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The standard canoe model from a manufacturer weighs \(810 \mathrm{~N},\) and an ultralight (and ultrastrong) model of the same size and shape weighs \(220 \mathrm{~N}\). Both models are capable of carrying the same load. For any given load, determine the additional volume of water displaced by the heavier model.

Short Answer

Expert verified
The additional volume of water displaced by the heavier model is approximately 0.0602 m³.

Step by step solution

01

Understand Archimedes' Principle

Archimedes' Principle states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by that object. This means the weight of water displaced by a floating object is equal to the weight of the object itself.
02

Determine the Buoyant Force

For both canoe models to float with the same load, the buoyant force must equal their total weight. The buoyant force (which equals the weight of displaced water) is \(810\, \text{N} + W_L\) for the standard model and \(220\, \text{N} + W_L\) for the ultralight model, where \(W_L\) is the weight of the load they carry.
03

Calculate Difference in Water Displaced

The difference in the water displaced by the two models is equal to the difference in their weights, considering they displace additional water equal to \(810 \, \text{N} - 220 \, \text{N} = 590 \, \text{N}\).
04

Convert to Volume

Water has a density of approximately \(1000 \text{ kg/m}^3\) or \(9.8 \times 10^3 \, \text{N/m}^3\). Therefore, we convert the weight of displaced water to volume using \( V = \frac{Weight}{Density} \) formula:\[ V = \frac{590 \, \text{N}}{9.8 \times 10^3 \, \text{N/m}^3} \approx 0.0602 \text{ m}^3 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyant Force
The concept of buoyant force is crucial in understanding why objects like canoes float. Buoyant force is the upward force a fluid exerts on an object placed within it. According to Archimedes' Principle, this force equals the weight of the fluid displaced by the object. If you imagine pressing your hand into a bucket of water, the buoyant force is what pushes your hand up.

For a floating object, the buoyant force equals its weight. This balance is why a canoe remains afloat even when loaded with gear. The heavier the object, the greater the buoyant force needed, meaning more water must be displaced to keep the object floating. In the context of our canoe models, both the standard and ultralight models need a buoyant force equal to their combined weight with their load to stay afloat.

In general, understanding buoyant force helps explain not only floating canoes but also other phenomena like why ships float and icebergs bob in the sea. It's a fundamental concept in fluid dynamics.
Water Displacement
Water displacement is closely linked to buoyant force. It refers to the volume of water that is moved out of the way when an object is submerged in water. The more water an object displaces, the more buoyant force it experiences.

When you place something in water, it pushes water aside, creating a space that matches its volume below the water surface. This change in water volume is what is meant by displacement. You can observe water displacement when you submerge a block of wood in a bathtub and notice the water level rising.

In our canoe problem, the heavier standard model displaces more water compared to the ultralight model because it requires a greater buoyant force to balance its larger weight. The difference in displacement between the two models leads to the additional volume of water displaced by the heavier model. This concept is essential in not only student exercises but practical tasks as well, such as shipbuilding and designing flotation devices.
Density of Water
Density of a substance is defined as its mass per unit volume. For water, it is approximately 1000 kg/m³, making it a standard for comparing the density of other substances.

The role of water's density is critical when calculating the volume of water displaced by an object based on the force it experiences due to gravity. In our exercise, using the density of water (converted into N/m³ for convenience), we can find how much water's weight corresponds to a particular buoyant force. By dividing the weight of water displaced (in newtons) by the density of water (also in newtons per cubic meter), we arrive at the volume in cubic meters.

Understanding the density of water allows individuals to predict and calculate whether an object will sink or float and how much water it will displace. This knowledge is foundational in areas such as aquarium design, engineering of water vessels, and various scientific research projects involving water.

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Most popular questions from this chapter

A liquid is stratified such that the specific gravity of the fluid at the surface is 0.98 and the specific gravity at a depth of \(12 \mathrm{~m}\) is equal to 1.07 . Assuming that the specific gravity varies linearly between the liquid surface and a depth of \(12 \mathrm{~m}\), determine the pressure at a depth of \(12 \mathrm{~m}\). State whether this is a gauge pressure or an absolute pressure.

The weight of a solid object in air is measured as \(40 \mathrm{~N},\) and the weight of this same object in water at \(20^{\circ} \mathrm{C}\) is measured as \(25 \mathrm{~N}\). Estimate the specific weight and volume of the object.

A vertical circular gate of diameter \(D\) is installed such that the top of the gate is a distance \(d\) below the water surface in a reservoir. Calculate the hydrostatic force on the gate and show that the location of the center of pressure is given by $$ y_{\mathrm{cp}}=D+\frac{D(8 d+5 D)}{16 d+8 D} $$

A hydrometer with a stem diameter of \(12 \mathrm{~mm}\) weighs \(0.246 \mathrm{~N}\). An engineer places the hydrometer in pure water at \(20^{\circ} \mathrm{C}\) and marks the place on the stem corresponding to the water surface. When the engineer places the hydrometer in a test liquid, the mark is \(2 \mathrm{~cm}\) above the surface of the liquid. Estimate the specific gravity of the test liquid.

A natural gas pipeline has a diameter of \(410 \mathrm{~mm}\) and a wall thickness of \(4.2 \mathrm{~mm}\). If the pressure of the gas in the pipeline is equal to \(800 \mathrm{kPa}\), estimate the average circumferential stress in the pipe wall.

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