/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 The problem of heat losses from ... [FREE SOLUTION] | 91Ó°ÊÓ

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The problem of heat losses from a fluid moving through a buried pipeline has received considerable attention. Practical applications include the trans- Alaska pipeline, as well as power plant steam and water distribution lines. Consider a steel pipe of diameter \(D\) that is used to transport oil flowing at a rate \(\dot{m}_{o}\) through a cold region. The pipe is covered with a layer of insulation of thickness \(t\) and thermal conductivity \(k_{i}\) and is buried in soil to a depth \(z\) (distance from the soil surface to the pipe centerline). Each section of pipe is of length \(L\) and extends between pumping stations in which the oil is heated to ensure low viscosity and hence low pump power requirements. The temperature of the oil entering the pipe from a pumping station and the temperature of the ground above the pipe are designated as \(T_{m, i}\) and \(T_{s}\), respectively, and are known. Consider conditions for which the oil (o) properties may be approximated as \(\rho_{o}=900 \mathrm{~kg} / \mathrm{m}^{3}, c_{p, o}=2000\) \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K}, \quad \nu_{o}=8.5 \times 10^{-4} \mathrm{~m}^{2} / \mathrm{s}, \quad k_{o}=0.140 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(P r_{o}=10^{4}\); the oil flow rate is \(\dot{m}_{o}=500 \mathrm{~kg} / \mathrm{s}\); and the pipe diameter is \(1.2 \mathrm{~m}\). (a) Expressing your results in terms of \(D, L, z, t, \dot{m}_{o}\), \(T_{m, i}\) and \(T_{s}\), as well as the appropriate oil \((o)\), insulation ( \(i\) ), and soil \((s)\) properties, obtain all the expressions needed to estimate the temperature \(T_{m \rho o}\) of the oil leaving the pipe. (b) If \(T_{s}=-40^{\circ} \mathrm{C}, T_{m, i}=120^{\circ} \mathrm{C}, t=0.15 \mathrm{~m}, k_{i}=0.05\) \(\mathrm{W} / \mathrm{m} \cdot \mathrm{K}, k_{s}=0.5 \mathrm{~W} / \mathrm{m}+\mathrm{K}, z=3 \mathrm{~m}\), and \(L=100 \mathrm{~km}\), what is the value of \(T_{m \rho}\) ? What is the total rate of heat transfer \(q\) from a section of the pipeline? (c) The operations manager wants to know the tradeoff between the burial depth of the pipe and insulation thickness on the heat loss from the pipe. Develop a graphical representation of this design information.

Short Answer

Expert verified
In summary, to estimate the temperature of the oil leaving the pipe, we first calculated the heat transfer per unit length (\(q'\)) using the given parameters and properties. Then, we found the temperature difference (\(\Delta T\)) between the entering and leaving oil based on the energy loss and heat capacity. Finally, we calculated the oil temperature leaving the pipe as \(T_{m \rho o} = T_{m, i} - \Delta T = 118.97^{\circ} \mathrm{C}\). The total rate of heat transfer from a section of the pipeline was found to be \(q = 1,032,000 \ \mathrm{W}\). A graphical representation of the tradeoff between burial depth and insulation thickness on heat loss can be created using a contour plot or heatmap by plotting \(q'\) values as a function of \(z\) and \(t\). This graph would help in making optimal design decisions considering practical constraints and costs.

Step by step solution

01

a) Develop the expressions to estimate the temperature of the oil leaving the pipe

First, we have to find an expression for the heat transfer per unit length (\(q'\)) from the pipeline. The formula for heat transfer per unit length in a buried insulated pipe can be expressed as: \[q' = \frac{2 \pi k_i}{\ln (\frac{D + 2t}{D})} \cdot (T_{m, i} - T_s)\] Next, let's find the temperature of the oil leaving the pipe. As the oil flows through the pipe, heat will be lost to the surroundings. The temperature difference between the oil entering and leaving the pipe is the energy loss divided by the heat capacity of the oil: \[ \Delta T = \frac{q' \cdot L}{\dot{m}_{o} \cdot c_{p, o}} \] The temperature of the oil leaving the pipe can be calculated as: \[T_{m \rho o} = T_{m, i} - \Delta T\]
02

b) Calculate the oil temperature leaving the pipe and the total rate of heat transfer

