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Find the currents flowing in the circuit in Figure 21.47.

Short Answer

Expert verified

The currents flowing in the circuit

I1=0.38AI2=-0.81AI3=1.2A

Step by step solution

01

Concept Introduction

Currentis a flow of electrical charge carriers, usually electrons or electron-deficient atoms. The common symbol for current is the uppercase letter I.

02

Explanation

Apply the Kirchhoff's law:

I1I2I3=018.0V+0.5I1+20I1+6I3+3.0V+0.25I3+15I1=03.0V6I3+8I212.0V+0.5I2+0.75I2+24.0V0.25I3=0

Therefore, by solving those equations, we get:

I1=0.38AI2=-0.81AI3=1.2A

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