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The motor in a toy car is powered by four batteries in series, which produce a total emf of \(6.00V\). The motor draws \(3.00A\) and develops a \(4.50V\) back emf at normal speed. Each battery has a \(0.100\Omega \) internal resistance. What is the resistance of the motor?

Short Answer

Expert verified

The resistance of the motor is obtained as \(0.1\Omega \).

Step by step solution

01

Definition of current and resistance 

Current is the term used to describe the speed at which charge moves. Resistance is the propensity of a substance to oppose the flow of charge.

02

Given information and Formula to be used

\(\begin{array}{c}{I_{back{\rm{ }}}} = 3A\\V = 6V{\rm{ }}\\Back{\rm{ }}emf{\rm{ }} = 4.50\;V\\{r_{{\mathop{\rm int}} {\rm{ }}}} = 0.1\Omega \end{array}\)

The current in a circuit,

\(I = \frac{V}{R},\)

where\(V\)is the potential and\(R\)is the resistance.

03

Calculate the resistance of the motor  

First we need find the resistance value,

\(\begin{array}{c}{I_{back{\rm{ }}}} = \frac{{V - {\rm{ }}Back{\rm{ }}emf{\rm{ }}}}{R}\\3 = \frac{{6 - 4.5}}{R}\\R = 0.5\Omega \end{array}\)

The total resistance is\(0.5\Omega \), which is equal to the effective resistance of four batteries and a motor connected in series.

Now we have,

\(\begin{array}{c}{R_{eff{\rm{ }}}} = 4{r_{{\mathop{\rm int}} {\rm{ }}}} + {R_{motor{\rm{ }}}}\\0.5 = 4 \times 0.1 + {R_{motor{\rm{ }}}}\\{R_{motor{\rm{ }}}} = 0.1\Omega \end{array}\)

Therefore, resistance value is \(0.1\Omega \).

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