/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Consider airflow over a flat pla... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider airflow over a flat plate of length \(L=1 \mathrm{~m}\) under conditions for which transition occurs at \(x_{c}=0.5 \mathrm{~m}\) based on the critical Reynolds number, \(R e_{x, c}=5 \times 10^{5}\). (a) Evaluating the thermophysical properties of air at \(350 \mathrm{~K}\), determine the air velocity. (b) In the laminar and turbulent regions, the local convection coefficients are, respectively, \(h_{\text {lam }}(x)=C_{\text {lam }} x^{-05}\) and \(h_{\text {marb }}=C_{\text {marb }} x^{-0.2}\) where, at \(T=350 \mathrm{~K}, C_{\text {lum }}=8.845 \mathrm{~W} / \mathrm{m}^{3 / 2} \cdot \mathrm{K}, C_{\text {tub }}=\) \(49.75 \mathrm{~W} / \mathrm{m}^{1.8} \cdot \mathrm{K}\), and \(x\) has units of \(\mathrm{m}\). Develop an expression for the average convection coefficient, \(\bar{h}_{\mathrm{hm}}(x)\), as a function of distance from the leading edge, \(x\), for the laminar region, \(0 \leq x \leq x_{x}\). (c) Develop an expression for the average convection coefficient, \(\bar{h}_{\text {art }}(x)\), as a function of distance from the leading edge, \(x\), for the turbulent region, \(x_{c} \leq x \leq L\). (d) On the same coordinates, plot the local and average convection coefficients, \(h_{x}\) and \(\bar{h}_{x}\), respectively, as a function of \(x\) for \(0 \leq x \leq L\).

Short Answer

Expert verified
The air velocity is found to be \(V_c = 9.375 \mathrm{~m/s}\). The expressions for the average convection coefficient in the laminar and turbulent regions are, respectively, \(\bar{h}_{lam}(x) = \frac{2(8.845)}{\sqrt{x}} \mathrm{W/m^2 \cdot K}\) and \(\bar{h}_{turb}(x) = \frac{5(49.75)}{4(x - 0.5)^{0.8}}(x^{0.8} - 0.5^{0.8}) \mathrm{W/m^2 \cdot K}\). To plot the local and average convection coefficients as a function of distance from the leading edge, use a graph plotting software with the given expressions, considering the distance range \(0\leq x\leq L\), where \( L = 1\mathrm{~m}\).

Step by step solution

01

Calculate the air velocity

At the critical point, we can use the equation: \(Re_{x, c} = \frac{\rho V_c x_c}{\mu}\) given that \(Re_{x, c} = 5 \times 10^5\), \(x_c = 0.5 \mathrm{~m}\) and we evaluate the thermophysical properties of air at \(350 \mathrm{~K}\), we have: \(V_c = \frac{Re_{x, c} \mu}{\rho x_c}\) Using the properties of air at 350 K: \(\rho = 1.177 \mathrm{~kg/m^3}\), and \(\mu = 2.21 \times 10^{-5} \mathrm{Pa \cdot s}\), the air velocity can be calculated as: \(V_c = \frac{5 \times 10^5 \times 2.21 \times 10^{-5} \mathrm{Pa \cdot s}}{1.177 \mathrm{~kg/m^3} \times 0.5 \mathrm{~m}}\) Upon calculating, we get: \(V_c = 9.375 \mathrm{~m/s}\) #b) Develop an expression for the average convection coefficient in the laminar region#
02

Average convection coefficient in the laminar region

In the laminar region, we can integrate the local convection coefficient equation to find the average convection coefficient, as follows: \(\bar{h}_{lam}(x) = \frac{1}{x} \int_{0}^{x}C_{lam}x'^{-0.5}dx'\) After integrating, we get the expression for the average convection coefficient in the laminar region as: \(\bar{h}_{lam}(x) = \frac{2C_{lam}}{\sqrt{x}}\) We are given \(C_{lam} = 8.845 \mathrm{W/m^{3/2} \cdot K}\), so the equation becomes: \(\bar{h}_{lam}(x) = \frac{2(8.845)}{\sqrt{x}} \mathrm{W/m^2 \cdot K}\) #c) Develop an expression for the average convection coefficient in the turbulent region#
03

