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Chapter 27: Q15PE (page 997)

What is the smallest separation between two slits that will produce a second-order maximum for 720-nm red light?

Short Answer

Expert verified

The smallest separation between two slits that produces a second-order maximum is obtained as 1.44脳10-6m.

Step by step solution

01

Given data

The wavelength of the light is位=720nm10-9m1nm=7.20脳10-7m

The order of the maximum is 2.

02

Evaluating the smallest separation

A formula for the angle of the second-order maximum can be expressed as,

诲蝉颈苍胃=2位.................................(1)

We are then supposed to solve for the smallest value of d using the fact the smallest value of d corresponds to胃=900.

Substituting the given data in equation (1), we get,

d=2位蝉颈苍胃=2脳7.20脳10-7msin900=1.44脳10-6m

Therefore, the smallest separation is1.44脳10-6m.

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