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What is the pressure head (of water) corresponding to a pressure of \(810 \mathrm{kPa}\) ? What depth of mercury at \(20^{\circ} \mathrm{C}\) will be required to produce a pressure of \(810 \mathrm{kPa}\) ?

Short Answer

Expert verified
Water head: 83.33 meters; Mercury head: 6.06 meters.

Step by step solution

01

Understand the Variables

The pressure head of a fluid is the height of a column of that fluid that would produce a given pressure due to gravity. The pressure given is 810 kPa. We want to find the height of a water column and a mercury column at 20°C that would produce this pressure.
02

Formula for Pressure Head

The formula for calculating the pressure head is \( h = \frac{P}{\rho g} \), where \( P \) is the pressure in pascals, \( \rho \) is the density of the fluid, and \( g \) is the acceleration due to gravity (9.81 \( \mathrm{m/s^2} \)).
03

Calculate Pressure Head for Water

For water at 20°C, the density \( \rho \) is approximately 998 \( \mathrm{kg/m^3} \). Using the formula, \( h_w = \frac{810,000}{998 \times 9.81} \Approx 83.33 \) meters.
04

Calculate Pressure Head for Mercury

For mercury at 20°C, the density \( \rho \) is approximately 13,600 \( \mathrm{kg/m^3} \). Using the formula, \( h_{Hg} = \frac{810,000}{13,600 \times 9.81} \Approx 6.06 \) meters.
05

Summarize Results

To achieve a pressure of 810 kPa, a water column would need to be approximately 83.33 meters tall, whereas a mercury column would need to be about 6.06 meters tall.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Density
Fluid density is a fundamental concept in fluid mechanics and is defined as the mass of a fluid per unit volume. It captures how much matter is packed into a particular space in the fluid, which can greatly affect its behavior and properties. For liquids like water and mercury, density plays a critical role in determining how they respond to pressure and buoyancy forces.
Understanding fluid density is crucial when calculating the pressure head, as seen in the exercise where we compare water and mercury's capacity to sustain the same pressure at different heights.
  • Water at 20°C has a density of approximately 998 kg/m³.
  • Mercury at 20°C has a much higher density of about 13,600 kg/m³.

These values highlight the fact that denser fluids like mercury can achieve the same pressure with a significantly shorter column height than less dense fluids like water.
Hydrostatic Pressure
Hydrostatic pressure is the pressure exerted by a fluid at equilibrium due to the force of gravity. An important thing to note is that this pressure increases with depth in the fluid. The deeper you go, the more weight is exerted by the fluid above, increasing the pressure experienced at that point.
In the given problem, we are concerned with the hydrostatic pressure, which can be related to the fluid column's height using the formula: \[ h = \frac{P}{\rho g} \] where \(P\) is the pressure, \(\rho\) is the fluid density, and \(g\) is the acceleration due to gravity. This relation helps us find how tall a column needs to be to exert the specified pressure, such as the \(810 \mathrm{kPa}\) used in the exercise.
  • Pressure is directly proportional to the fluid density and column height.
  • Higher density fluids achieve the same pressure with shorter columns.
Fluid Column Height
The fluid column height is a measurement of how tall a column of fluid needs to be to exert a specific pressure at its base. It's a way to visualize pressure in terms of height and is an intuitive way to understand the concept of pressure head.
From the exercise, we determined the height required for both water and mercury to produce a pressure of \(810 \mathrm{kPa}\). This concept helps illustrate how different fluids behave under similar pressure conditions.
  • For water, a column height of approximately 83.33 meters is needed.
  • For mercury, the required height is much less, around 6.06 meters.

This comparison clearly shows the relationship between density and column height: a denser fluid like mercury achieves the same pressure with a shorter column.

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Most popular questions from this chapter

A \(2 \mathrm{~m} \times 3 \mathrm{~m}\) rectangular gate is located on the sloping side of a water reservoir such that the \(2-\mathrm{m}\) side of the gate is parallel to the water surface. The side of the reservoir (and the gate) slopes at an angle of \(60^{\circ}\) to the horizontal, and the top of the gate is \(2.5 \mathrm{~m}\) vertically below the water surface. Estimate the resultant hydrostatic force on the gate and the effective location of this resultant force, as measured vertically downward from the water surface.

The pressure in the airspace above an oil \((\mathrm{SG}=0.80)\) surface in a tank is \(14 \mathrm{kPa}\). Find the pressure \(1.5 \mathrm{~m}\) below the surface of the oil.

Two piston diameters are being considered for use in a hydraulic system: a 25-mmdiameter piston and a 100 -mm-diameter piston. If an applied force of \(500 \mathrm{~N}\) to the 25 -mm piston is found to be satisfactory, what force on the 100 -mm piston at the same location would be required so as not to compromise the performance of the hydraulic system?

A hydrometer with a stem diameter of \(12 \mathrm{~mm}\) weighs \(0.246 \mathrm{~N}\). An engineer places the hydrometer in pure water at \(20^{\circ} \mathrm{C}\) and marks the place on the stem corresponding to the water surface. When the engineer places the hydrometer in a test liquid, the mark is \(2 \mathrm{~cm}\) above the surface of the liquid. Estimate the specific gravity of the test liquid.

A hot air balloon is to carry a weight of \(1.5 \mathrm{kN}\) over an area that has a typical atmospheric pressure of \(101 \mathrm{kPa}\) and a typical summer temperature of \(20^{\circ} \mathrm{C}\). The balloon is made of a material that has a mass of \(80 \mathrm{~g} / \mathrm{m}^{2}\), and the air in the balloon is to be heated to a temperature of \(80^{\circ} \mathrm{C}\). What will be the diameter of the balloon under stable conditions?

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