Average convection coefficient in the turbulent region

In the turbulent region, we can integrate the local convection coefficient equation to find the average convection coefficient, as follows: \(\bar{h}_{turb}(x) = \frac{1}{x - x_c} \int_{x_c}^{x}C_{turb}x'^{-0.2}dx'\) After integrating, we get the expression for the average convection coefficient in the turbulent region as: \(\bar{h}_{turb}(x) = \frac{5C_{turb}}{4(x - x_c)^{0.8}}(x^{0.8} - x_c^{0.8})\) We are given \(C_{turb} = 49.75 \mathrm{W/m^{1.8} \cdot K}\) and \(x_c = 0.5 \mathrm{m}\), so the equation becomes: \(\bar{h}_{turb}(x) = \frac{5(49.75)}{4(x - 0.5)^{0.8}}(x^{0.8} - 0.5^{0.8}) \mathrm{W/m^2 \cdot K}\) #d) Plot the local and average convection coefficients as a function of distance from the leading edge#
04

Plot the local and average convection coefficients as a function of distance

We have the following expressions: 1. \(h_{lam}(x) = C_{lam} x^{-0.5}\) 2. \(h_{turb}(x) = C_{turb} x^{-0.2}\) 3. \(\bar{h}_{lam}(x) = \frac{2C_{lam}}{\sqrt{x}}\) 4. \(\bar{h}_{turb}(x) = \frac{5C_{turb}}{4(x - x_c)^{0.8}}(x^{0.8} - x_c^{0.8})\) Use any graph plotting software or calculator to plot these expressions in the same graph considering the distance range \(0\leq x\leq L\), where \( L = 1\mathrm{~m}\). This will give you the graphical representation of local and average convection coefficients as a function of distance from the leading edge.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reynolds Number
The concept of Reynolds Number is fundamental in fluid dynamics and helps in predicting flow patterns in different fluid flow situations. Reynolds Number, often denoted by \( Re \), is calculated using the formula:
  • \( Re = \frac{\rho VD}{\mu} \)
where:- \( \rho \) is the fluid density- \( V \) is the velocity of the fluid- \( D \) is the characteristic length (like diameter or length of the plate)- \( \mu \) is the dynamic viscosity of the fluid.
Reynolds Number helps us determine whether the flow will be laminar or turbulent. When \( Re \) is below about 2000 for pipe flow (and around 5 x 10^5 for flow over a flat plate), the flow is generally laminar. Above this, the flow tends to become turbulent. It's a dimensionless quantity that provides a powerful way to relate all these factors involved in the flow. Understanding the Reynolds Number is critical in engineering to predict how fluids will behave across surfaces and obstacles.
Laminar Flow
Laminar Flow refers to a type of fluid motion characterized by smooth, parallel layers of fluid that flow in the same direction, often with little to no disruption between them. This type of flow occurs when the Reynolds Number is below a critical threshold, typically \( Re < 2000 \) for flow in pipes.
Several notable characteristics define laminar flow:
  • The flow is steady and layers do not mix.
  • Velocity profile is usually parabolic or linear, depending on the system.
  • Energy loss in the system is minimal when compared with turbulent flow.
In the context of a flat plate, the transition from laminar to turbulent flow happens at a critical Reynolds Number, which affects the convection coefficients and hence the thermal performance. Laminar flow on a flat plate begins at the leading edge and transitions to turbulent as the Reynolds Number increases past the threshold, changing the nature of heat transfer across the plate.
Turbulent Flow
Turbulent Flow is a complex flow regime characterized by chaotic and irregular fluid motion, where layers of fluid mix thoroughly. This type of flow typically occurs when the Reynolds Number is higher than 4000. Here's what to know about turbulent flow:
  • Flow is erratic, with rapid fluctuations in velocity and pressure.
  • Mixes layers and increases the rate of momentum, heat, and mass transfer.
  • Typically leads to higher friction losses compared to laminar flow.
When air moves quickly over a flat plate, it can transition from laminar to turbulent flow past a certain distance, as depicted by a critical Reynolds Number. In turbulent flow regime, local convection coefficients are influenced significantly, often increasing the heat transfer to a higher level due to the improved mixing efficiency. Understanding turbulent flow allows engineers to resolve many practical fluid dynamics challenges in aerodynamics and hydrodynamics, optimizing designs for performance and safety.

