/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q12CQ Which of the particles in Figure... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 22: Q12CQ (page 809)

Which of the particles in Figure 22.47 has the greatest mass, assuming all have identical charges and velocities?

Short Answer

Expert verified

The particles 鈥榓鈥� in the figure has the greatest mass, assuming all have identical charges and velocities.

Step by step solution

01

Definition of Magnetic force

The magnetic force is always applicable on the moving charge and can be expressed as,


Where q and v are the charge and velocity of the charged particle and B is the applied magnetic field.

02

Cause of Magnetic force

Charged particles move in a circular motion as a result of magnetic force, which is known as centripetal force, and the radius of the circular motion can be given as,

rmvqB

Where m is the mass of the charged particle.

If we keep the other parameters constant except mass, we can write that,

r鈭�m

Therefore, the particle with a higher radius will have the greatest mass, and we can see from the above figure that the particle with a higher radius is 鈥榓鈥�.

Therefore, the particel with the greatest mass is a.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Repeat Exercise 22.1 for a negative charge.

How far from the starter cable of a car, carrying 150 A, must you be to experience a field less than the Earth鈥檚5.00脳10-5T ? Assume a long straight wire carries the current. (In practice, the body of your car shields the dashboard compass.)

(a) An oxygen\({\rm{ - 16}}\) ion with a mass of \({\rm{2}}{\rm{.66 \times 1}}{{\rm{0}}^{{\rm{ - 26}}}}{\rm{ kg}}\) travels at \({\rm{5}}{\rm{.00 \times 1}}{{\rm{0}}^{\rm{6}}}{\rm{ m/s}}\) perpendicular to a \({\rm{1}}{\rm{.20 - T}}\) magnetic field, which makes it move in a circular arc with a 0.231-m radius. What positive charge is on the ion? (b) What is the ratio of this charge to the charge of an electron? (c) Discuss why the ratio found in (b) should be an integer.

Nonnuclear submarines use batteries for power when submerged.

(a) Find the magnetic field 50.0 cm from a straight wire carrying 1200 A from the batteries to the drive mechanism of a submarine.

(b) What is the field if the wires to and from the drive mechanism are side by side?

(c) Discuss the effects this could have for a compass on the submarine that is not shielded.

(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500鈥�渭颁 charge and flies due west at a speed of 660 m/s over the Earth鈥檚 south magnetic pole, where the 8.00脳10鈥�5鈥�Tmagnetic field points straight up. What are the direction and the magnitude of the magnetic force on the plane? (b) Discuss whether the value obtained in part (a) implies this is a significant or negligible effect.
See all solutions

Recommended explanations on Physics Textbooks

Circular Motion and Gravitation

Read Explanation

Work Energy and Power

Read Explanation

Physics of Motion

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Fundamentals of Physics

Read Explanation

Kinematics Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.