/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q8CQ The decay of one type of \({\rm{... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The decay of one type of \({\rm{K}}\)-meson is cited as evidence that nature favours matter over antimatter. Since mesons are composed of a quark and an antiquark, is it surprising that they would preferentially decay to one type over another? Is this an asymmetry in nature? Is the predominance of matter over antimatter an asymmetry?

Short Answer

Expert verified

We would expect the kaon to decay into both types with equal probability, so this observation demonstrates an asymmetry in nature and contributes to efforts to explain the large asymmetry of matter's dominance over antimatter in the universe.

Step by step solution

01

Definition of mesons.

Generally, the matter is made up of matter but every matter contains constituent antimatter particle. The decay of one K-mesons preferentially creates matter over antimatter.

02

 Step 2: Finding whether mesons decay into one type over another?

Matter and antimatter should be equivalent pairs of opposing quantum numbers, just as a positive charge is neither better nor worse than a negative charge. This is why we expect a K-meson, especially a long-lived neutral kaon composed symmetrically of a quark-antiquark, to decay with equal probability into a "matter heavy" path and a "antimatter heavy" path. This was not noticed. With a higher probability, the -meson decays into the "matter heavy" path.

This was the first indication of a violation of CP symmetry. Because CP symmetry states that the physics should be the same in both C-symmetry (particle-antiparticle interchange) and P-symmetry (parity change, coordinate inversion) at the same time, its violation is important in attempts to explain the predominance.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A section of superconducting wire carries a current of\({\rm{100 A}}\)and requires\({\rm{1}}{\rm{.00 L}}\)of liquid nitrogen per hour to keep it below its critical temperature. For it to be economically advantageous to use a superconducting wire, the cost of cooling the wire must be less than the cost of energy lost to heat in the wire. Assume that the cost of liquid nitrogen is\({\rm{\$ 0}}{\rm{.30}}\)per litre, and that electric energy costs\({\rm{\$ 0}}{\rm{.10}}\)per KW·h. What is the resistance of a normal wire that costs as much in wasted electric energy as the cost of liquid nitrogen for the superconductor?

Not only is liquid nitrogen a cheaper coolant than liquid helium, its boiling point is higher (\({\rm{77 K}}\)vs\({\rm{4}}{\rm{.2 K}}\)). How does higher temperature help lower the cost of cooling a material? Explain in terms of the rate of heat transfer being related to the temperature difference between the sample and its surroundings.

Using data from the previous problem, find the increase in rotational kinetic energy, given the core’s mass is\({\rm{1}}{\rm{.3}}\)times that of our Sun. Where does this increase in kinetic energy come from?

Consider a star moving in a circular orbit at the edge of a galaxy. Construct a problem in which you calculate the mass of that galaxy in kg and in multiples of the solar mass based on the velocity of the star and its distance from the center of the galaxy.

Is the event horizon of a black hole the actual physical surface of the object?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.