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Chapter 31: Q20 PE (page 1149)

\({{\rm{\beta }}^{\rm{ + }}}\)decay of \(^{{\rm{52}}}{\rm{Fe}}\)

Short Answer

Expert verified

The \({\beta ^ - }\) Decay equation of \(^{52}Fe\)is \(_{26}^{52}F{e_{26}} \to _{25}^{52}M{n_{27}} + {\beta ^ + } + {\nu _e}\).

Step by step solution

01

What is atomic mass number ?

The amount of matter contained in an atom of an element is called its atomic mass.

02

 Formula to be used

\(A = N + Z\)

Where A is atomic mass number

Z is the number of protons in a nucleus

X is the symbol for the element

In the expression below:

\(_Z^A{X_N}\)

Z is the number of protons in a nucleus

X is the symbol for the element

03

To determine the  decay equation of \(^{{\rm{52}}}{\rm{Fe}}\)

We know that

\(A = N + Z\)

Where A is atomic mass number

The atomic mass of \(_{26}^{52}{\rm{F}}{{\rm{e}}_{26}}\) is 52 and

\(\begin{align}A &= 52\\Z &= 26\\N &= 26\end{align}\)

Thus,

\(\begin{align}A &= 52\\N &= 26 + 1\\ &= 27\\Z &= A - N\\ &= 52 - 27\\ &= 25\end{align}\)

Therefore, \({\beta ^ - }\) Decay equation of \(^{52}Fe\)is \(_{26}^{52}F{e_{26}} \to _{25}^{52}M{n_{27}} + {\beta ^ + } + {\nu _e}\).

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Most popular questions from this chapter

  1. The \(^{{\rm{210}}}\) Po source used in a physics laboratory is labelled as having an activity of \(1.0\,{\rm{\mu Ci}}\) on the date it was prepared. A student measures the radioactivity of this source with a Geiger counter and observes 1500 counts per minute. She notices that the source was prepared 120 days before her lab. What fraction of the decays is she observing with her apparatus?
  2. Identify some of the reasons that only a fraction of the 伪s emitted are observed by the detector.

: 尾decay producing137Ba. The parent nuclide is a major waste product of reactors and has chemistry similar to potassium and sodium, resulting in its concentration in your cells if ingested.

The ceramic glaze on a red-orange Fiesta ware plate is \({{\rm{U}}_{\rm{2}}}{{\rm{O}}_{\rm{3}}}\)and contains \({\rm{50}}{\rm{.0}}\)grams of \(^{{\rm{238}}}{\rm{U}}\), but very little \(^{{\rm{235}}}{\rm{U}}\). (a)

  1. What is the activity of the plate?
  2. Calculate the total energy that will be released by the \(^{{\rm{238}}}{\rm{U}}\)decay.
  3. If energy is worth \({\rm{12}}{\rm{.0}}\)cents per\({\rm{kW \times h}}\), what is the monetary value of the energy emitted? (These plates went out of production some 30 years ago, but are still available as collectibles.)

Verify that a\(2.3 \times {10^{17}}\,{\rm{km}}\)mass of water at normal density would make a cube\(60\,{\rm{km}}\)on a side, as claimed in Example\({\rm{31}}{\rm{.1}}\). (This mass at nuclear density would make a cube\(1.0\,{\rm{m}}\)on a side.)

If a \(1.50\,{\rm{cm}}\)-thick piece of lead can absorb \({\rm{90}}{\rm{.0 \% }}\) of the \({\rm{\gamma }}\) rays from a radioactive source, how many centimeters of lead are needed to absorb all but \({\rm{0}}{\rm{.100 \% }}\) of the \({\rm{\gamma }}\) rays?
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