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Most popular questions from this chapter

The naphthalene sublimation technique involves the use of a mass transfer experiment coupled with an analysis based on the heat and mass transfer analogy to obtain local or average convection heat transfer coefficients for complex surface geometries. A coating of naphthalene, which is a volatile solid at room temperature, is applied to the surface and is then subjected to airflow in a wind tunnel. Alternatively, solid objects may be cast from liquid naphthalene. Over a designated time interval, \(\Delta t\), there is a discernible loss of naphthalene due to sublimation, and by measuring the surface recession at locations of interest or the mass loss of the sample, local or average mass transfer coefficients may be determined. Consider a rectangular rod of naphthalene exposed to air in cross flow at \(V=10 \mathrm{~m} / \mathrm{s}, T_{\mathrm{s}}=300 \mathrm{~K}\), as in Problem 6.10, except now \(c=10 \mathrm{~mm}\) and \(d=30 \mathrm{~mm}\). Determine the change in mass of the \(L=500\)-mm-long rod over a time period of \(\Delta t=30 \mathrm{~min}\). Naphthalene has a molecular weight of \(M_{\mathrm{A}}=128.16 \mathrm{~kg} / \mathrm{kmol}\), and its solid-vapor saturation pressure at \(27^{\circ} \mathrm{C}\) and \(1 \mathrm{ltm}\) is \(p_{\text {A, } a t}=1.33 \times 10^{-4}\) bar.

The defroster of an automobile functions by discharging warm air on the inner surface of the windshield. To prevent condensation of water vapor on the surface, the temperature of the air and the surface convection coefficient \(\left(T_{\infty, j}, \overline{h_{i}}\right)\) must be large enough to maintain a surface temperature \(T_{s i}\) that is at least as high as the dewpoint \(\left(T_{s, i} \geq T_{d \mathrm{p}}\right)\). Consider a windshield of length \(L=800 \mathrm{~mm}\) and thickness \(t=6 \mathrm{~mm}\) and driving conditions for which the vehicle moves at a velocity of \(V=70 \mathrm{mph}\) in ambient air at \(T_{\infty \rho}=-15^{\circ} \mathrm{C}\). From laboratory experiments performed on a model of the vehicle, the average convection coefficient on the outer surface of the windshield is known to be correlated by an expression of the form \(\overline{N_{L}}=0.030 \operatorname{Re}_{L}^{0.8} \operatorname{Pr}^{1 / 3}\), where \(R e_{L}=V L \nu\). Air properties may be approximated as \(k=0.023 \mathrm{~W} / \mathrm{m}=\mathrm{K}\), \(v=12.5 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\), and \(\operatorname{Pr}=0.71\). If \(T_{d p}=10^{\circ} \mathrm{C}\) and \(T_{m, j}=50^{\circ} \mathrm{C}\), what is the smallest value of \(\bar{h}_{j}\) required to prevent condensation on the inner surface?

Experiments have shown that the transition from laminar to turbulent conditions for flow normal to the axis of a long cylinder occurs at a critical Reynolds number of \(R e_{D,} \approx 2 \times 10^{5}\), where \(D\) is the cylinder diameter. Moreover, the transition from incompressible to compressible flow occurs at a critical Mach number of \(M a_{e}=0.3\). For air at a pressure of \(p=1 \mathrm{~atm}\) and temperature \(T=27^{\circ} \mathrm{C}\), determine the critical cylinder diameter \(D_{c}\) below which, if the flow is turbulent, compressibility effects are likely to be important.

An object of irregular shape has a characteristic length of \(L=1 \mathrm{~m}\) and is maintained at a uniform surface temperature of \(T_{s}=400 \mathrm{~K}\). When placed in atmospheric air at a temperature of \(T_{x}=300 \mathrm{~K}\) and moving with a velocity of \(V=100 \mathrm{~m} / \mathrm{s}\), the average heat flux from the surface to the air is \(20,000 \mathrm{~W} / \mathrm{m}^{2}\). If a second object of the same shape, but with a characteristic length of \(L=5 \mathrm{~m}\), is maintained at a surface temperature of \(T_{s}=400 \mathrm{~K}\) and is placed in atmospheric air at \(T_{\infty}=300 \mathrm{~K}\), what will the value of the average convection coefficient be if the air velocity is \(V=20 \mathrm{~m} / \mathrm{s}\) ?

A fan that can provide air speeds up to \(50 \mathrm{~m} / \mathrm{s}\) is to be used in a low-speed wind tunnel with atmospheric air at \(25^{\circ} \mathrm{C}\). If one wishes to use the wind tunnel to study flatplate boundary layer behavior up to Reynolds numbers of \(R e_{x}=10^{8}\), what is the minimum plate length that should be used? At what distance from the leading edge would transition occur if the critical Reynolds number were \(R e_{x, c}=5 \times 10^{5}\) ?

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