91影视

The speed of the electron is $v=4.00脳{10}^{3}m/s$

The magnetic force is $F=1.40脳{10}^{鈥�16}N$

The charge on the electron is $q=1.6脳{10}^{19}C$

The magnetic field strength is $B=1.25T$

The equation that is used to determine the angle between the electron velocity and the magnetic field is:

$\mathit{胃}\mathbf{)}\mathbf{=}\mathit{q}\mathit{v}\mathit{B}\mathbf{}\mathit{s}\mathit{i}\mathit{n}\mathbf{(}$鈥︹赌︹赌︹赌︹赌�.(1)

where the value ofdetermines the strength of the magnetic force.

Substituting the given values in equation (1) we will get,

$\mathit{胃}\mathit{i}\mathit{n}\mathbf{=}\mathbf{(}\mathbf{}\mathbf{}\mathbf{)}\mathbf{}\mathbf{}\mathbf{}\frac{\mathbf{1}\mathbf{.}\mathbf{40}\mathbf{脳}{\mathbf{10}}^{\mathbf{鈥�}\mathbf{16}\mathbf{}\mathbf{}}\mathbf{N}}{\mathbf{(}\mathbf{1}\mathbf{.}\mathbf{6}\mathbf{脳}{\mathbf{10}}^{\mathbf{鈥�}\mathbf{19}}\mathbf{}\mathbf{}\mathbf{C}\mathbf{)}\mathbf{脳}\mathbf{(}\mathbf{4}\mathbf{.}\mathbf{00}\mathbf{脳}{\mathbf{10}}^{\mathbf{3}\mathbf{}\mathbf{}}\mathbf{m}\mathbf{/}\mathbf{s}\mathbf{)}\mathbf{脳}\mathbf{1}\mathbf{.}\mathbf{25}\mathbf{}\mathbf{T}}$

=0.175

This can give us the value of such that,

$$\begin{gathered} \mathit{胃}\mathbf{=}\mathit{s}\mathit{i}{\mathit{n}}^{\mathbf{1}}\mathbf{}\mathbf{(}\mathbf{0}\mathbf{.}\mathbf{175}\mathbf{)} \\ \mathbf{=}\mathbf{10}\mathbf{.}{\mathbf{1}}^{\mathbf{鈭�}} \end{gathered}$$

The other value of $胃$will also be the same as role="math" localid="1653741005917" $\mathit{胃}\mathbf{80}\mathbf{-}$ , which will give another value of angle such that,

role="math" localid="1653741026619" $\mathit{胃}\mathbf{801}\mathbf{鈥�}\mathbf{69}\mathbf{.}\mathbf{9}$

Therefore, The angle between the electron velocity and the magnetic field is obtained as,$\mathbf{10}\mathbf{.}{\mathbf{1}}^{\mathbf{鈭�}}$ or$\mathbf{169}\mathbf{.}{\mathbf{9}}^{\mathbf{鈭�}}$ .