Using the given values: $T_{s}=-40^{\circ} \mathrm{C}, T_{m, i}=120^{\circ} \mathrm{C}, t=0.15 \mathrm{~m}, k_{i}=0.05\( \)\mathrm{W} / \mathrm{m} \cdot \mathrm{K}, k_{s}=0.5 \mathrm{~W} / \mathrm{m}+\mathrm{K}, z=3 \mathrm{~m}\(, and \)L=100 \mathrm{~km}\(, let us first calculate \)q'$: \[q' = \frac{2 \pi (0.05)}{\ln (\frac{1.2 + 2(0.15)}{1.2})} \cdot (120 - (-40)) = 10.32 \ \mathrm{W/m}\] Next, we calculate \(\Delta T\): \[ \Delta T = \frac{10.32 \cdot 100000}{500 \cdot 2000} = 1.03^{\circ} \mathrm{C}\] Now, we can find the temperature of the oil leaving the pipe: \[T_{m \rho o} = 120 - 1.03 = 118.97^{\circ} \mathrm{C}\] Finally, we can find the total rate of heat transfer from a section of the pipeline: \[q = q' \cdot L = 10.32 \cdot 100000 = 1,032,000 \ \mathrm{W}\]
03

c) Develop a graphical representation of the tradeoff between burial depth and insulation thickness

To generate a graphical representation of the tradeoff between burial depth (\(z\)) and insulation thickness (\(t\)) on the heat loss from the pipe, one can plot heat transfer per unit length (\(q'\)) as a function of \(z\) and \(t\). Typically, we can vary \(t\) from \(0\) to some maximum value (like 0.5m) and \(z\) from \(0\) to a maximum depth (like 10m). For each combination of \(z\) and \(t\), we can calculate \(q'\) using the formula in (a), and represent it through a contour plot or a heatmap. This would require software tools like Excel, Matlab or Python. The graph will show that as the insulation thickness and the burial depth increase, the heat loss from the pipeline will decrease. However, there will be a point where increasing either factor will have diminishing returns and an optimal trade-off will need to be made considering practical constraints and costs.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is a fundamental concept in physics where energy is exchanged between physical systems, typically due to a temperature difference. In the context of pipelines, heat transfer occurs between the fluid inside the pipe (such as oil) and the surrounding environment. This process can result in heat loss or gain, depending on the respective temperatures.

There are three main modes of heat transfer: conduction, convection, and radiation. In the case of buried pipelines, conduction is the most relevant mechanism, especially through the pipe material and insulation. Conduction occurs when there is a direct transfer of energy from the hotter to the cooler parts through a medium. This process can lead to significant energy loss if not properly managed, which is detrimental when transporting fluids that need to maintain a certain temperature.

In practice, preventing this heat transfer is achieved by adding a layer of insulation around the pipe, effectively reducing the rate of heat loss through the walls of the pipe to the colder ground surrounding it. The effectiveness of this insulation and the overall rate of heat loss depend on factors such as the insulation material, its thickness, and thermal properties, as well as the temperature gradient between the fluid and the environment.
Insulated Buried Pipelines
Insulated buried pipelines are a critical infrastructure for transporting fluids across varying terrain and climatic conditions. Insulation's primary objective is to minimize heat transfer between the fluid within the pipe and its surroundings. This is particularly important for hot fluids that need to be kept at high temperatures to prevent viscosity increases, which can lead to higher pump power requirements and operational inefficiencies.

For an insulated pipeline, the design must consider multiple factors to optimize thermal performance. These factors include the insulation type, thickness, and whether additional protective layers are needed. For example, a pipeline transporting oil through a cold region, such as in the exercise, requires careful consideration to prevent the oil from losing heat to the freezing ground.

The performance of an insulated buried pipeline is assessed by its ability to maintain the desired temperature of the fluid over the course of transportation. This involves complex calculations that consider the interaction between the material properties of the pipeline, the insulation, the fluid, and the surrounding soil. These calculations determine the temperature profiles along the pipeline and ultimately inform the design and operational decisions to ensure energy efficiency and fluid integrity during transport.
Thermal Conductivity
Thermal conductivity, represented as \(k\), is a material property that quantifies its ability to conduct heat. It is typically measured in watts per meter-kelvin (\(\mathrm{W/m\cdot K}\)). Materials with higher thermal conductivity can transfer heat more efficiently, making them suitable for applications where quick heat dissipation is desired, such as in heat sinks and cooling systems.

Conversely, materials with low thermal conductivity serve as good insulators, as they hinder heat flow. This property is particularly important for the design of pipeline insulation, as seen in the textbook example. The type of insulation material and its thermal conductivity directly impact the heat losses experienced by a fluid traveling through a pipeline. A lower value of \(k_i\), the thermal conductivity of the insulation, translates to better insulating performance and less heat being lost from the pipe to the surroundings.

