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\(\bullet\) Neutron stars are the remains of exploded stars, and they rotate at very high rates of speed. Suppose a certain neutron star has a radius of 10.0 \(\mathrm{km}\) and rotates with a period of 1.80 \(\mathrm{ms}\) . (a) Calculate the surface rotational speed at the equator of the star as a fraction of \(c .\) (b) Assuming the star's surface is an iner- tial frame of reference (which it isn't, because of its rotation), use the Lorentz velocity transformation to calculate the speed of a point on the equator with respect to a point directly oppo- site it on the star's surface.

Short Answer

Expert verified
(a) 11.6% of the speed of light. (b) 23.2% of the speed of light.

Step by step solution

01

Understanding the Problem

We need to find the surface rotational speed of a neutron star and calculate it as a fraction of the speed of light, represented by \(c\). Then, we will use the Lorentz velocity transformation to find the speed of a point on the equator with respect to a point directly opposite it. The given data includes: the radius \(r = 10.0\ km = 10,000\ m\) and the rotational period \(T = 1.80\ ms = 1.80 \times 10^{-3}\ s\).
02

Calculate the Surface Rotational Speed

The rotational speed \(v\) can be found using the formula \(v = \frac{2\pi r}{T}\). Substituting the values, we have \(v = \frac{2\pi \times 10,000}{1.80 \times 10^{-3}}\). Calculating this gives \(v = 34,906,585.04\ m/s\).
03

Express Rotational Speed as a Fraction of c

The speed of light \(c\) is approximately \(3 \times 10^8\ m/s\). To express \(v\) as a fraction of \(c\), we divide \(v\) by \(c\): \(\frac{34,906,585.04}{3 \times 10^8} \approx 0.116\).
04

Lorentz Velocity Transformation

The velocity of a point on the equator with respect to a point directly opposite is simply double the surface speed because each point moves in opposite directions. Therefore, the relative velocity is \(2v\). However, using the Lorentz transformation, we find the relative velocity \(v'\): \[ v' = \frac{2v}{1 + \frac{v^2}{c^2}} = \frac{2 \times 34,906,585.04}{1 + \left(\frac{34,906,585.04}{3 \times 10^8}\right)^2} \approx 0.232c. \]
05

Interpretation of Results

The rotational speed at the equator is 11.6% the speed of light. The speed of a point on the equator with respect to the opposite point on the star's surface is approximately 23.2% the speed of light.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Speed
In astrophysics, rotational speed is a critical concept when dealing with objects like neutron stars. These dense remnants of supernova explosions rotate extremely fast due to their compact size and the conservation of angular momentum. To understand this, imagine an ice skater spinning faster when they pull their arms close to their body. It's the same principle: as the massive core of a star collapses into a neutron star, it retains much of its original angular momentum but dramatically decreases in size, thus speeding up its rotation.
The rotational speed of an object can be calculated using the formula:
  • \( v = \frac{2\pi r}{T} \)
where \( v \) is the rotational speed, \( r \) is the radius of the object, and \( T \) is the period of rotation. For example, if a neutron star has a radius of 10 kilometers and completes one rotation every 1.80 milliseconds, these values can be plugged into the formula to find the the speed at which a point on the equator is moving. This speed is fundamental for further calculations, especially when comparing it to the speed of light.
Lorentz Velocity Transformation
The Lorentz velocity transformation comes into play when dealing with high velocities that are comparable to the speed of light. It is part of Einstein's theory of relativity, which addresses how measurements of time and space are influenced by movement at high speeds. This is essential when dealing with objects like neutron stars, whose surface may be moving at significant fractions of the speed of light.
When calculating how the speed of a point on the equator relates to a point directly opposite it on the neutron star's surface, we need the Lorentz velocity transformation:
  • \( v' = \frac{2v}{1 + \frac{v^2}{c^2}} \)
where \( v' \) is the transformed velocity, \( v \) is the original velocity, and \( c \) is the speed of light. This formula adjusts the simple sum of velocities to account for relativistic effects, ensuring the calculated velocities don't exceed the speed of light. As such, it reveals the relative motion between two points on the neutron star, measuring in fractions of the speed of light.
Speed of Light Fraction
Expressing speed as a fraction of the speed of light provides a clear perspective on just how fast astronomical objects can move. The speed of light \( c \), approximately \( 3 \times 10^8 \) meters per second, is the ultimate speed limit in the universe.
For a neutron star, calculating its surface rotational speed involves dividing the measured speed by the speed of light:
  • \( \text{Fraction of } c = \frac{v}{c} \)
This fraction helps to quantify impressive velocities in terms understandable by comparing them to "light speed." For instance, if a neutron star's equatorial speed is found to be about 11.6% of \( c \), it highlights just how extreme and energetic these objects are in comparison to any ordinary matter.
These fractions help us comprehend the dynamics of neutron stars, ensuring our grasp of their physics is firmly rooted in the relativistic framework dictated by the laws of the universe. It reminds us of the extraordinary nature of these celestial objects, existing at the edge of physical limits.

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