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Constant magnitude of \(B\) ** How should the current density inside a thick cylindrical wire depend on \(r\) so that the magnetic field has constant magnitude inside the wire?

Short Answer

Expert verified
The current density \(J\) inside the wire must depend on \(r\) such that \(J\propto1/r\) in order for the magnetic field to have constant magnitude inside the wire.

Step by step solution

01

Apply Ampere's law

Ampere's law relates the circulation of magnetic field around a closed loop to the current through it. For a cylindrical wire, we choose a circular Amperean loop of radius \(r\) inside the wire. By symmetry, the magnetic field \(B\) is always tangent to this loop and it has the same magnitude at every point. The field and the direction of integration are both in azimuthal direction, so the angle between them is zero. Ampere's law becomes \(\oint B \cdot dl = \mu_0 I_{enc}\), where \(I_{enc}\) is the enclose current within the loop. We can rewrite this equation as \(B \cdot 2 \pi r = \mu_0 I_{enc}\).
02

Express the enclosed current in terms of current density

The current density \(J\) is defined as the current per unit area. For the cylindrical wire, the current enclosed within the circular loop of \(r\) is given by \(I_{enc} = \int J \cdot da\), where \(da = r \cdot d \theta \cdot dr\) is the area element in cylindrical coordinates. Substituting this into the Ampere's law equation gives \(B \cdot 2 \pi r = \mu_0 \int J \cdot r d \theta dr\). In order to derive a constant magnetic field \(B\), it is necessary for \(J\) to be a function of \(r\).
03

Solve for current density

By symmetry, \(J\) does not depend on the angle \(\theta\) and the integration over \(\theta\) yields \(2 \pi\). The equation then becomes \(B \cdot r = \mu_0 \int J \cdot r dr\). If \(B\) is to be constant, the right hand side must also be constant w.r.t \(r\). It follows that \(J\propto1/r\), i.e., the current density decreases inversely with the radius.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field Inside a Conductor
The concept of the magnetic field inside a conductor can be intriguing, as it involves imagining how invisible lines of magnetic force permeate a material carrying electric current. In simple terms, when a conductor such as a wire carries a current, it generates a magnetic field around it. The direction of this magnetic field can be determined by the right-hand rule, which states that if you point the thumb of your right hand in the direction of the current, the direction in which your fingers curl will indicate the magnetic field direction.

For a long, straight conductor, the magnetic field lines form circular loops around the wire. However, in a cylindrical wire, the situation becomes more complex due to the wire's geometry. Using Ampere's law, \( \oint B \cdot dl = \mu_0 I_{enc} \), we understand that the magnetic field inside a wire is directly related to the current enclosed by the path upon which we are applying the law. A key insight for having a constant magnetic field within a cylindrical conductor is ensuring that the relationship between the magnetic field and the current density is carefully managed.
Current Density Dependence on Radius
Getting to grips with how current density varies with the radius in a cylindrical wire requires a bit of spatial thinking. Current density, often denoted by \(J\), is the amount of electric current flowing per unit area within the conductor. Thinking about a thick wire, rather than current flowing uniformly across the entire cross-section, we realize that the distribution of current can vary.

In our problem, we are asked to determine how \(J\) should depend on the radial position \(r\) so that the magnetic field inside the wire remains constant. Since the magnetic field \(B\) is directly proportional to the enclosed current \(I_{enc}\) in Ampere's law, and \(I_{enc}\) depends on the current density and area over which it is flowing, having a constant \(B\) implies a very specific radial dependence for \(J\). The solution unveils that this dependence is inversely proportional, meaning \(J \propto 1/r\). This indicates that closer to the center of the wire, where \(r\) is smaller, the current density must be higher to maintain a uniform magnetic field throughout the wire's interior.
Application of Cylindrical Coordinates in Electromagnetism
Cylindrical coordinates become exceedingly helpful when dealing with problems in electromagnetism involving cylindrical symmetry. Unlike Cartesian coordinates, which are best suited for rectangular shapes, cylindrical coordinates are aligned with circular or cylindrical shapes, making them more intuitive for solving such problems.

In the context of our exercise, we applied cylindrical coordinates to describe the area element \(da\), which is essentially a small piece of the wire's cross-section at a certain radius \(r\) and angle \(\theta\). This allows us to integrate over the cross-section to find the enclosed current that is contributing to the magnetic field at that radius. The beauty of using cylindrical coordinates lies in their alignment with the problem's symmetry, simplifying the integration process and guiding us to the correct dependence of current density on radius to achieve the desired uniform magnetic field inside the cylindrical conductor.

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Most popular questions from this chapter

Vector potential inside a wire ** A round wire of radius \(r_{0}\) carries a current \(I\) distributed uniformly over the cross section of the wire. Let the axis of the wire be the \(z\) axis, with \(\hat{z}\) the direction of the current. Show that a vector potential of the form \(\mathbf{A}=A_{0} \hat{\mathbf{z}}\left(x^{2}+y^{2}\right)\) will correctly give the magnetic field \(\mathbf{B}\) of this current at all points inside the wire. What is the value of the constant, \(A_{0}\) ?

Field at the center of a disk * A disk with radius \(R\) and surface charge density \(\sigma\) spins with angular frequency \(\omega\). What is the magnetic field at the center?

E and B for a point charge ** (a) Use the Lorentz transformations to show that the \(\mathbf{E}\) and \(\mathbf{B}\) fields due to a point charge moving with constant velocity \(\mathbf{v}\) are related by \(\mathbf{B}=\left(\mathbf{v} / c^{2}\right) \times \mathbf{E}\) (b) If \(v \ll c\), then \(\mathbf{E}\) is essentially obtained from Coulomb's law, and \(\mathbf{B}\) can be calculated from the Biot-Savart law. Calculate \(\mathbf{B}\) this way, and then verify that it satisfies \(\mathbf{B}=\left(\mathbf{v} / c^{2}\right) \times\) E. (It may be helpful to think of the point charge as a tiny rod of charge, in order to get a handle on the \(d l\) in the BiotSavart law.)

A rotating solid cylinder ** (a) A very long cylinder with radius \(R\) and uniform volume charge density \(\rho\) spins with frequency \(\omega\) around its axis. What is the magnetic field at a point on the axis? (b) How would your answer change if all the charge were concentrated on the surface?

Proton beam \(* *\) A high-energy accelerator produces a beam of protons with kinetic energy \(2 \mathrm{GeV}\) (that is, \(2 \cdot 10^{9} \mathrm{eV}\) per proton). You may assume that the rest energy of a proton is \(1 \mathrm{GeV}\). The current is 1 milliamp, and the beam diameter is \(2 \mathrm{~mm}\). As measured in the laboratory frame: (a) what is the strength of the electric field caused by the beam \(1 \mathrm{~cm}\) from the central axis of the beam? (b) What is the strength of the magnetic field at the same distance? (c) Now consider a frame \(F^{\prime}\) that is moving along with the protons. What fields would be measured in \(F^{\prime}\) ?

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