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Experiments have shown that the transition from laminar to turbulent conditions for flow normal to the axis of a long cylinder occurs at a critical Reynolds number of \(R e_{D,} \approx 2 \times 10^{5}\), where \(D\) is the cylinder diameter. Moreover, the transition from incompressible to compressible flow occurs at a critical Mach number of \(M a_{e}=0.3\). For air at a pressure of \(p=1 \mathrm{~atm}\) and temperature \(T=27^{\circ} \mathrm{C}\), determine the critical cylinder diameter \(D_{c}\) below which, if the flow is turbulent, compressibility effects are likely to be important.

Short Answer

Expert verified
The critical cylinder diameter \(D_c\) below which, if the flow is turbulent, compressibility effects are likely to be important can be calculated by following these steps: 1. Determine the air density (\(\rho\)) and dynamic viscosity (\(\mu\)) at the given temperature and pressure using the ideal gas law and Sutherland's formula. 2. Calculate the flow velocity at the critical Reynolds number (\(Re_{D,c} = 2\times10^5\)) as a function of cylinder diameter. 3. Calculate the speed of sound (\(a\)) in the medium using the ideal gas equation for an ideal gas. 4. Calculate the critical cylinder diameter (\(D_c\)) where compressibility effects become important using the relation \(D_c = \frac{v_c}{a_c \times Ma_{e,c}}\), where \(v_c\) is the critical flow velocity, \(a_c\) is the critical speed of sound, and \(Ma_{e,c} = 0.3\) is the critical Mach number. By solving this equation for the critical cylinder diameter \(D_c\), we can find the threshold below which compressibility effects are likely to be important if the flow is turbulent.

Step by step solution

01

Determine the air properties at given temperature and pressure

First, let's determine the air density (\(\rho\)) and dynamic viscosity (\(\mu\)) at given temperature and pressure, using the ideal gas law and constant properties known for air. From the ideal gas law, we get: \(\rho = \frac{p}{RT}\) where \(p = 1\times10^5\) Pa (converting the pressure from atm to Pa), \(R = 287\) J/kg.K (specific gas constant for air), and \(T = 27 + 273 = 300\) K. Plug in the values to get the density: \(\rho = \frac{1\times10^5}{287 \times 300}\) Next, we'll find the dynamic viscosity (\(\mu\)) of air at the given temperature. From the Sutherland's formula, we have: \(\mu = \mu_0\left(\frac{T}{T_0}\right)^{3/2} \frac{T_0 + S}{T + S}\) where \(\mu_0 = 1.716 \times 10^{-5}\) Pa.s (reference viscosity), \(T_0 = 273\) K (reference temperature), and \(S = 110.4\) K (Sutherland's constant). Plug in the values to get the dynamic viscosity: \(\mu = 1.716 \times 10^{-5}\left(\frac{300}{273}\right)^{3/2} \frac{273 + 110.4}{300 + 110.4}\)
02

Calculate the flow velocity at the critical Reynolds number

Now that we have the air properties, we can find the flow velocity at the critical Reynolds number (\(Re_{D,c} = 2\times10^5\)). From the Reynolds number formula: \(v = \frac{Re_D \times \mu}{\rho D}\) Plugging in the values from Step 1, we get the flow velocity as a function of cylinder diameter: \(v = \frac{2\times10^5 \times \mu}{\rho D}\)
03

Calculate the speed of sound in the medium

To find Mach number, we also need to know the speed of sound (\(a\)) in the medium. For an ideal gas, we have: \(a = \sqrt{\gamma RT}\) where \(\gamma = 1.4\) is the specific heat ratio for air. Plug in the values to find the speed of sound in the medium: \(a = \sqrt{1.4 \times 287 \times 300}\)
04

Calculate the critical cylinder diameter where compressibility effects become important

