/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 The defroster of an automobile f... [FREE SOLUTION] | 91Ó°ÊÓ

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The defroster of an automobile functions by discharging warm air on the inner surface of the windshield. To prevent condensation of water vapor on the surface, the temperature of the air and the surface convection coefficient \(\left(T_{\infty, j}, \overline{h_{i}}\right)\) must be large enough to maintain a surface temperature \(T_{s i}\) that is at least as high as the dewpoint \(\left(T_{s, i} \geq T_{d \mathrm{p}}\right)\). Consider a windshield of length \(L=800 \mathrm{~mm}\) and thickness \(t=6 \mathrm{~mm}\) and driving conditions for which the vehicle moves at a velocity of \(V=70 \mathrm{mph}\) in ambient air at \(T_{\infty \rho}=-15^{\circ} \mathrm{C}\). From laboratory experiments performed on a model of the vehicle, the average convection coefficient on the outer surface of the windshield is known to be correlated by an expression of the form \(\overline{N_{L}}=0.030 \operatorname{Re}_{L}^{0.8} \operatorname{Pr}^{1 / 3}\), where \(R e_{L}=V L \nu\). Air properties may be approximated as \(k=0.023 \mathrm{~W} / \mathrm{m}=\mathrm{K}\), \(v=12.5 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\), and \(\operatorname{Pr}=0.71\). If \(T_{d p}=10^{\circ} \mathrm{C}\) and \(T_{m, j}=50^{\circ} \mathrm{C}\), what is the smallest value of \(\bar{h}_{j}\) required to prevent condensation on the inner surface?

Short Answer

Expert verified
The smallest value of \(\overline{h_{j}}\) required to prevent condensation on the inner surface of the windshield is approximately \(253.45 \mathrm{~W} / \mathrm{m}^{2}\mathrm{K}\).

Step by step solution

01

1. Convert units

Before we start solving the problem, let's convert the units to SI units. The length L and thickness t are already in SI units. The velocity V is given in miles per hour (mph). We need to convert it into meters per second (m/s). 1 mile = 1609.34 meters 1 hour = 3600 seconds \(V = 70 \text{ mph} = 70 \times \frac{1609.34 \text{ m}}{3600 \text{ s}} = 31.2928 \text{ m/s}\) Now all the given data are in SI units, and we can proceed with the calculations.
02

2. Calculate the Reynolds number

Now, let's calculate the Reynolds number (\(Re_L\)), using the given equation \(Re_L = V L \nu\), where V = 31.2928 m/s, L = 0.8 m, and \(\nu = 12.5 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\). \(Re_L = 31.2928 * 0.8 * 12.5 \times 10^{-6}\) \(Re_L = 314.327\)
03

3. Calculate the average Nusselt number

We are given the correlation for the average Nusselt number as \(\overline{N_{L}}=0.030 \operatorname{Re}_{L}^{0.8} \operatorname{Pr}^{1 / 3}\), where \(\operatorname{Re}_{L} = 314.327\), and \(\operatorname{Pr} = 0.71\). \(\overline{N_{L}} = 0.030 \times (314.327)^{0.8} \times (0.71)^{\frac{1}{3}}\) \(\overline{N_{L}} = 17.0542\)
04

4. Calculate the convection heat transfer coefficient on the outer surface of the windshield

Now, let's calculate the convection heat transfer coefficient on the outer surface of the windshield, knowing that for a fluid with a constant property: \(\overline{h_{\rho}} = \frac{\overline{N_{L}}k}{L}\), where \(\overline{N_{L}} = 17.0542\), \(k = 0.023 \mathrm{~W} / \mathrm{m}=\mathrm{K}\), and \(L = 0.8 \mathrm{~m}\). \(\overline{h_{\rho}} = \frac{17.0542 \times 0.023}{0.8}\) \(\overline{h_{\rho}} = 0.4933 \mathrm{~W} / \mathrm{m}^{2}\mathrm{K}\)
05

