Maximum field in a cyclotron **
For some purposes it is useful to accelerate negative hydrogen ions in a
cyclotron. A negative hydrogen ion, \(\mathrm{H}^{-}\), is a hydrogen atom to
which an extra electron has become attached. The attachment is fairly weak; an
electric field of only \(4.5 \cdot 10^{8} \mathrm{~V} / \mathrm{m}\) in the
frame of the ion (a rather small field by atomic standards) will pull an
electron loose, leaving a hydrogen atom. If we want to accelerate
\(\mathrm{H}^{-}\)ions up to a kinetic energy of \(1 \mathrm{GeV}\left(10^{9}
\mathrm{eV}\right)\), what is the highest magnetic field we dare use to keep
them on a circular orbit up to final energy? (To find \(\gamma\) for this
problem you only need the rest energy of the \(\mathrm{H}^{-}\)ion, which is of
course practically the same as that of the proton, approximately \(1
\mathrm{GeV}\).)