We know, at the critical condition, \(Re_{D,c} = 2\times10^5\) and \(Ma_{e,c} = 0.3\). From the Mach number formula: \(D_c = \frac{v_c}{a_c \times Ma_{e,c}}\) where \(v_c\) is the critical flow velocity and \(a_c\) is the critical speed of sound, both are calculated in Step 2 and 3 respectively. Plug in the values to get the critical cylinder diameter: \(D_c = \frac{\frac{2\times10^5 \times \mu}{\rho D_c}}{\sqrt{1.4 \times 287 \times 300} \times 0.3}\) Solve this equation for the critical cylinder diameter \(D_c\), which represents the threshold below which compressibility effects are likely to be important if the flow is turbulent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laminar to Turbulent Transition
Understanding when a fluid flow transitions from laminar to turbulent is crucial in many engineering applications. The flow of a fluid over a surface, like a cylinder, is described as laminar when it moves in smooth, parallel layers with little or no disruption between them.
However, as the velocity increases, or certain critical conditions are met, disturbances occur, and the flow transitions to turbulent. Turbulent flow is characterized by chaotic, swirling eddies, which increase the friction against the surface and can lead to more rapid wear or other effects.
The critical factor in determining when this transition occurs is the Reynolds number (\(Re_D\)). This is a dimensionless number calculated using the formula:
  • \(Re_D = \frac{\rho v D}{\mu}\)
where \(\rho\) is the fluid density, \(v\) is the flow velocity, \(D\) is the characteristic length (like the diameter of a cylinder), and \(\mu\) is the dynamic viscosity.
For flow around a long cylinder, the transition is documented to occur around a Reynolds number of \(2 \times 10^5\). Understanding this helps engineers design systems that either maximize or minimize turbulent flow based on the desired outcome.
Mach Number
The Mach Number is crucial when considering fluid flows, especially in aerodynamics and gas dynamics. It is a dimensionless quantity representing the ratio of the speed of a fluid to the speed of sound in that fluid.
Mathematically, it is given as:
  • \(Ma = \frac{v}{a}\)
where \(v\) is the velocity of the fluid, and \(a\) is the speed of sound in the medium.
The critical Mach number (**Mae,c**) of 0.3 indicates the boundary where flow characteristics begin to significantly change due to compressibility effects. Below this value, the fluid flow is considered incompressible, meaning the density changes in the flow are negligible.
As the Mach number increases beyond 0.3, compressibility becomes a vital factor influencing flow behavior, requiring more sophisticated analysis and modeling to predict flow patterns and forces accurately. This is particularly important in high-speed aerodynamics, such as those involving aircraft or missile design.
Compressible Flow
Compressible flow refers to fluid flow in which density variations within the fluid become significant. This is distinguished from incompressible flow, where density changes are negligible, typically at Mach numbers below 0.3.
In technical terms, compressibility becomes crucial when the speed of the flow approaches that of sound in the medium. Such conditions are common in aerodynamics, rocket propulsion, and high-speed rail systems.
Managing compressible flow requires considerations including changes in temperature, pressure, and volume that occur concurrently with velocity changes. Specifically, engineers need to ensure accurate predictions in flow rates, pressure drops, and the propagation speed of pressure waves across the fluid domain.
Critical Diameter Calculation
The task of calculating the critical diameter of a cylinder, at which compressibility effects and turbulent flow coincide, involves understanding critical flow conditions.
To determine this diameter, the Reynolds number and the critical Mach number must be factored into calculations.
Using the equation for the Reynolds number and knowing the conditions where transition occurs (\(Re_{D,c} = 2 \times 10^5\) and \(Ma_{e,c} = 0.3\)), the velocity (\(v_c\)) corresponding to these conditions is calculated first.
Then the speed of sound in air is calculated using:
  • \(a = \sqrt{\gamma RT}\)
where \(\gamma = 1.4\) for air.
Finally, the critical diameter is determined by rearranging the equation for the Mach number:
  • \(D_c = \frac{v_c}{a \times Ma_{e,c}}\)
Solving this ensures that the cylinder flow remains at or below this diameter if we want compressibility effects in turbulent conditions to be significant.