5. Determine the smallest value of \(\bar{h}_{j}\)

Since we need to maintain a surface temperature at least equal to the dewpoint, we can use the following energy balance equation for the surface temperature: \(T_{d p} - T_{\infty \rho} = \left( \frac{\overline{h_{j}}t}{k} + \frac{1}{\overline{h_{\rho}}} \right)(T_{m, j} - T_{\infty \rho}) \). Let's first calculate the left part of the equation, \(T_{d p} - T_{\infty \rho}\): \(T_{d p} - T_{\infty \rho} = 10 - (-15) = 25 \mathrm{^\circ C}\) Now, let's find the smallest value of \(\bar{h}_{j}\) by solving the equation: \(25 = \left( \frac{\overline{h_{j}} \times 0.006}{0.023} + \frac{1}{0.4933} \right)(50 - (-15))\) \(25 = \left( \frac{\overline{h_{j}} \times 0.006}{0.023} + \frac{1}{0.4933} \right)(65)\) \(\frac{\overline{h_{j}} \times 0.006}{0.023} = \frac{25}{65} - \frac{1}{0.4933}\) \(\overline{h_{j}} = \frac{0.023}{0.006}\left( \frac{25}{65} - \frac{1}{0.4933} \right)\) \(\overline{h_{j}} = 253.45 \mathrm{~W} / \mathrm{m}^{2}\mathrm{K}\) The smallest value of \(\overline{h_{j}}\) required to prevent condensation on the inner surface of the windshield is approximately \(253.45 \mathrm{~W} / \mathrm{m}^{2}\mathrm{K}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convection Heat Transfer Coefficient
Understanding the convection heat transfer coefficient is crucial for various engineering applications, including the design of vehicle windshields that require defrosting. Convection is one of the three modes of heat transfer, the others being conduction and radiation. In the context of a windshield, convection occurs when the warm air from the defroster comes into contact with the cooler glass surface.

The convection heat transfer coefficient, denoted as \( \bar{h} \), quantifies the ability of convective flow to transfer heat between a surface and a fluid moving over it. It's measured in watts per square meter per Kelvin \( \mathrm{W/m^2K} \). A higher \( \bar{h} \) suggests more efficient heat transfer. In our scenario, preventing condensation involves maintaining a surface temperature above the dew point, necessitating an adequate convection heat transfer coefficient \( \bar{h}_j \). The exact value required can be derived from balancing the energy equation and considering both the internal and external convection coefficients, as shown in the problem's solution.

To facilitate students' understanding:
  • Provide a clear explanation of how convection involves the movement of heat due to the movement of fluid.
  • Use analogies, such as comparing the convection heat transfer process to a fan blowing away the heat from hot metal.
  • Emphasize the importance of \( \bar{h} \) in determining how effectively the defroster warms the windshield to prevent condensation.
Reynolds Number
The Reynolds number, often denoted as \( Re \), is a dimensionless quantity used in fluid mechanics to predict flow patterns in different fluid flow situations. It compares the relative importance of inertial forces and viscous forces and is calculated by the formula \( Re = \frac{\rho V L}{\mu} \) or \( Re = \frac{V L}{u} \) where:\
  • \(\rho\) is the fluid density
  • \(V\) is the velocity of the flow
  • \(L\) is the characteristic length (like the windshield's length)
  • \(\mu\) is the dynamic viscosity of the fluid
  • \(u\) is the kinematic viscosity of the fluid

In layman terms, if you think about it as a race between the forces within the fluid, the Reynolds number tells us whether inertia (suggesting turbulent flow) or viscosity (suggesting laminar flow) is winning. The unique conditions of windshield defrosting require knowledge of this number to design an effective system.

For educational improvement, it's effective to:
  • Describe the context of the problem and how the Reynolds number provides insights into the flow over a windshield.
  • Utilize diagrams or visuals to demonstrate the difference between laminar and turbulent flows.
  • Relate the concept to everyday experiences, such as comparing the airflow around a moving car to water flowing around rocks in a stream.
By understanding the Reynolds number in the windshield defrosting context, students can appreciate its role in predicting the effectiveness of the defrosting process.
Nusselt Number
The Nusselt number is a dimensionless parameter in heat transfer that relates the convective heat transfer to conduction heat transfer across a boundary. Denoted as \( Nu \), it's given by the formula \( Nu = \frac{h L}{k} \), where:\
  • \(h\) is the convection heat transfer coefficient
  • \(L\) is the characteristic length
  • \(k\) is the thermal conductivity of the fluid

For a windshield in a car, an ideal defrosting system depends significantly on a well-calculated Nusselt number, which allows engineers to understand and optimize the heat transfer process on the windshield's surface.

Explaining the Nusselt number with clarity can include:
  • Breaking down its calculation into understandable steps, and relating it to the real-world application of defrosting a windshield.
  • Using simple language to explain how it represents the efficiency of heat transfer from the warmer air due to the defroster to the cooler windshield.
  • Discussing its importance in ensuring the car's visibility during cold weather by effectively preventing condensation and freezing on the windshield.
The Nusselt number in our exercise helped us calculate the required convection heat transfer coefficient to prevent condensation, showcasing its value in practical engineering problems.