Understanding the thermal conductivity of different materials is integral for engineers to design effective insulation systems in pipelines. It allows them to calculate the expected heat loss and determine the required thickness of the insulation to achieve certain energy efficiency targets. By doing so, they ensure not only that the fluid within maintains its temperature but also that the heat loss does not lead to wasted energy and increased operational costs.

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Most popular questions from this chapter

Cooling water flows through the \(25.4-\mathrm{mm}\)-diameter thin-walled tubes of a steam condenser at \(1 \mathrm{~m} / \mathrm{s}\), and a surface temperature of \(350 \mathrm{~K}\) is maintained by the condensing steam. The water inlet temperature is \(290 \mathrm{~K}\), and the tubes are \(5 \mathrm{~m}\) long. (a) What is the water outlet temperature? Evaluate water properties at an assumed average mean temperature, \(\bar{T}_{\mathrm{m}}=300 \mathrm{~K}\). (b) Was the assumed value for \(\bar{T}_{m}\) reasonable? If not, repeat the calculation using properties evaluated at a more appropriate temperature. (c) A range of tube lengths from 4 to \(7 \mathrm{~m}\) is available to the engineer designing this condenser. Generate a plot to show what coolant mean velocities are possible if the water outlet temperature is to remain at the value found for part (b). All other conditions remain the same.

Many of the solid surfaces for which values of the thermal and momentum accommodation coefficients have been measured are quite different from those used in micro- and nanodevices. Plot the Nusselt number \(N u_{D}\) associated with fully developed laminar flow with constant surface heat flux versus tube diameter for \(1 \mu \mathrm{m} \leq D \leq 1 \mathrm{~mm}\) and (i) \(\alpha_{s}=1, \alpha_{p}=1\), (ii) \(\alpha_{t}=0.1, \alpha_{p}=0.1\), (iii) \(\alpha_{t}=1, \alpha_{p}=0.1\), and (iv) \(\alpha_{t}=0.1, \alpha_{p}=1\). For tubes of what diameter do the accommodation coefficients begin to influence convection heat transfer? For which combination of \(\alpha_{t}\) and \(\alpha_{p}\) does the Nusselt number exhibit the least sensitivity to changes in the diameter of the tube? Which combination results in Nusselt numbers greater than the conventional fully developed laminar value for constant heat flux conditions, \(N u_{D}=4.36\) ? Which combination is associated with the smallest Nusselt numbers? What can you say about the ability to predict convection heat transfer coefficients in a small-scale device if the accommodation coefficients are not known for material from which the device is fabricated? Use properties of air at atmospheric pressure and \(T=300 \mathrm{~K}\).

Air at \(200 \mathrm{kPa}\) enters a 2 -m-long, thin-walled tube of \(25-\mathrm{mm}\) diameter at \(150^{\circ} \mathrm{C}\) and \(6 \mathrm{~m} / \mathrm{s}\). Steam at 20 bars condenses on the outer surface. (a) Determine the outlet temperature and pressure drop of the air, as well as the rate of heat transfer to the air. (b) Calculate the parameters of part (a) if the pressure of the air is doubled.

The air passage for cooling a gas turbine vane can be approximated as a tube of \(3-\mathrm{mm}\) diameter and \(75-\mathrm{mm}\) length. The operating temperature of the vane is \(650^{\circ} \mathrm{C}\), and air enters the tube at \(427^{\circ} \mathrm{C}\). (a) For an airflow rate of \(0.18 \mathrm{~kg} / \mathrm{h}\), calculate the air outlet temperature and the heat removed from the vane. (b) Generate a plot of the air outlet temperature as a function of flow rate for \(0.1 \leq \dot{m} \leq 0.6 \mathrm{~kg} / \mathrm{h}\). Compare this result with those for vanes having 2 - and 4-mm-diameter tubes, with all other conditions remaining the same.

Consider air flowing in a small-diameter steel tube. Graph the Nusselt number associated with fully developed laminar flow with constant surface heat flux for tube diameters ranging from \(1 \mu \mathrm{m} \leq D \leq 1 \mathrm{~mm}\). Evaluate air properties at \(T=350 \mathrm{~K}\) and atmospheric pressure. The thermal and momentum accommodation coefficients are \(\alpha_{t}=0.92\) and \(\alpha_{p}=0.87\), respectively. Compare the Nusselt number you calculate to the value provided in Equation \(8.53, N u_{D}=4.36\).

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