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A futuristic spaceship flies past Pluto with a speed of 0.964 \(\mathrm{c}\) relative to the surface of the planet. When the spaceship is directly overhead at an altitude of \(1500 \mathrm{km},\) a very bright signal light on the surface of Pluto blinks on and then off. An observer on Pluto measures the signal light to be on for 80.0\(\mu\) y. What is the duration of the light pulse as measured by the pilot of the spaceship?

Short Answer

Expert verified
The duration of the light pulse as measured by the pilot is approximately 301.89 \, \mu y.

Step by step solution

01

Identify the Variables

We need to determine the duration of the light pulse as observed by the pilot of the spaceship, given the speed of the spaceship and the duration measured on Pluto. - Speed of the spaceship: \( v = 0.964c \)- Duration on Pluto (rest frame): \( t = 80.0 \, \mu y \)
02

Recall the Time Dilation Formula

The time dilation formula relates the time measured in the rest frame to the time measured in a moving frame. The formula is:\[ t' = \frac{t}{\sqrt{1 - \frac{v^2}{c^2}}} \]Where:- \( t' \) is the time interval in the moving frame (spaceship).- \( t \) is the time interval in the rest frame (Pluto).- \( v \) is the relative velocity between frames.- \( c \) is the speed of light.
03

Plug in the Values

Substitute the known values into the time dilation formula:\[ t' = \frac{80.0 \, \mu y}{\sqrt{1 - (0.964)^2}}\]Calculate the denominator using:\[ 1 - (0.964)^2 = 1 - 0.929696 = 0.070304\]
04

Calculate the Square Root

Find the square root of the denominator:\[ \sqrt{0.070304} \approx 0.265\]
05

Compute the Dilated Time

Now compute the time interval as measured in the spaceship frame:\[ t' = \frac{80.0 \, \mu y}{0.265} \approx 301.89 \, \mu y\]
06

Conclusion

The duration of the light pulse as measured by the pilot of the spaceship is approximately \( 301.89 \, \mu y \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

special relativity
Special relativity is a fundamental theory in physics formulated by Albert Einstein in 1905. It provides a framework for understanding how motion affects an observation of space and time. Special relativity is based on two key postulates:
  • The laws of physics are the same in all inertial frames of reference, meaning they do not change for observers who are moving at a constant speed relative to each other.
  • The speed of light in a vacuum is constant at approximately 299,792 kilometers per second (c), regardless of the motion of the light source or observer.
These postulates lead to some fascinating conclusions about the nature of time and space. Under special relativity, time and space are intertwined in a single entity known as spacetime. This results in effects such as time dilation, where time appears to slow down for a moving object relative to a stationary observer. Similarly, lengths contract along the direction of motion, which is known as length contraction. These effects become significant at speeds approaching the speed of light, as illustrated in our spaceship and Pluto exercise.
relativistic effects
Relativistic effects, such as time dilation and length contraction, arise due to the principles of special relativity. Time dilation is particularly interesting and often causes perplexity since it involves time appearing to run differently for observers in different frames.
To understand time dilation, picture two observers: one stationary and the other moving at a significant fraction of the speed of light. The moving observer, like our spaceship pilot, will measure that the time interval of an event (like a light pulse) is longer compared to what the stationary observer measures on Pluto. This occurs because the moving observer's clock ticks slower when observed from the stationary frame, as represented by the time dilation formula:
\[t' = \frac{t}{\sqrt{1 - \frac{v^2}{c^2}}}\]The effect grows as velocity increases, becoming substantial at velocities nearing the speed of light, bending our daily intuitions about time. Length contraction works alongside time dilation, meaning objects contract in the direction of motion for a stationary observer. These effects are not just thought experiments but bear practical significance, especially in fields like space travel, where speeds can become incredibly high relative to Earth.
space travel
Space travel involves moving spacecraft beyond the immediate vicinity of Earth's atmosphere. In the realm of relativistic physics, as spacecraft approach significant fractions of the speed of light (like 0.964c in our exercise), the effects predicted by special relativity become pronounced.
  • Time Dilation: Astronauts aboard such fast-moving spacecraft would experience time more slowly compared to people on Earth. If a journey took ten years for astronauts, it might appear to last longer for those on Earth due to the relativistic time dilation.
  • Length Contraction: The spacecraft would also appear contracted in length along its direction of travel for an observer at rest relative to the spacecraft's path, although this would not affect the ship or its occupants directly.
These relativistic effects pose both challenges and opportunities for future space exploration. The time dilation could potentially offer a form of natural 'time travel' for human exploration of distant stars, as their perceived travel time could be much shorter compared to Earth's timeframe.
Understanding and harnessing these relativistic effects are crucial steps in planning long-duration space missions and designing the technology that will take us beyond our solar system.

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Most popular questions from this chapter

A spaceship makes the long trip from earth to the nearest star system, Alpha Centauri, at a speed of 0.955\(c .\) The star is about 4.37 light years from earth, as measured in earth's frame of reference \((1\) light year is the distance light travels in a year). (a) How many years does the trip take, according to an observer on earth? (b) How many years does the trip take according to a passenger on the spaceship? (c) How many light years distant is Alpha Centauri from earth, as measured by a passenger on the speeding spacecraft? (Note that, in the ship's frame of reference, the passengers are at rest, while the space between earth and Alpha Centauri goes rushing past at 0.955\(c .\) (d) Use your answer from part (c) along with the speed of the spacecraft to calculate another answer for part (b). Do your two answers for that part agree? Should they?

A spaceship is traveling toward earth from the space colony on Asteroid 1040 \(\mathrm{A}\) . The ship is at the halfway point of the trip, passing Mars at a speed of 0.9\(c\) relative to Mars's frame of reference. At the same instant, a passenger on the spaceship receives a radio message from her boyfriend on 1040 \(\mathrm{A}\) and another from her hairdresser on earth. According to the passenger on the ship, were these messages sent simultane- ously or at different times. If at different times, which one was sent first? Explain your reasoning.

\(\bullet\) Sketch a graph of (a) the nonrelativistic Newtonian momentum as a function of speed \(v\) and (b) the relativistic momentum as a function of \(v .\) In both cases, start from \(v=0\) and include the region where \(v \rightarrow c .\) Does either of these graphs extend beyond \(v=c ?\)

\(\cdot\) An enemy spaceship is moving toward your starfighter with a speed of \(0.400 c,\) as measured in your reference frame. The enemy ship fires a missile toward you at a speed of 0.700\(c\) relative to the enemy ship. (See Figure \(27.24 . )\) (a) What is the speed of the missile relative to you? Express your answer in terms of the speed of light. (b) If you measure the enemy ship to be \(8.00 \times 10^{6} \mathrm{km}\) away from you when the missile is fired, how much time, measured in your frame, will it take the missile to reach you?

At what speed is the momentum of a particle three times as great as the result obtained from the nonrelativistic expression \(m v ?\)

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