91影视

The charge on the aluminum rod is

The magnetic field strength of the permanent magnet is $\mathbf{B}\mathbf{=}\mathbf{1}\mathbf{.}\mathbf{50}\mathbf{}\mathbf{T}$

The speed of the aluminum rod is $\mathbf{v}\mathbf{=}\mathbf{5}\mathbf{.}\mathbf{00}\mathbf{m}\mathbf{/}\mathbf{s}$

To determine the force exerted on a charged rod in a magnetic field, we will use the following equation,

$\mathbf{F}\mathbf{=}\mathbf{qvBsin}\mathbf{\left(}\mathbf{胃}\mathbf{\right)}$鈥︹赌︹赌︹赌︹赌︹赌︹赌︹赌�..(1)

Where is the angle between the velocity and magnetic field direction. To get the maximum force, the direction of the velocity must be perpendicular to the magneti field, i.e., having an angle of ${\mathbf{90}}^{\mathbf{掳}}$or${\mathbf{270}}^{\mathbf{掳}}$where $\mathit{胃}$equals to 1 or -1, i.e., maximum.

The direction of the force will be perpendicular to both the velocity and the magnetic field. So, substituting the values in expression (1) will give,

$$\begin{gathered} \mathit{F}\mathbf{=}\mathit{q}\mathit{v}\mathit{B} \\ \mathbf{}\mathbf{}\mathbf{=}\left(1脳{10}^{鈥�7}C\right)\mathbf{脳}\left(5m/s\right)\mathbf{脳}\mathbf{1}\mathbf{.}\mathbf{5}\mathit{T} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{-}\mathbf{7}\mathbf{.}\mathbf{5}\mathbf{脳}{\mathbf{10}}^{\mathbf{鈥�}\mathbf{7}}\mathit{N} \end{gathered}$$

Therefore, the maximum force is $\mathbf{7}\mathbf{.}\mathbf{5}\mathbf{脳}{\mathbf{10}}^{\mathbf{鈥�}\mathbf{7}}\mathit{N}$in the direction perpendicular to both the velocity and the magnetic field.