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Most popular questions from this chapter

The naphthalene sublimation technique involves the use of a mass transfer experiment coupled with an analysis based on the heat and mass transfer analogy to obtain local or average convection heat transfer coefficients for complex surface geometries. A coating of naphthalene, which is a volatile solid at room temperature, is applied to the surface and is then subjected to airflow in a wind tunnel. Alternatively, solid objects may be cast from liquid naphthalene. Over a designated time interval, \(\Delta t\), there is a discernible loss of naphthalene due to sublimation, and by measuring the surface recession at locations of interest or the mass loss of the sample, local or average mass transfer coefficients may be determined. Consider a rectangular rod of naphthalene exposed to air in cross flow at \(V=10 \mathrm{~m} / \mathrm{s}, T_{\mathrm{s}}=300 \mathrm{~K}\), as in Problem 6.10, except now \(c=10 \mathrm{~mm}\) and \(d=30 \mathrm{~mm}\). Determine the change in mass of the \(L=500\)-mm-long rod over a time period of \(\Delta t=30 \mathrm{~min}\). Naphthalene has a molecular weight of \(M_{\mathrm{A}}=128.16 \mathrm{~kg} / \mathrm{kmol}\), and its solid-vapor saturation pressure at \(27^{\circ} \mathrm{C}\) and \(1 \mathrm{ltm}\) is \(p_{\text {A, } a t}=1.33 \times 10^{-4}\) bar.

It is known that on clear nights the air temperature need not drop below \(0^{\circ} \mathrm{C}\) before a thin layer of water on the ground will freeze. Consider such a layer of water on a clear night for which the effective sky temperature is \(-30^{\circ} \mathrm{C}\) and the convection heat transfer coefficient due to wind motion is \(h=25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The water may be assumed to have an emissivity of \(1.0\) and to be insulated from the ground as far as conduction is concerned. (a) Neglecting evaporation, determine the lowest temperature the air can have without the water freezing. (b) For the conditions given, estimate the mass transfer coefficient for water evaporation \(h_{\mathrm{m}}(\mathrm{m} / \mathrm{s})\). (c) Accounting now for the effect of evaporation, what is the lowest temperature the air can have without the water freezing? Assume the air to be dry.

Consider airflow over a flat plate of length \(L=1 \mathrm{~m}\) under conditions for which transition occurs at \(x_{c}=0.5 \mathrm{~m}\) based on the critical Reynolds number, \(R e_{x, c}=5 \times 10^{5}\). (a) Evaluating the thermophysical properties of air at \(350 \mathrm{~K}\), determine the air velocity. (b) In the laminar and turbulent regions, the local convection coefficients are, respectively, \(h_{\text {lam }}(x)=C_{\text {lam }} x^{-05}\) and \(h_{\text {marb }}=C_{\text {marb }} x^{-0.2}\) where, at \(T=350 \mathrm{~K}, C_{\text {lum }}=8.845 \mathrm{~W} / \mathrm{m}^{3 / 2} \cdot \mathrm{K}, C_{\text {tub }}=\) \(49.75 \mathrm{~W} / \mathrm{m}^{1.8} \cdot \mathrm{K}\), and \(x\) has units of \(\mathrm{m}\). Develop an expression for the average convection coefficient, \(\bar{h}_{\mathrm{hm}}(x)\), as a function of distance from the leading edge, \(x\), for the laminar region, \(0 \leq x \leq x_{x}\). (c) Develop an expression for the average convection coefficient, \(\bar{h}_{\text {art }}(x)\), as a function of distance from the leading edge, \(x\), for the turbulent region, \(x_{c} \leq x \leq L\). (d) On the same coordinates, plot the local and average convection coefficients, \(h_{x}\) and \(\bar{h}_{x}\), respectively, as a function of \(x\) for \(0 \leq x \leq L\).

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On a summer day the air temperature is \(27^{\circ} \mathrm{C}\) and the relative humidity is \(30 \%\). Water evaporates from the surface of a lake at a rate of \(0.10 \mathrm{~kg} / \mathrm{h}\) per square meter of water surface area. The temperature of the water is also \(27^{\circ} \mathrm{C}\). Determine the value of the convection mass transfer coefficient. 6.53 It is observed that a 230 -mm-diameter pan of water at \(23^{\circ} \mathrm{C}\) has a mass loss rate of \(1.5 \times 10^{-5} \mathrm{~kg} / \mathrm{s}\) when the ambient air is dry and at \(23^{\circ} \mathrm{C}\). (a) Determine the convection mass transfer coefficient for this situation. (b) Estimate the evaporation mass loss rate when the ambient air has a relative humidity of \(50 \%\). (c) Estimate the evaporation mass loss rate when the water and ambient air temperatures are \(47^{\circ} \mathrm{C}\), assuming that the convection mass transfer coefficient remains unchanged and the ambient air is dry.

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