/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Fluid enters a tube with a flow ... [FREE SOLUTION] | 91影视

91影视

Fluid enters a tube with a flow rate of \(0.015 \mathrm{~kg} / \mathrm{s}\) and an inlet temperature of \(20^{\circ} \mathrm{C}\). The tube, which has a length of \(6 \mathrm{~m}\) and diameter of \(15 \mathrm{~mm}\), has a surface temperature of \(30^{\circ} \mathrm{C}\). (a) Determine the heat transfer rate to the fluid if it is water. (b) Determine the heat transfer rate for the nanofluid of Example 2.2.

Short Answer

Expert verified
The heat transfer rates for the fluid are found by calculating the Reynolds number, Prandtl number, Nusselt number, and heat transfer coefficient using appropriate correlations. For water, the heat transfer rate, Q, is calculated using the provided temperatures and dimensions. For the nanofluid, the same steps are followed using the properties of the nanofluid given in Example 2.2. After completing these calculations, the heat transfer rate will be higher for the nanofluid due to its improved thermal conductivity.

Step by step solution

01

Calculate the Reynolds number

First, we need to find the Reynolds number (Re) for the given flow rate. The Reynolds number is defined as: \[ Re = \frac{\rho V d}{\mu} \] where 蟻 = density of the fluid, V = flow velocity, d = diameter of the tube, and 渭 = dynamic viscosity of the fluid. Given the flow rate (Q = 0.015 kg/s) and diameter (d = 15 mm), we can find flow velocity (V) by using the formula: \[ V = \frac{4Q}{\pi d^2} \] For water, we can find density and dynamic viscosity at 20掳C from standard tables. Here, we have 蟻 = 998 kg/m鲁 and 渭 = 1.002 x 10鈦宦 kg/(m.s). Now, we can calculate the Reynolds number for water.
02

Calculate the Prandtl number

Next, we need to find the Prandtl number (Pr), which is the ratio of momentum diffusivity to thermal diffusivity. Prandtl number can be calculated using the formula: \[ Pr = \frac{\mu C_p}{k} \] where C_p = specific heat capacity of the fluid, and k = thermal conductivity of the fluid. For water, we can find the specific heat capacity and thermal conductivity at 20掳C from standard tables. Here, we have C_p = 4182 J/(kg.K) and k = 0.6 W/(m.K). Now, we can calculate the Prandtl number for water.
03

Calculate the Nusselt number

For calculating the Nusselt number (Nu), we need to use appropriate correlations depending on the flow type and geometry. For a circular tube, constant surface temperature, and fully developed flow (Re > 2100), we can use the Dittus-Boelter equation: \[ Nu = 0.023 Re^{0.8} Pr^{0.4} \] Now, we can calculate the Nusselt number for water using the Reynolds and Prandtl numbers obtained earlier.
04

Calculate the heat transfer coefficient

Once we have the Nusselt number, we can find the heat transfer coefficient (h) by using the formula: \[ h = \frac{k Nu}{d} \] Now, we can calculate the heat transfer coefficient for water.
05

Calculate the heat transfer rate

Finally, we can find the heat transfer rate (Q) for the water using the following formula: \[ Q = h A \Delta T \] where A = surface area of the tube, and 螖T = temperature difference between the surface and the inlet. Given the surface temperature (T_s = 30掳C) and inlet temperature (T_in = 20掳C), we can find 螖T. A can be calculated as A = 蟺dL, where L is the tube length. Now, we can calculate the heat transfer rate for water.
06

