91影视

Torque can be a force applied on the different current carrying loops/segments in a uniform magnetic field.

The torque can be estimated using the expression,

$\mathbf{蟿}\mathbf{=}\mathbf{NIABsin}\mathbf{\left(}\mathbf{胃}\mathbf{\right)}\mathbf{}$鈥︹赌︹赌︹赌︹赌︹赌�(1)

where the number of turns,$\mathbf{N}$, the current,$\mathbf{I}$, the area of the loop,$\mathbf{A}$, and the inclination angle of the loop, $\mathbf{胃}$.

The maximum torque can be obtained when$\mathrm{胃}=90掳$.

The area of the current-carrying loop is,

$$\begin{gathered} \mathrm{A}=0.18\mathrm{m}脳0.18\mathrm{m} \\ =0.03{\mathrm{m}}^2 \end{gathered}$$

This can be used in equation (1) to determine the torque, such that,

$$\begin{gathered} {\mathrm{蟺}}_{\max }=\mathrm{NIABsin}\left(90掳\right) \\ =150脳50\mathrm{A}脳0.03{\mathrm{m}}^2脳1.60\mathrm{T}脳\sin \left(90掳\right) \\ =360\mathrm{N}鈥�\mathrm{m} \end{gathered}$$

Therefore, the maximum torque is $360\mathrm{N}鈥�\mathrm{m}$.

Substitute the given data in equation (1), to determine the torque,

$$\begin{gathered} {\mathrm{蟺}}_{\max }=\mathrm{NIABsin}\left(90掳\right) \\ =150脳50\mathrm{A}脳0.03{\mathrm{m}}^2脳1.60\mathrm{T}脳\sin \left(10.9掳\right) \\ =68.1\mathrm{N}鈥�\mathrm{m} \end{gathered}$$

Hence, the value of torque is $68.1\mathrm{N}鈥�\mathrm{m}$.