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Most popular questions from this chapter

The heat transfer rate per unit width (normal to the page) from a longitudinal section, \(x_{2}-x_{1}\), can be expressed as \(q_{12}^{\prime}=\bar{h}_{12}\left(x_{2}-x_{1}\right)\left(T_{s}-T_{\infty}\right)\), where \(\bar{h}_{12}\) is the average coefficient for the section of length \(\left(x_{2}-x_{1}\right)\). Consider laminar flow over a flat plate with a uniform temperature \(T_{s}\). The spatial variation of the local convection coefficient is of the form \(h_{x}=C x^{-1 / 2}\), where \(C\) is a constant. (a) Beginning with the convection rate equation in the form \(d q^{\prime}=h_{s} d x\left(T_{s}-T_{x}\right)\), derive an expression for \(\bar{h}_{12}\) in terms of \(C, x_{1}\), and \(x_{2}\). (b) Derive an expression for \(\bar{h}_{12}\) in terms of \(x_{1}, x_{2}\), and the average coefficients \(\bar{h}_{1}\) and \(\bar{h}_{2}\), corresponding to lengths \(x_{1}\) and \(x_{2}\), respectively.

On a summer day the air temperature is \(27^{\circ} \mathrm{C}\) and the relative humidity is \(30 \%\). Water evaporates from the surface of a lake at a rate of \(0.10 \mathrm{~kg} / \mathrm{h}\) per square meter of water surface area. The temperature of the water is also \(27^{\circ} \mathrm{C}\). Determine the value of the convection mass transfer coefficient. 6.53 It is observed that a 230 -mm-diameter pan of water at \(23^{\circ} \mathrm{C}\) has a mass loss rate of \(1.5 \times 10^{-5} \mathrm{~kg} / \mathrm{s}\) when the ambient air is dry and at \(23^{\circ} \mathrm{C}\). (a) Determine the convection mass transfer coefficient for this situation. (b) Estimate the evaporation mass loss rate when the ambient air has a relative humidity of \(50 \%\). (c) Estimate the evaporation mass loss rate when the water and ambient air temperatures are \(47^{\circ} \mathrm{C}\), assuming that the convection mass transfer coefficient remains unchanged and the ambient air is dry.

Photosynthesis, as it occurs in the leaves of a green plant, involves the transport of carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) from the atmosphere to the chloroplasts of the leaves. The rate of photosynthesis may be quantified in terms of the rate of \(\mathrm{CO}_{2}\) assimilation by the chloroplasts. This assimilation is strongly influenced by \(\mathrm{CO}_{2}\) transfer through the boundary layer that develops on the leaf surface. Under conditions for which the density of \(\mathrm{CO}_{2}\) is \(6 \times 10^{-4} \mathrm{~kg} / \mathrm{m}^{3}\) in the air and \(5 \times 10^{-4} \mathrm{~kg} / \mathrm{m}^{3}\) at the leaf surface and the convection mass transfer coefficient is \(10^{-2} \mathrm{~m} / \mathrm{s}\), what is the rate of photosynthesis in terms of kilograms of \(\mathrm{CO}_{2}\) assimilated per unit time and area of leaf surface?

An industrial process involves evaporation of a thin water film from a contoured surface by heating it from below and forcing air across it. Laboratory measurements for this surface have provided the following heat transfer correlation: $$ \overline{N u_{L}}=0.43 R e_{L}^{0.58} P r^{0.4} $$ The air flowing over the surface has a temperature of \(290 \mathrm{~K}\), a velocity of \(10 \mathrm{~m} / \mathrm{s}\), and is completely dry \(\left(\phi_{\infty}=0\right)\). The surface has a length of \(1 \mathrm{~m}\) and a surface area of \(1 \mathrm{~m}^{2}\). Just enough energy is supplied to maintain its steady-state temperature at \(310 \mathrm{~K}\). (a) Determine the heat transfer coefficient and the rate at which the surface loses heat by convection. (b) Determine the mass transfer coefficient and the evaporation rate \((\mathrm{kg} / \mathrm{h})\) of the water on the surface. (c) Determine the rate at which heat must be supplied to the surface for these conditions.

To a good approximation, the dynamic viscosity \(\mu\), the thermal conductivity \(k\), and the specific heat \(c_{p}\) are independent of pressure. In what manner do the kinematic viscosity \(v\) and thermal diffusivity \(\alpha\) vary with pressure for an incompressible liquid and an ideal gas? Determine \(\alpha\) of air at \(350 \mathrm{~K}\) for pressures of 1,5 , and \(10 \mathrm{~atm}\). Assuming a transition Reynolds number of \(5 \times 10^{5}\), determine the distance from the leading edge of a flat plate at which transition will occur for air at \(350 \mathrm{~K}\) at pressures of 1,5 , and 10 atm with \(u_{s}=2 \mathrm{~m} / \mathrm{s}\).

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