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A basketball referee tosses the ball straight up for the starting tip-off. At what velocity must a basketball player leave the ground to rise above the floor in an attempt to get the ball?

Short Answer

Expert verified

4.95ms

Step by step solution

01

Given Data

  • The acceleration of the player,a=-g=-9.8ms.
  • Final velocity, V= 0.
  • Distance, d=1.25m
02

Velocity of the player

If an object starts with velocity U and after a distance d velocity changes to V, the achieved acceleration is a. The equation of motion can be written as:

V2-U2=2gd

Substituting values in the above equation, we get:

02-U2=2-9.811.25U2=24.525U=24.525U=4.95ms

Hence the velocity at which the player should jump is 4.95ms.

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