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If a body of specific gravity \(\mathrm{SG}_{1}\) is placed in a liquid of specific gravity \(\mathrm{SG}_{2}\), what fraction of the total volume of the body will be above the surface of the liquid? If an iceberg has a specific gravity of 0.95 and is floating in seawater with a specific gravity of \(1.25,\) what fraction of the iceberg is above water?

Short Answer

Expert verified
24% of the iceberg's volume is above water.

Step by step solution

01

Understanding Buoyant Force

The buoyant force acting on a submerged object is equal to the weight of the liquid displaced by the object. Using Archimedes' principle, we equate the buoyant force to the weight of the body.
02

Relating Specific Gravities and Volume Fractions

The fraction of the volume of the body submerged in the liquid is equal to the ratio of the body's specific gravity to the liquid's specific gravity, i.e., \( \frac{\text{SG}_1}{\text{SG}_2} \).
03

Calculate Fraction Submerged

For the iceberg, \( \text{SG}_1 = 0.95 \) (iceberg) and \( \text{SG}_2 = 1.25 \) (seawater). The submerged fraction is \( \frac{0.95}{1.25} = 0.76 \).
04

Calculate Fraction Above Water

The fraction of the iceberg above water is \(1 - 0.76 = 0.24\). Thus, 24% of the iceberg's volume is above the water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Archimedes' Principle
Archimedes' Principle is a fundamental concept in fluid mechanics that is crucial for understanding buoyancy. It states that any object, when immersed in a fluid, experiences an upward force equal to the weight of the fluid that the object displaces. This principle is essential in determining whether an object will float or sink when placed in a liquid. To apply Archimedes' Principle, you first need to determine the volume of the displaced fluid, which is the same as the volume of the submerged part of the object. The weight of this fluid indicates the buoyant force acting on the object. If this buoyant force is equal to or greater than the object's weight, the object will float. Otherwise, it will sink. This principle not only helps predict floating objects but also enables various practical applications, from designing ships to understanding the behavior of floating icebergs.
Specific Gravity
Specific Gravity (SG) is a dimensionless quantity that describes the density of a substance relative to the density of a reference substance, often water for liquids. Specific gravity is used to compare the density of substances without having to use actual units of density like kg/m³. Essentially, it tells us how heavy a substance is compared to water: - If SG > 1, the substance is denser than water. - If SG < 1, the substance is less dense. - If SG = 1, the substance has the same density as water. In the context of floating objects, specific gravity is an important factor. It helps determine how much of an object will be submerged when it is floating, based on the comparison between the specific gravity of the object and that of the liquid.
Volume Fraction
Volume Fraction describes the proportion of an object's volume that is either submerged in or above a liquid. It is essential for understanding how much of an object will be visible above the surface when it is floating.To calculate the submerged volume fraction, you use the ratio of the object's specific gravity (SG_1) to the liquid's specific gravity (SG_2):\[ \text{Submerged Volume Fraction} = \frac{\text{SG}_1}{\text{SG}_2} \]This tells you what portion of the object's volume is under the liquid. In the iceberg example from the problem, with specific gravity ratio calculations, you find that 76% of the iceberg is submerged. The remaining volume fraction above the water can be calculated by subtracting this submerged fraction from 1, indicating that 24% of the iceberg is above water.
Submerged Object Analysis
Submerged Object Analysis involves assessing how much of an object sits below the surface of a liquid and how much rises above it. This analysis is crucial for understanding stability and buoyancy of floating objects. To analyze a submerged object: 1. Determine the object's and the fluid's specific gravities. 2. Calculate the submerged volume fraction using the ratio of specific gravities. 3. Identify the percentage of the object submerged by multiplying this ratio by 100. 4. Calculate the volume fraction above the liquid by subtracting the submerged fraction from 1. In practical terms, this analysis helps predict the behavior of floating objects like icebergs or boats. For icebergs, knowing the submerged and above-water volume fractions aids in understanding their movement and potential hazards.

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Most popular questions from this chapter

A water truck is mounted with a cylindrical tank that has a diameter of \(2 \mathrm{~m}\) and a length of \(10 \mathrm{~m}\). The long axis of the tank is oriented with the direction of truck motion. If the tank is filled with water at \(20^{\circ} \mathrm{C}\) and the truck accelerates at a rate of \(2 \mathrm{~m} / \mathrm{s}^{2}\), estimate the difference in magnitude between the resultant hydrostatic force on the front and back of the tank.

A circular hatch is located in a sloping wall of a water storage reservoir, where the wall slopes at \(35^{\circ}\) to the horizontal, the radius of the hatch is \(420 \mathrm{~mm}\), and the center of the hatch is \(3 \mathrm{~m}\) below the water surface (measured along the sloping wall). Find the magnitude and location of the resultant hydrostatic force on the hatch.

A cylindrical container has a diameter of \(0.4 \mathrm{~m}\) and contains kerosene to a depth of \(0.6 \mathrm{~m}\). The temperature of the kerosene is \(20^{\circ} \mathrm{C}\). If the container, with its long axis oriented vertically, is placed on the floor of a delivery elevator that ascends with an acceleration of \(1.5 \mathrm{~m} / \mathrm{s}^{2}\), what is the pressure in the fluid on the bottom of the container? What force does the container exert on the floor of the elevator? Assume that the mass of the container is negligible compared with that of the kerosene.

A light airplane uses an aneroid barometer to measure changes in altitude. At one elevation, the pressure is \(96 \mathrm{kPa}\), and at a higher elevation, the pressure is \(85.3 \mathrm{kPa}\). Estimate the difference in altitude corresponding to these measurements. Assume that the airplane is operating in a standard atmosphere.

What is the pressure head (of water) corresponding to a pressure of \(810 \mathrm{kPa}\) ? What depth of mercury at \(20^{\circ} \mathrm{C}\) will be required to produce a pressure of \(810 \mathrm{kPa}\) ?

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