91影视

The wavelength of a waveform signal conveyed in space or down a wire is the distance between identical points (adjacent crests) in adjacent cycles.

The distance between the two slits is $\mathrm{d}=400鈥�\mathrm{nm}\left(\frac{{10}^{鈥�9}\mathrm{m}}{1\mathrm{nm}}\right)=4.00脳{10}^{鈥�7}鈥�\mathrm{m}$

The wavelength of the light is $\mathrm{位}=700鈥�\mathrm{nm}\left(\frac{{10}^{鈥�9}\mathrm{m}}{1\mathrm{nm}}\right)=7.00脳{10}^{鈥�7}鈥�\mathrm{m}$

The equation for the constructive interference can be given as

$\mathbf{诲蝉颈苍胃}\mathbf{=}\mathbf{尘位}$鈥︹赌︹赌︹赌︹赌︹赌︹赌�..(1)

Solve equation (1) for $\mathrm{胃}$ and substitute the value of m=1 and $\mathrm{位}$, we get

$$\begin{gathered} \mathrm{胃}={\sin }^{鈥�1}\left(\frac{\mathrm{尘位}}{\mathrm{d}}\right) \\ ={\sin }^{鈥�1}\left(\frac{1脳7.00脳{10}^{鈥�7}\mathrm{m}}{4.00脳{10}^{鈥�7}\mathrm{m}}\right) \\ ={\sin }^{鈥�1}\left(1.75\right) \end{gathered}$$

There is no way to solve it since the sine function can have values in the range of

$\left[0_1卤1\right]$

Therefore, the value of $\mathrm{胃蝉颈苍}$ cannot exceed $1$.

It gives no reasonable solution for$\mathrm{胃}$between zero and $90.0掳$, implying that no formed fringes can exist.

Therefore, it produces no viable solution for $\mathrm{胃}$between zero and $90.0掳$, implying there will be no spectrum.

The $\mathrm{d}$must be greater than or equal to$\mathrm{位}$in order to produce fringes.

Therefore,$\mathrm{d}$must be bigger than or equal to $\mathrm{位}$in order to produce fringes.