Repeat the steps for the nanofluid

Follow the same steps (1 to 5) for the nanofluid of Example 2.2. You will need to find the properties (density, dynamic viscosity, specific heat capacity, and thermal conductivity) of the nanofluid at 20掳C to complete the calculations. After completing these steps, you will have determined the heat transfer rate for both water and the nanofluid. Note that the heat transfer rate will be higher for the nanofluid, as its higher thermal conductivity improves energy transfer.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds Number
The Reynolds Number is a crucial concept in fluid dynamics that helps us determine the flow regime of a fluid. It is defined as the ratio of inertial forces to viscous forces within a fluid flow. In simpler terms, it indicates how likely the fluid flow is to be turbulent versus laminar.
Laminar flow is smooth and orderly, while turbulent flow is chaotic and mixed. The formula for Reynolds Number is given by:
  • Re = \( \frac{\rho V d}{\mu} \)
Where:
  • \(\rho\) is the density of the fluid
  • \(V\) is the flow velocity
  • \(d\) is the diameter of the tube
  • \(\mu\) is the dynamic viscosity of the fluid
Reynolds Number helps determine whether heat transfer calculations should use turbulent or laminar flow equations, influencing methods like the Dittus-Boelter equation.
Prandtl Number
The Prandtl Number is key in understanding the relationship between two types of diffusivities in a fluid: momentum and thermal. It is defined as the ratio of momentum diffusivity (kinematic viscosity) to thermal diffusivity.
It tells us how quickly momentum is diffused throughout a fluid relative to that fluid's thermal energy.
The formula for Prandtl Number is given by:
  • Pr = \( \frac{\mu C_p}{k} \)
Where:
  • \(\mu\) is the dynamic viscosity
  • \(C_p\) is the specific heat capacity
  • \(k\) is the thermal conductivity
This number plays a significant role in calculating the Nusselt Number, which in turn affects how we compute the heat transfer coefficient. Each fluid has a unique Prandtl number at a given temperature, impacting heat transfer characteristics.
Nusselt Number
The Nusselt Number is a pivotal concept when analyzing convective heat transfer. It represents the ratio of convective to conductive heat transfer across a fluid boundary. Essentially, it measures the enhancement of heat transfer through a fluid layer as opposed to pure conduction.
For flow inside tubes, this number is particularly important, as it can be calculated using various correlations based on the flow regime and geometry of the system.
A common equation for calculating the Nusselt Number in turbulent flow is given by the Dittus-Boelter equation:
  • Nu = \( 0.023 Re^{0.8} Pr^{0.4} \)
This formula correlates the Reynolds and Prandtl numbers to estimate the Nusselt Number, which thereafter allows for calculating the heat transfer coefficient.
Heat Transfer Coefficient
The Heat Transfer Coefficient is a critical parameter in determining the rate of heat transfer between a fluid and a surface. It quantifies the convective heat transfer occurring over a given surface and is greatly influenced by the flow conditions determined by the Reynolds, Prandtl, and Nusselt numbers.
The formula to find the Heat Transfer Coefficient is:
  • h = \( \frac{k Nu}{d} \)
Where:
  • \(k\) is the thermal conductivity of the fluid
  • \(Nu\) is the Nusselt number
  • \(d\) is the diameter of the tube
This coefficient is vital for calculating the actual heat transfer rate, which tells us the efficiency of heat exchange between the fluid and the tube based on the surface temperature.
Nanofluid
Nanofluids are an innovative class of fluids engineered by adding nanoparticles to traditional fluids to enhance their thermal properties. These particles can be metals, oxides, or other conductive materials, significantly increasing the thermal conductivity even in small percentages.
The use of nanofluids in heat transfer applications offers improved energy transfer rates over traditional fluids like water.
When using nanofluids in calculations, their altered physical properties, like density, viscosity, specific heat, and thermal conductivity, must be considered.
This often leads to higher heat transfer coefficients, as nanofluids are specially designed to elevate energy transfer efficiency, making them ideal for enhancing the performance of cooling systems, automotive heat exchangers, and in medical applications. Such advancements promise reduced energy consumption and heightened thermal regulation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Engine oil flows at a rate of \(1 \mathrm{~kg} / \mathrm{s}\) through a \(5-\mathrm{mm}-\) diameter straight tube. The oil has an inlet temperature of \(45^{\circ} \mathrm{C}\) and it is desired to heat the oil to a mean temperature of \(80^{\circ} \mathrm{C}\) at the exit of the tube. The surface of the tube is maintained at \(150^{\circ} \mathrm{C}\). Determine the required length of the tube. Hint: Calculate the Reynolds numbers at the entrance and exit of the tube before proceeding with your analysis.

At a particular axial station, velocity and temperature profiles for laminar flow in a parallel plate channel have the form $$ \begin{aligned} &u(y)=0.75\left[1-\left(y / y_{o}\right)^{2}\right] \\ &T(y)=5.0+95.66\left(y / y_{o}\right)^{2}-47.83\left(y / y_{o}\right)^{4} \end{aligned} $$ with units of \(\mathrm{m} / \mathrm{s}\) and \({ }^{\circ} \mathrm{C}\), respectively. Determine corresponding values of the mean velocity, \(u_{m}\), and mean (or bulk) temperature, \(T_{m}\). Plot the velocity and temperature distributions. Do your values of \(u_{m}\) and \(T_{m}\) appear reasonable?

In the final stages of production, a pharmaceutical is sterilized by heating it from 25 to \(75^{\circ} \mathrm{C}\) as it moves at \(0.2 \mathrm{~m} / \mathrm{s}\) through a straight thin-walled stainless steel tube of \(12.7=\mathrm{mm}\) diameter. A uniform heat flux is maintained by an electric resistance heater wrapped around the outer surface of the tube. If the tube is \(10 \mathrm{~m}\) long, what is the required heat flux? If fluid enters the tube with a fully developed velocity profile and a uniform temperature profile, what is the surface temperature at the tube exit and at a distance of \(0.5 \mathrm{~m}\) from the entrance? Fluid properties may be approximated as \(\rho=\) \(1000 \mathrm{~kg} / \mathrm{m}^{3}, c_{p}=4000 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, m=2 \times 10^{-3} \mathrm{~kg} / \mathrm{s} \cdot \mathrm{m}\), \(k=0.8 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), and \(P r=10\).

Fluid enters a thin-walled tube of \(5-\mathrm{mm}\) diameter and \(2-\mathrm{m}\) length with a flow rate of \(0.04 \mathrm{~kg} / \mathrm{s}\) and a temperature of \(T_{m, i}=85^{\circ} \mathrm{C}\). The tube surface is maintained at a temperature of \(T_{s}=25^{\circ} \mathrm{C}\), and for this operating condition, the outlet temperature is \(T_{m, o}=31.1^{\circ} \mathrm{C}\). What is the outlet temperature if the flow rate is doubled? Fully developed, turbulent flow may be assumed to exist in both cases, and the fluid properties may be assumed to be independent of temperature.

Water at \(300 \mathrm{~K}\) and a flow rate of \(5 \mathrm{~kg} / \mathrm{s}\) enters a black, thin-walled tube, which passes through a large furnace whose walls and air are at a temperature of \(700 \mathrm{~K}\). The diameter and length of the tube are \(0.25 \mathrm{~m}\) and \(8 \mathrm{~m}\), respectively. Convection coefficients associated with water flow through the tube and airflow over the tube are \(300 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(50 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. (a) Write an expression for the linearized radiation coefficient corresponding to radiation exchange between the outer surface of the pipe and the furnace walls. Explain how to calculate this coefficient if the surface temperature of the tube is represented by the arithmetic mean of its inlet and outlet values. (b) Determine the outlet temperature of the water, \(T_{m, o^{\circ}}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.