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(a) What current flows when a\(60.0{\rm{ }}Hz,{\rm{ }}480{\rm{ }}V\)AC source is connected to a 0\(0.250{\rm{ }}\mu F\)capacitor? (b) What would the current be at\(25.0{\rm{ }}kHz\)?

Short Answer

Expert verified

(a.) The current is obtained as: \(45.2{\rm{ }}mA\).

(b.) The current is obtained as: \(18.9{\rm{ }}A\).

Step by step solution

01

Define Electromagnetic Induction

Magnetic or electromagnetic induction is the process of producing an electromotive force across an electrical conductor in a shifting magnetic field. Michael Faraday discovered induction in\({\rm{1831}}\), which James Clerk Maxwell formally defined as Faraday's law of induction.

02

Evaluating the formula

The reactance of the capacitor is evaluated using the formula:

\({X_C}{\rm{ }} = {\rm{ }}2\pi fC\)

Knowing the reactance, we then can simply apply the Ohm's law to evaluate the intensity as:

\(\begin{aligned} I{\rm{ }} &= {\rm{ }}\frac{U}{{{X_C}}}\\ &= {\rm{ }}2\pi UCf\end{aligned}\)

03

Evaluating the current for part a

(a.) The numerical value in the first case, when the frequency is \({\rm{60 Hz}}\) will be:

\(\begin{aligned} I{\rm{ }} &= {\rm{ }}2\pi {\rm{ }} \times {\rm{ }}480{\rm{ }} \times {\rm{ }}2.5{\rm{ }} \times {\rm{ }}{10^{ - 7}}{\rm{ }} \times {\rm{ }}60\\ &= {\rm{ }}45.2{\rm{ }}mA\end{aligned}\)

Therefore, the current is: \(45.2{\rm{ }}mA\).

04

Evaluating the current for part b

(b.) The numerical value in the second case, when frequency is \({\rm{25 kHz}}\) will be:

\(\begin{aligned} I{\rm{ }} &= {\rm{ }}2\pi {\rm{ }} \times {\rm{ }}480{\rm{ }} \times {\rm{ }}2.5{\rm{ }} \times {\rm{ }}{10^{ - 7}}{\rm{ }} \times {\rm{ }}2.5{\rm{ }} \times {\rm{ }}{10^3}\\ &= {\rm{ }}18.9{\rm{ }}A\end{aligned}\)

Therefore, the current is: \(18.9{\rm{ }}A\).

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