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Chapter 31: Q28PE (page 1150)

伪decay producing 208Pb. The parent nuclide is in the decay series produced by 232Th, the only naturally occurring isotope of thorium.

Short Answer

Expert verified

The 伪 decay equation of 208Pb is 鈥� \[_{84}^{212}P{o_{128}} \to _{82}^{208}\;P{b_{126}} + _2^4H{e_2}\].

Step by step solution

01

Concept Introduction

The process of nuclear decay in which the parent nucleus emits an alpha particle is known as alpha decay. Two protons and two neutrons make up the alpha particle, which is structurally comparable to the nucleus of a helium atom and is symbolised by the Greek letter 伪.

02

Finding α decay equation

As it is known the equation for 伪 decay is 鈥�

\[_Z^A{X_{A - Z}} \to _{z - 2}^{A - 4}{Y_{A - Z - 2}} + _2^4H{e_2}\]

Where, ve is the electron's neutrino.

Also, it is known that A = Z + N.

Since, A = 208 and Z = 84.

So, the equation in this case is 鈥�

\[_{84}^{212}P{o_{128}} \to _{82}^{208}\;P{b_{126}} + _2^4H{e_2}\]

Therefore, the decay equation is \[_{84}^{212}P{o_{128}} \to _{82}^{208}\;P{b_{126}} + _2^4H{e_2}\].

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Most popular questions from this chapter

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Suppose the range for5.0 MeV伪 ray is known to be2.0mmin a certain material. Does this mean that every5.0 MeV伪 a ray that strikes this material travels 2.0mm , or does the range have an average value with some statistical fluctuations in the distances traveled? Explain.

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