and the tube at a rate \(\dot{m}\), and the outer surface of the tube is well insulated. Heat generation occurs within the fuel rod, and the volumetric generation rate is known to vary sinusoidally with distance along the rod. That is, \(\dot{q}(x)=\dot{q}_{o} \sin (\pi x / L)\), where \(\dot{q}_{o}\left(\mathrm{~W} / \mathrm{m}^{3}\right)\) is a constant. A uniform convection coefficient \(h\) may be assumed to exist between the surface of the rod and the water. (a) Obtain expressions for the local heat flux \(q^{\prime \prime}(x)\) and the total heat transfer \(q\) from the fuel rod to the water. (b) Obtain an expression for the variation of the mean temperature \(T_{m}(x)\) of the water with distance \(x\) along the tube. (c) Obtain an expression for the variation of the rod surface temperature \(T_{s}(x)\) with distance \(x\) along the tube. Develop an expression for the \(x\)-location at which this temperature is maximized.

Consider a horizontal, thin-walled circular tube of diameter \(D=0.025 \mathrm{~m}\) submerged in a container of \(n\) octadecane (paraffin), which is used to store thermal energy. As hot water flows through the tube, heat is transferred to the paraffin, converting it from the solid to liquid state at the phase change temperature of \(T_{z}=27.4^{\circ} \mathrm{C}\). The latent heat of fusion and density of paraffin are \(h_{\text {ff }}=244 \mathrm{~kJ} / \mathrm{kg}\) and \(\rho=770 \mathrm{~kg} / \mathrm{m}^{3}\), respectively, and thermophysical properties of the water may be taken as \(c_{p}=4.185 \mathrm{~kJ} / \mathrm{kg} \cdot \mathrm{K}, k=0.653 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(\mu=467 \times 10^{-6} \mathrm{~kg} / \mathrm{s} \cdot \mathrm{m}\), and \(\operatorname{Pr}=2.99\) (a) Assuming the tube surface to have a uniform temperature corresponding to that of the phase change, determine the water outlet temperature and total heat transfer rate for a water flow rate of \(0.1 \mathrm{~kg} / \mathrm{s}\) and an inlet temperature of \(60^{\circ} \mathrm{C}\). If \(H=W=0.25 \mathrm{~m}\), how long would it take to completely liquefy the paraffin, from an initial state for which all the paraffin is solid and at \(27.4^{\circ} \mathrm{C}\) ? (b) The liquefaction process can be accelerated by increasing the flow rate of the water. Compute and plot the heat rate and outlet temperature as a function of flow rate for \(0.1 \leq \dot{m} \leq 0.5 \mathrm{~kg} / \mathrm{s}\). How long would it take to melt the paraffin for \(\dot{m}=0.5 \mathrm{~kg} / \mathrm{s}\) ?

Water at \(20^{\circ} \mathrm{C}\) and a flow rate of \(0.1 \mathrm{~kg} / \mathrm{s}\) enters a heated, thin-walled tube with a diameter of \(15 \mathrm{~mm}\) and length of \(2 \mathrm{~m}\). The wall heat flux provided by the heating elements depends on the wall temperature according to the relation $$ q_{s}^{\prime \prime}(x)=q_{s, o}^{\prime \prime}\left[1+\alpha\left(T_{s}-T_{\mathrm{ref}}\right)\right] $$ where \(q_{s, \rho}^{\prime \prime}=10^{4} \mathrm{~W} / \mathrm{m}^{2}, \alpha=0.2 \mathrm{~K}^{-1}, T_{\text {ref }}=20^{\circ} \mathrm{C}\), and \(T_{s}\) is the wall temperature in \({ }^{\circ} \mathrm{C}\). Assume fully developed flow and thermal conditions with a convection coefficient of \(3000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (a) Beginning with a properly defined differential control volume in the tube, derive expressions for the variation of the water, \(T_{m}(x)\), and the wall, \(T_{s}(x)\), temperatures as a function of distance from the tube inlet. (b) Using a numerical integration scheme, calculate and plot the temperature distributions, \(T_{m}(x)\) and \(T_{s}(x)\), on the same graph. Identify and comment on the main features of the distributions. Hint: The \(I H T\) integral function \(D E R\left(T_{m}, x\right)\) can be used to perform the integration along the length of the tube. (c) Calculate the total rate of heat transfer to the water.

Atmospheric air enters the heated section of a circular tube at a flow rate of \(0.005 \mathrm{~kg} / \mathrm{s}\) and a temperature of \(20^{\circ} \mathrm{C}\). The tube is of diameter \(D=50 \mathrm{~mm}\), and fully developed conditions with \(h=25 \mathrm{~W} / \mathrm{m}^{2}+\mathrm{K}\) exist over the entire length of \(L=3 \mathrm{~m}\). (a) For the case of uniform surface heat flux at \(q_{s}^{\prime \prime}=1000 \mathrm{~W} / \mathrm{m}^{2}\), determine the total heat transfer rate \(q\) and the mean temperature of the air leaving the tube \(T_{m \rho^{-}}\)What is the value of the surface temperature at the tube inlet \(T_{s, i}\) and outlet \(T_{s, \rho}\) ? Sketch the axial variation of \(T_{s}\) and \(T_{m}\). On the same figure, also sketch (qualitatively) the axial variation of \(T_{s}\) and \(T_{m}\) for the more realistic case in which the local convection coefficient varies with \(x\). (b) If the surface heat flux varies linearly with \(x\), such that \(q_{s}^{\prime \prime}\left(\mathrm{W} / \mathrm{m}^{2}\right)=500 x(\mathrm{~m})\), what are the values of \(q, T_{m, o}, T_{s, j}\), and \(T_{s, o}\) ? Sketch the axial variation of \(T_{s}\) and \(T_{m-}\) On the same figure, also sketch (qualitatively) the axial variation of \(T_{s}\) and \(T_{m}\) for the more realistic case in which the local convection coefficient varies with \(x\). (c) For the two heating conditions of parts (a) and (b), plot the mean fluid and surface temperatures, \(T_{m}(x)\) and \(T_{s}(x)\), respectively, as functions of distance along the tube. What effect will a fourfold increase in the convection coefficient have on the temperature distributions? (d) For each type of heating process, what heat fluxes are required to achieve an air outlet temperature of \(125^{\circ} \mathrm{C}\) ? Plot the temperature distributions.

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